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65 lines
2.0 KiB
65 lines
2.0 KiB
8 months ago
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/**
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* File: binary_search_insertion.kt
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* Created Time: 2024-1-25
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* Author: curtishd (1023632660@qq.com)
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*/
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package chapter_searching
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/* 二分查找插入点(无重复元素) */
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fun binarySearchInsertionSimple(nums: IntArray, target: Int): Int {
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var i = 0
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var j = nums.size - 1 // 初始化双闭区间 [0, n-1]
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while (i <= j) {
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val m = i + (j - i) / 2 // 计算中点索引 m
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if (nums[m] < target) {
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i = m + 1 // target 在区间 [m+1, j] 中
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} else if (nums[m] > target) {
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j = m - 1 // target 在区间 [i, m-1] 中
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} else {
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return m // 找到 target ,返回插入点 m
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}
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}
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// 未找到 target ,返回插入点 i
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return i
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}
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/* 二分查找插入点(存在重复元素) */
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fun binarySearchInsertion(nums: IntArray, target: Int): Int {
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var i = 0
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var j = nums.size - 1 // 初始化双闭区间 [0, n-1]
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while (i <= j) {
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val m = i + (j - i) / 2 // 计算中点索引 m
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if (nums[m] < target) {
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i = m + 1 // target 在区间 [m+1, j] 中
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} else if (nums[m] > target) {
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j = m - 1 // target 在区间 [i, m-1] 中
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} else {
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j = m - 1 // 首个小于 target 的元素在区间 [i, m-1] 中
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}
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}
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// 返回插入点 i
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return i
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}
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/* Driver Code */
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fun main() {
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// 无重复元素的数组
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var nums = intArrayOf(1, 3, 6, 8, 12, 15, 23, 26, 31, 35)
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println("\n数组 nums = ${nums.contentToString()}")
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// 二分查找插入点
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for (target in intArrayOf(6, 9)) {
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val index = binarySearchInsertionSimple(nums, target)
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println("元素 $target 的插入点的索引为 $index")
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}
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// 包含重复元素的数组
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nums = intArrayOf(1, 3, 6, 6, 6, 6, 6, 10, 12, 15)
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println("\n数组 nums = ${nums.contentToString()}")
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// 二分查找插入点
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for (target in intArrayOf(2, 6, 20)) {
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val index = binarySearchInsertion(nums, target)
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println("元素 $target 的插入点的索引为 $index")
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}
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}
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