Add JavaScript and TypeScript code of top_k and update some code style (#686)

* Update JS and TS code style

* Add JavaScript and TypeScript code of top_k

* Update top_k.ts

* Apply suggestions from code review

Co-authored-by: Justin Tse <xiefahit@gmail.com>

* Apply suggestions from code review

Co-authored-by: Justin Tse <xiefahit@gmail.com>

---------

Co-authored-by: Yudong Jin <krahets@163.com>
pull/691/head
Justin Tse 1 year ago committed by GitHub
parent 4c75c204f3
commit 5d7e0a59b1
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@ -53,7 +53,7 @@ function traverse(nums) {
count++;
}
// 直接遍历数组
for (let num of nums) {
for (const num of nums) {
count += 1;
}
}

@ -9,7 +9,7 @@ function backtrack(choices, state, n, res) {
// 当爬到第 n 阶时,方案数量加 1
if (state === n) res.set(0, res.get(0) + 1);
// 遍历所有选择
for (choice of choices) {
for (const choice of choices) {
// 剪枝:不允许越过第 n 阶
if (state + choice > n) break;
// 尝试:做出选择,更新状态

@ -70,7 +70,7 @@ class GraphAdjList {
// 在邻接表中删除顶点 vet 对应的链表
this.adjList.delete(vet);
// 遍历其他顶点的链表,删除所有包含 vet 的边
for (let set of this.adjList.values()) {
for (const set of this.adjList.values()) {
const index = set.indexOf(vet);
if (index > -1) {
set.splice(index, 1);

@ -82,7 +82,7 @@ class HashMapChaining {
for (let i = 0; i < bucket.length; i++) {
if (bucket[i].key === key) {
bucket.splice(i, 1);
this.size--;
this.#size--;
break;
}
}

@ -115,6 +115,11 @@ class MaxHeap {
print() {
printHeap(this.#maxHeap);
}
/* 取出堆中元素 */
getMaxHeap() {
return this.#maxHeap;
}
}
/* Driver Code */
@ -145,3 +150,8 @@ console.log(`\n堆元素数量为 ${size}`);
/* 判断堆是否为空 */
let isEmpty = maxHeap.isEmpty();
console.log(`\n堆是否为空 ${isEmpty}`);
module.exports = {
MaxHeap,
};

@ -0,0 +1,34 @@
/**
* File: top_k.js
* Created Time: 2023-08-13
* Author: Justin (xiefahit@gmail.com)
*/
const { MaxHeap } = require('./my_heap');
/* 基于堆查找数组中最大的 k 个元素 */
function top_k_heap(nums, k) {
// 使用大顶堆 MaxHeap对数组 nums 取相反数
const invertedNums = nums.map(num => -num);
// 将数组的前 k 个元素入堆
const heap = new MaxHeap(invertedNums.slice(0, k));
// 从第 k+1 个元素开始,保持堆的长度为 k
for (let i = k; i < invertedNums.length; i++) {
// 若当前元素小于堆顶元素,则将堆顶元素出堆、当前元素入堆
if (invertedNums[i] < heap.peek()) {
heap.pop();
heap.push(invertedNums[i]);
}
}
// 取出堆中元素
const maxHeap = heap.getMaxHeap();
// 对堆中元素取相反数
const invertedMaxHeap = maxHeap.map(num => -num);
return invertedMaxHeap;
}
/* Driver Code */
const nums = [1, 7, 6, 3, 2];
const k = 3;
const res = top_k_heap(nums, k);
console.log(`最大的 ${k} 个元素为`, res);

@ -53,7 +53,7 @@ function traverse(nums: number[]): void {
count++;
}
// 直接遍历数组
for (let num of nums) {
for (const num of nums) {
count += 1;
}
}
@ -98,4 +98,4 @@ traverse(nums);
let index = find(nums, 3);
console.log('在 nums 中查找元素 3 ,得到索引 =', index);
export {};
export { };

@ -14,7 +14,7 @@ function backtrack(
// 当爬到第 n 阶时,方案数量加 1
if (state === n) res.set(0, res.get(0) + 1);
// 遍历所有选择
for (let choice of choices) {
for (const choice of choices) {
// 剪枝:不允许越过第 n 阶
if (state + choice > n) break;
// 尝试:做出选择,更新状态
@ -38,4 +38,4 @@ const n = 9;
const res = climbingStairsBacktrack(n);
console.log(`${n} 阶楼梯共有 ${res} 种方案`);
export {};
export { };

@ -70,7 +70,7 @@ class GraphAdjList {
// 在邻接表中删除顶点 vet 对应的链表
this.adjList.delete(vet);
// 遍历其他顶点的链表,删除所有包含 vet 的边
for (let set of this.adjList.values()) {
for (const set of this.adjList.values()) {
const index: number = set.indexOf(vet);
if (index > -1) {
set.splice(index, 1);

@ -114,6 +114,11 @@ class MaxHeap {
public print(): void {
printHeap(this.maxHeap);
}
/* 取出堆中元素 */
public getMaxHeap(): number[] {
return this.maxHeap;
}
}
/* Driver Code */
@ -144,3 +149,5 @@ console.log(`\n堆元素数量为 ${size}`);
/* 判断堆是否为空 */
const isEmpty = maxHeap.isEmpty();
console.log(`\n堆是否为空 ${isEmpty}`);
export { MaxHeap };

@ -0,0 +1,34 @@
/**
* File: top_k.ts
* Created Time: 2023-08-13
* Author: Justin (xiefahit@gmail.com)
*/
import { MaxHeap } from './my_heap';
/* 基于堆查找数组中最大的 k 个元素 */
function top_k_heap(nums: number[], k: number): number[] {
// 将堆中所有元素取反,从而用大顶堆来模拟小顶堆
const invertedNums = nums.map(num => -num);
// 将数组的前 k 个元素入堆
const heap = new MaxHeap(invertedNums.slice(0, k));
// 从第 k+1 个元素开始,保持堆的长度为 k
for (let i = k; i < invertedNums.length; i++) {
// 若当前元素小于堆顶元素,则将堆顶元素出堆、当前元素入堆
if (invertedNums[i] < heap.peek()) {
heap.pop();
heap.push(invertedNums[i]);
}
}
// 取出堆中元素
const maxHeap = heap.getMaxHeap();
// 对堆中元素取相反数
const invertedMaxHeap = maxHeap.map(num => -num);
return invertedMaxHeap;
}
/* Driver Code */
const nums = [1, 7, 6, 3, 2];
const k = 3;
const res = top_k_heap(nums, k);
console.log(`最大的 ${k} 个元素为`, res);
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