Update medianThree() in quick_sort.

pull/261/head
Yudong Jin 2 years ago
parent 3e19205c84
commit 5f0ae848c4

@ -59,7 +59,7 @@ private:
static int medianThree(vector<int>& nums, int left, int mid, int right) {
// 使用了异或操作来简化代码
// 异或规则为 0 ^ 0 = 1 ^ 1 = 0, 0 ^ 1 = 1 ^ 0 = 1
if ((nums[left] > nums[mid]) ^ (nums[left] > nums[right]))
if ((nums[left] < nums[mid]) ^ (nums[left] < nums[right]))
return left;
else if ((nums[mid] < nums[left]) ^ (nums[mid] < nums[right]))
return mid;

@ -65,7 +65,7 @@ namespace hello_algo.chapter_sorting
{
// 使用了异或操作来简化代码
// 异或规则为 0 ^ 0 = 1 ^ 1 = 0, 0 ^ 1 = 1 ^ 0 = 1
if ((nums[left] > nums[mid]) ^ (nums[left] > nums[right]))
if ((nums[left] < nums[mid]) ^ (nums[left] < nums[right]))
return left;
else if ((nums[mid] < nums[left]) ^ (nums[mid] < nums[right]))
return mid;

@ -47,9 +47,11 @@ func (q *quickSort) quickSort(nums []int, left, right int) {
/* 选取三个元素的中位数 */
func (q *quickSortMedian) medianThree(nums []int, left, mid, right int) int {
if (nums[left] > nums[mid]) != (nums[left] > nums[right]) {
// 使用了异或操作来简化代码(!= 在这里起到异或的作用)
// 异或规则为 0 ^ 0 = 1 ^ 1 = 0, 0 ^ 1 = 1 ^ 0 = 1
if (nums[left] < nums[mid]) != (nums[left] < nums[right]) {
return left
} else if (nums[mid] < nums[left]) != (nums[mid] > nums[right]) {
} else if (nums[mid] < nums[left]) != (nums[mid] < nums[right]) {
return mid
}
return right

@ -58,7 +58,7 @@ class QuickSortMedian {
static int medianThree(int[] nums, int left, int mid, int right) {
// 使用了异或操作来简化代码
// 异或规则为 0 ^ 0 = 1 ^ 1 = 0, 0 ^ 1 = 1 ^ 0 = 1
if ((nums[left] > nums[mid]) ^ (nums[left] > nums[right]))
if ((nums[left] < nums[mid]) ^ (nums[left] < nums[right]))
return left;
else if ((nums[mid] < nums[left]) ^ (nums[mid] < nums[right]))
return mid;

@ -56,7 +56,7 @@ class QuickSortMedian {
medianThree(nums, left, mid, right) {
// 使用了异或操作来简化代码
// 异或规则为 0 ^ 0 = 1 ^ 1 = 0, 0 ^ 1 = 1 ^ 0 = 1
if ((nums[left] > nums[mid]) ^ (nums[left] > nums[right])) return left;
if ((nums[left] < nums[mid]) ^ (nums[left] < nums[right])) return left;
else if ((nums[mid] < nums[left]) ^ (nums[mid] < nums[right])) return mid;
else return right;
}

@ -42,7 +42,7 @@ class QuickSortMedian:
def median_three(self, nums, left, mid, right):
# 使用了异或操作来简化代码
# 异或规则为 0 ^ 0 = 1 ^ 1 = 0, 0 ^ 1 = 1 ^ 0 = 1
if (nums[left] > nums[mid]) ^ (nums[left] > nums[right]):
if (nums[left] < nums[mid]) ^ (nums[left] < nums[right]):
return left
elif (nums[mid] < nums[left]) ^ (nums[mid] > nums[right]):
return mid

@ -58,7 +58,7 @@ class QuickSortMedian {
medianThree(nums: number[], left: number, mid: number, right: number): number {
// 使用了异或操作来简化代码
// 异或规则为 0 ^ 0 = 1 ^ 1 = 0, 0 ^ 1 = 1 ^ 0 = 1
if (Number(nums[left] > nums[mid]) ^ Number(nums[left] > nums[right])) {
if (Number(nums[left] < nums[mid]) ^ Number(nums[left] < nums[right])) {
return left;
} else if (Number(nums[mid] < nums[left]) ^ Number(nums[mid] < nums[right])) {
return mid;

