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/**
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* File: counting_sort.swift
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* Created Time: 2023-03-22
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* Author: nuomi1 (nuomi1@qq.com)
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*/
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/* 计数排序 */
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// 简单实现,无法用于排序对象
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func countingSortNaive(nums: inout [Int]) {
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// 1. 统计数组最大元素 m
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let m = nums.max()!
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// 2. 统计各数字的出现次数
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// counter[num] 代表 num 的出现次数
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var counter = Array(repeating: 0, count: m + 1)
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for num in nums {
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counter[num] += 1
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}
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// 3. 遍历 counter ,将各元素填入原数组 nums
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var i = 0
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for num in stride(from: 0, to: m + 1, by: 1) {
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for _ in stride(from: 0, to: counter[num], by: 1) {
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nums[i] = num
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i += 1
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}
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}
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}
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/* 计数排序 */
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// 完整实现,可排序对象,并且是稳定排序
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func countingSort(nums: inout [Int]) {
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// 1. 统计数组最大元素 m
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let m = nums.max()!
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// 2. 统计各数字的出现次数
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// counter[num] 代表 num 的出现次数
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var counter = Array(repeating: 0, count: m + 1)
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for num in nums {
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counter[num] += 1
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}
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// 3. 求 counter 的前缀和,将“出现次数”转换为“尾索引”
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// 即 counter[num]-1 是 num 在 res 中最后一次出现的索引
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for i in stride(from: 0, to: m, by: 1) {
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counter[i + 1] += counter[i]
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}
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// 4. 倒序遍历 nums ,将各元素填入结果数组 res
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// 初始化数组 res 用于记录结果
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var res = Array(repeating: 0, count: nums.count)
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for i in stride(from: nums.count - 1, through: 0, by: -1) {
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let num = nums[i]
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res[counter[num] - 1] = num // 将 num 放置到对应索引处
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counter[num] -= 1 // 令前缀和自减 1 ,得到下次放置 num 的索引
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}
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// 使用结果数组 res 覆盖原数组 nums
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for i in stride(from: 0, to: nums.count, by: 1) {
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nums[i] = res[i]
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}
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}
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@main
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enum CountingSort {
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/* Driver Code */
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static func main() {
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var nums = [1, 0, 1, 2, 0, 4, 0, 2, 2, 4]
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countingSortNaive(nums: &nums)
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print("计数排序(无法排序对象)完成后 nums = \(nums)")
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var nums1 = [1, 0, 1, 2, 0, 4, 0, 2, 2, 4]
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countingSort(nums: &nums1)
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print("计数排序完成后 nums1 = \(nums1)")
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}
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}
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