|
|
|
/**
|
|
|
|
* File: build_tree.kt
|
|
|
|
* Created Time: 2024-01-25
|
|
|
|
* Author: curtishd (1023632660@qq.com)
|
|
|
|
*/
|
|
|
|
|
|
|
|
package chapter_divide_and_conquer.build_tree
|
|
|
|
|
|
|
|
import utils.TreeNode
|
|
|
|
import utils.printTree
|
|
|
|
|
|
|
|
/* 构建二叉树:分治 */
|
|
|
|
fun dfs(
|
|
|
|
preorder: IntArray,
|
|
|
|
inorderMap: Map<Int?, Int?>,
|
|
|
|
i: Int,
|
|
|
|
l: Int,
|
|
|
|
r: Int
|
|
|
|
): TreeNode? {
|
|
|
|
// 子树区间为空时终止
|
|
|
|
if (r - l < 0) return null
|
|
|
|
// 初始化根节点
|
|
|
|
val root = TreeNode(preorder[i])
|
|
|
|
// 查询 m ,从而划分左右子树
|
|
|
|
val m = inorderMap[preorder[i]]!!
|
|
|
|
// 子问题:构建左子树
|
|
|
|
root.left = dfs(preorder, inorderMap, i + 1, l, m - 1)
|
|
|
|
// 子问题:构建右子树
|
|
|
|
root.right = dfs(preorder, inorderMap, i + 1 + m - l, m + 1, r)
|
|
|
|
// 返回根节点
|
|
|
|
return root
|
|
|
|
}
|
|
|
|
|
|
|
|
/* 构建二叉树 */
|
|
|
|
fun buildTree(preorder: IntArray, inorder: IntArray): TreeNode? {
|
|
|
|
// 初始化哈希表,存储 inorder 元素到索引的映射
|
|
|
|
val inorderMap = HashMap<Int?, Int?>()
|
|
|
|
for (i in inorder.indices) {
|
|
|
|
inorderMap[inorder[i]] = i
|
|
|
|
}
|
|
|
|
val root = dfs(preorder, inorderMap, 0, 0, inorder.size - 1)
|
|
|
|
return root
|
|
|
|
}
|
|
|
|
|
|
|
|
/* Driver Code */
|
|
|
|
fun main() {
|
|
|
|
val preorder = intArrayOf(3, 9, 2, 1, 7)
|
|
|
|
val inorder = intArrayOf(9, 3, 1, 2, 7)
|
|
|
|
println("前序遍历 = ${preorder.contentToString()}")
|
|
|
|
println("中序遍历 = ${inorder.contentToString()}")
|
|
|
|
|
|
|
|
val root = buildTree(preorder, inorder)
|
|
|
|
println("构建的二叉树为:")
|
|
|
|
printTree(root)
|
|
|
|
}
|