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=begin
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File: subset_sum_i_naive.rb
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Created Time: 2024-05-22
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Author: Xuan Khoa Tu Nguyen (ngxktuzkai2000@gmail.com)
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=end
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### 回溯算法:子集和 I ###
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def backtrack(state, target, total, choices, res)
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# 子集和等于 target 时,记录解
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if total == target
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res << state.dup
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return
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end
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# 遍历所有选择
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for i in 0...choices.length
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# 剪枝:若子集和超过 target ,则跳过该选择
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next if total + choices[i] > target
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# 尝试:做出选择,更新元素和 total
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state << choices[i]
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# 进行下一轮选择
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backtrack(state, target, total + choices[i], choices, res)
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# 回退:撤销选择,恢复到之前的状态
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state.pop
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end
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end
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### 求解子集和 I(包含重复子集)###
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def subset_sum_i_naive(nums, target)
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state = [] # 状态(子集)
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total = 0 # 子集和
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res = [] # 结果列表(子集列表)
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backtrack(state, target, total, nums, res)
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res
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end
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### Driver Code ###
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if __FILE__ == $0
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nums = [3, 4, 5]
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target = 9
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res = subset_sum_i_naive(nums, target)
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puts "输入数组 nums = #{nums}, target = #{target}"
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puts "所有和等于 #{target} 的子集 res = #{res}"
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puts "请注意,该方法输出的结果包含重复集合"
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end
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