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/**
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* File: two_sum.swift
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* Created Time: 2023-01-03
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* Author: nuomi1 (nuomi1@qq.com)
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*/
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/* 方法一:暴力枚举 */
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func twoSumBruteForce(nums: [Int], target: Int) -> [Int] {
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// 两层循环,时间复杂度为 O(n^2)
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for i in nums.indices.dropLast() {
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for j in nums.indices.dropFirst(i + 1) {
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if nums[i] + nums[j] == target {
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return [i, j]
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}
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}
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}
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return [0]
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}
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/* 方法二:辅助哈希表 */
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func twoSumHashTable(nums: [Int], target: Int) -> [Int] {
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// 辅助哈希表,空间复杂度为 O(n)
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var dic: [Int: Int] = [:]
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// 单层循环,时间复杂度为 O(n)
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for i in nums.indices {
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if let j = dic[target - nums[i]] {
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return [j, i]
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}
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dic[nums[i]] = i
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}
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return [0]
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}
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@main
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enum LeetcodeTwoSum {
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/* Driver Code */
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static func main() {
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// ======= Test Case =======
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let nums = [2, 7, 11, 15]
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let target = 13
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// ====== Driver Code ======
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// 方法一
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var res = twoSumBruteForce(nums: nums, target: target)
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print("方法一 res = \(res)")
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// 方法二
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res = twoSumHashTable(nums: nums, target: target)
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print("方法二 res = \(res)")
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}
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}
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