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61 lines
1.8 KiB
61 lines
1.8 KiB
8 months ago
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/**
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* File: coin_change_greedy.cpp
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* Created Time: 2023-07-20
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* Author: krahets (krahets@163.com)
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*/
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#include "../utils/common.hpp"
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/* 零錢兌換:貪婪 */
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int coinChangeGreedy(vector<int> &coins, int amt) {
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// 假設 coins 串列有序
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int i = coins.size() - 1;
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int count = 0;
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// 迴圈進行貪婪選擇,直到無剩餘金額
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while (amt > 0) {
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// 找到小於且最接近剩餘金額的硬幣
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while (i > 0 && coins[i] > amt) {
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i--;
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}
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// 選擇 coins[i]
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amt -= coins[i];
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count++;
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}
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// 若未找到可行方案,則返回 -1
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return amt == 0 ? count : -1;
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}
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/* Driver Code */
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int main() {
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// 貪婪:能夠保證找到全域性最優解
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vector<int> coins = {1, 5, 10, 20, 50, 100};
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int amt = 186;
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int res = coinChangeGreedy(coins, amt);
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cout << "\ncoins = ";
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printVector(coins);
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cout << "amt = " << amt << endl;
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cout << "湊到 " << amt << " 所需的最少硬幣數量為 " << res << endl;
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// 貪婪:無法保證找到全域性最優解
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coins = {1, 20, 50};
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amt = 60;
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res = coinChangeGreedy(coins, amt);
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cout << "\ncoins = ";
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printVector(coins);
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cout << "amt = " << amt << endl;
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cout << "湊到 " << amt << " 所需的最少硬幣數量為 " << res << endl;
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cout << "實際上需要的最少數量為 3 ,即 20 + 20 + 20" << endl;
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// 貪婪:無法保證找到全域性最優解
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coins = {1, 49, 50};
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amt = 98;
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res = coinChangeGreedy(coins, amt);
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cout << "\ncoins = ";
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printVector(coins);
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cout << "amt = " << amt << endl;
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cout << "湊到 " << amt << " 所需的最少硬幣數量為 " << res << endl;
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cout << "實際上需要的最少數量為 2 ,即 49 + 49" << endl;
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return 0;
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}
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