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/**
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* File: subset_sum_i_naive.js
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* Created Time: 2023-07-30
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* Author: yuan0221 (yl1452491917@gmail.com)
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*/
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/* 回溯演算法:子集和 I */
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function backtrack(state, target, total, choices, res) {
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// 子集和等於 target 時,記錄解
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if (total === target) {
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res.push([...state]);
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return;
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}
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// 走訪所有選擇
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for (let i = 0; i < choices.length; i++) {
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// 剪枝:若子集和超過 target ,則跳過該選擇
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if (total + choices[i] > target) {
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continue;
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}
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// 嘗試:做出選擇,更新元素和 total
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state.push(choices[i]);
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// 進行下一輪選擇
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backtrack(state, target, total + choices[i], choices, res);
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// 回退:撤銷選擇,恢復到之前的狀態
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state.pop();
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}
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}
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/* 求解子集和 I(包含重複子集) */
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function subsetSumINaive(nums, target) {
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const state = []; // 狀態(子集)
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const total = 0; // 子集和
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const res = []; // 結果串列(子集串列)
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backtrack(state, target, total, nums, res);
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return res;
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}
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/* Driver Code */
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const nums = [3, 4, 5];
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const target = 9;
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const res = subsetSumINaive(nums, target);
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console.log(`輸入陣列 nums = ${JSON.stringify(nums)}, target = ${target}`);
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console.log(`所有和等於 ${target} 的子集 res = ${JSON.stringify(res)}`);
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console.log('請注意,該方法輸出的結果包含重複集合');
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