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126 lines
4.4 KiB
126 lines
4.4 KiB
6 months ago
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/**
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* File: min_path_sum.java
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* Created Time: 2023-07-10
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* Author: krahets (krahets@163.com)
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*/
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package chapter_dynamic_programming;
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import java.util.Arrays;
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public class min_path_sum {
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/* Minimum path sum: Brute force search */
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static int minPathSumDFS(int[][] grid, int i, int j) {
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// If it's the top-left cell, terminate the search
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if (i == 0 && j == 0) {
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return grid[0][0];
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}
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// If the row or column index is out of bounds, return a +∞ cost
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if (i < 0 || j < 0) {
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return Integer.MAX_VALUE;
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}
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// Calculate the minimum path cost from the top-left to (i-1, j) and (i, j-1)
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int up = minPathSumDFS(grid, i - 1, j);
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int left = minPathSumDFS(grid, i, j - 1);
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// Return the minimum path cost from the top-left to (i, j)
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return Math.min(left, up) + grid[i][j];
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}
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/* Minimum path sum: Memoized search */
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static int minPathSumDFSMem(int[][] grid, int[][] mem, int i, int j) {
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// If it's the top-left cell, terminate the search
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if (i == 0 && j == 0) {
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return grid[0][0];
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}
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// If the row or column index is out of bounds, return a +∞ cost
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if (i < 0 || j < 0) {
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return Integer.MAX_VALUE;
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}
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// If there is a record, return it
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if (mem[i][j] != -1) {
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return mem[i][j];
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}
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// The minimum path cost from the left and top cells
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int up = minPathSumDFSMem(grid, mem, i - 1, j);
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int left = minPathSumDFSMem(grid, mem, i, j - 1);
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// Record and return the minimum path cost from the top-left to (i, j)
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mem[i][j] = Math.min(left, up) + grid[i][j];
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return mem[i][j];
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}
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/* Minimum path sum: Dynamic programming */
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static int minPathSumDP(int[][] grid) {
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int n = grid.length, m = grid[0].length;
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// Initialize dp table
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int[][] dp = new int[n][m];
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dp[0][0] = grid[0][0];
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// State transition: first row
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for (int j = 1; j < m; j++) {
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dp[0][j] = dp[0][j - 1] + grid[0][j];
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}
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// State transition: first column
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for (int i = 1; i < n; i++) {
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dp[i][0] = dp[i - 1][0] + grid[i][0];
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}
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// State transition: the rest of the rows and columns
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for (int i = 1; i < n; i++) {
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for (int j = 1; j < m; j++) {
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dp[i][j] = Math.min(dp[i][j - 1], dp[i - 1][j]) + grid[i][j];
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}
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}
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return dp[n - 1][m - 1];
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}
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/* Minimum path sum: Space-optimized dynamic programming */
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static int minPathSumDPComp(int[][] grid) {
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int n = grid.length, m = grid[0].length;
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// Initialize dp table
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int[] dp = new int[m];
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// State transition: first row
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dp[0] = grid[0][0];
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for (int j = 1; j < m; j++) {
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dp[j] = dp[j - 1] + grid[0][j];
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}
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// State transition: the rest of the rows
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for (int i = 1; i < n; i++) {
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// State transition: first column
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dp[0] = dp[0] + grid[i][0];
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// State transition: the rest of the columns
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for (int j = 1; j < m; j++) {
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dp[j] = Math.min(dp[j - 1], dp[j]) + grid[i][j];
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}
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}
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return dp[m - 1];
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}
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public static void main(String[] args) {
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int[][] grid = {
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{ 1, 3, 1, 5 },
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{ 2, 2, 4, 2 },
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{ 5, 3, 2, 1 },
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{ 4, 3, 5, 2 }
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};
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int n = grid.length, m = grid[0].length;
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// Brute force search
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int res = minPathSumDFS(grid, n - 1, m - 1);
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System.out.println("The minimum path sum from the top left corner to the bottom right corner is " + res);
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// Memoized search
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int[][] mem = new int[n][m];
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for (int[] row : mem) {
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Arrays.fill(row, -1);
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}
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res = minPathSumDFSMem(grid, mem, n - 1, m - 1);
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System.out.println("The minimum path sum from the top left corner to the bottom right corner is " + res);
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// Dynamic programming
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res = minPathSumDP(grid);
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System.out.println("The minimum path sum from the top left corner to the bottom right corner is " + res);
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// Space-optimized dynamic programming
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res = minPathSumDPComp(grid);
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System.out.println("The minimum path sum from the top left corner to the bottom right corner is " + res);
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}
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}
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