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/**
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* File: leetcode_two_sum.rs
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* Created Time: 2023-01-14
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* Author: xBLACICEx (xBLACKICEx@outlook.com), sjinzh (sjinzh@gmail.com)
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*/
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use std::collections::HashMap;
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struct SolutionBruteForce;
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struct SolutionHashMap;
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/* 方法一:暴力枚举 */
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impl SolutionBruteForce {
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pub fn two_sum(nums: &Vec<i32>, target: i32) -> Vec<i32> {
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let size = nums.len();
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// 两层循环,时间复杂度 O(n^2)
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for i in 0..size - 1 {
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for j in i + 1..size {
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if nums[i] + nums[j] == target {
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return vec![i as i32, j as i32];
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}
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}
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}
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vec![]
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}
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}
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/* 方法二:辅助哈希表 */
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impl SolutionHashMap {
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pub fn two_sum(nums: &Vec<i32>, target: i32) -> Vec<i32> {
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// 辅助哈希表,空间复杂度 O(n)
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let mut dic = HashMap::new();
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// 单层循环,时间复杂度 O(n)
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for (i, num) in nums.iter().enumerate() {
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match dic.get(&(target - num)) {
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Some(v) => return vec![*v as i32, i as i32],
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None => dic.insert(num, i as i32)
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};
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}
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vec![]
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}
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}
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/* Driver Code */
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fn main() {
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// ======= Test Case =======
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let nums = vec![ 2, 7, 11, 15 ];
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let target = 9;
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// 方法一
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let res = SolutionBruteForce::two_sum(&nums, target);
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print!("方法一 res = ");
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inc::print_util::print_array(&res);
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// 方法二
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let res = SolutionHashMap::two_sum(&nums, target);
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print!("\n方法二 res = ");
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inc::print_util::print_array(&res);
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}
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