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// File: subset_sum_i_naive.go
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// Created Time: 2023-06-24
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// Author: Reanon (793584285@qq.com)
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package chapter_backtracking
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/* 回溯算法:子集和 I */
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func backtrackSubsetSumINaive(total, target int, state, choices *[]int, res *[][]int) {
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// 子集和等于 target 时,记录解
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if target == total {
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newState := append([]int{}, *state...)
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*res = append(*res, newState)
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return
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}
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// 遍历所有选择
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for i := 0; i < len(*choices); i++ {
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// 剪枝:若子集和超过 target ,则跳过该选择
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if total+(*choices)[i] > target {
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continue
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}
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// 尝试:做出选择,更新元素和 total
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*state = append(*state, (*choices)[i])
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// 进行下一轮选择
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backtrackSubsetSumINaive(total+(*choices)[i], target, state, choices, res)
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// 回退:撤销选择,恢复到之前的状态
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*state = (*state)[:len(*state)-1]
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}
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}
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/* 求解子集和 I(包含重复子集) */
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func subsetSumINaive(nums []int, target int) [][]int {
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state := make([]int, 0) // 状态(子集)
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total := 0 // 子集和
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res := make([][]int, 0) // 结果列表(子集列表)
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backtrackSubsetSumINaive(total, target, &state, &nums, &res)
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return res
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}
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