|
|
|
// File: time_complexity_test.go
|
|
|
|
// Created Time: 2022-12-13
|
|
|
|
// Author: msk397 (machangxinq@gmail.com)
|
|
|
|
|
|
|
|
package chapter_computational_complexity
|
|
|
|
|
|
|
|
import (
|
|
|
|
"fmt"
|
|
|
|
"testing"
|
|
|
|
)
|
|
|
|
|
|
|
|
func TestTimeComplexity(t *testing.T) {
|
|
|
|
n := 8
|
|
|
|
fmt.Println("输入数据大小 n =", n)
|
|
|
|
|
|
|
|
count := constant(n)
|
|
|
|
fmt.Println("常数阶的计算操作数量 =", count)
|
|
|
|
|
|
|
|
count = linear(n)
|
|
|
|
fmt.Println("线性阶的计算操作数量 =", count)
|
|
|
|
count = arrayTraversal(make([]int, n))
|
|
|
|
fmt.Println("线性阶(遍历数组)的计算操作数量 =", count)
|
|
|
|
|
|
|
|
count = quadratic(n)
|
|
|
|
fmt.Println("平方阶的计算操作数量 =", count)
|
|
|
|
nums := make([]int, n)
|
|
|
|
for i := 0; i < n; i++ {
|
|
|
|
nums[i] = n - i
|
|
|
|
}
|
|
|
|
count = bubbleSort(nums)
|
|
|
|
fmt.Println("平方阶(冒泡排序)的计算操作数量 =", count)
|
|
|
|
|
|
|
|
count = exponential(n)
|
|
|
|
fmt.Println("指数阶(循环实现)的计算操作数量 =", count)
|
|
|
|
count = expRecur(n)
|
|
|
|
fmt.Println("指数阶(递归实现)的计算操作数量 =", count)
|
|
|
|
|
|
|
|
count = logarithmic(float64(n))
|
|
|
|
fmt.Println("对数阶(循环实现)的计算操作数量 =", count)
|
|
|
|
count = logRecur(float64(n))
|
|
|
|
fmt.Println("对数阶(递归实现)的计算操作数量 =", count)
|
|
|
|
|
|
|
|
count = linearLogRecur(float64(n))
|
|
|
|
fmt.Println("线性对数阶(递归实现)的计算操作数量 =", count)
|
|
|
|
|
|
|
|
count = factorialRecur(n)
|
|
|
|
fmt.Println("阶乘阶(递归实现)的计算操作数量 =", count)
|
|
|
|
}
|