@ -16,20 +16,28 @@ comments: true
=== "Step 1"
![pivot_division_step1](quick_sort.assets/pivot_division_step1.png)
=== "Step 2"
![pivot_division_step2](quick_sort.assets/pivot_division_step2.png)
=== "Step 3"
![pivot_division_step3](quick_sort.assets/pivot_division_step3.png)
=== "Step 4"
![pivot_division_step4](quick_sort.assets/pivot_division_step4.png)
=== "Step 5"
![pivot_division_step5](quick_sort.assets/pivot_division_step5.png)
=== "Step 6"
![pivot_division_step6](quick_sort.assets/pivot_division_step6.png)
=== "Step 7"
![pivot_division_step7](quick_sort.assets/pivot_division_step7.png)
=== "Step 8"
![pivot_division_step8](quick_sort.assets/pivot_division_step8.png)
=== "Step 9"
![pivot_division_step9](quick_sort.assets/pivot_division_step9.png)
@ -220,7 +228,6 @@ comments: true
swap(nums, i, left); // 将基准数交换至两子数组的分界线
return i; // 返回基准数的索引
}
```
=== "Swift"
@ -408,7 +415,7 @@ comments: true
int medianThree(int[] nums, int left, int mid, int right) {
// 使用了异或操作来简化代码
// 异或规则为 0 ^ 0 = 1 ^ 1 = 0, 0 ^ 1 = 1 ^ 0 = 1
if ((nums[left] > nums[mid]) ^ (nums[left] > nums[right]))
if ((nums[left] < nums[mid]) ^ (nums[left] < nums[right]))
return left;
else if ((nums[mid] < nums[left]) ^ (nums[mid] < nums[right]))
return mid;
@ -434,7 +441,7 @@ comments: true
int medianThree(vector<int>& nums, int left, int mid, int right) {
// 使用了异或操作来简化代码
// 异或规则为 0 ^ 0 = 1 ^ 1 = 0, 0 ^ 1 = 1 ^ 0 = 1
if ((nums[left] > nums[mid]) ^ (nums[left] > nums[right]))
if ((nums[left] < nums[mid]) ^ (nums[left] < nums[right]))
return left;
else if ((nums[mid] < nums[left]) ^ (nums[mid] < nums[right]))
return mid;
@ -460,7 +467,7 @@ comments: true
def median_three(self, nums, left, mid, right):
# 使用了异或操作来简化代码
# 异或规则为 0 ^ 0 = 1 ^ 1 = 0, 0 ^ 1 = 1 ^ 0 = 1
if (nums[left] > nums[mid]) ^ (nums[left] > nums[right]):
if (nums[left] < nums[mid]) ^ (nums[left] < nums[right]):
return left
elif (nums[mid] < nums[left]) ^ (nums[mid] > nums[right]):
return mid
@ -481,7 +488,7 @@ comments: true
```go title="quick_sort.go"
/* 选取三个元素的中位数 */
func medianThree(nums []int, left, mid, right int) int {
if (nums[left] > nums[mid]) != (nums[left] > nums[right]) {
if (nums[left] < nums[mid]) != (nums[left] < nums[right]) {
return left
} else if (nums[mid] < nums[left]) != (nums[mid] > nums[right]) {
return mid
@ -507,7 +514,7 @@ comments: true
function medianThree(nums, left, mid, right) {
// 使用了异或操作来简化代码
// 异或规则为 0 ^ 0 = 1 ^ 1 = 0, 0 ^ 1 = 1 ^ 0 = 1
if ((nums[left] > nums[mid]) ^ (nums[left] > nums[right]))
if ((nums[left] < nums[mid]) ^ (nums[left] < nums[right]))
return left;
else if ((nums[mid] < nums[left]) ^ (nums[mid] < nums[right]))
return mid;
@ -533,7 +540,7 @@ comments: true
function medianThree(nums: number[], left: number, mid: number, right: number): number {
// 使用了异或操作来简化代码
// 异或规则为 0 ^ 0 = 1 ^ 1 = 0, 0 ^ 1 = 1 ^ 0 = 1
if (Number(nums[left] > nums[mid]) ^ Number(nums[left] > nums[right])) {
if (Number(nums[left] < nums[mid]) ^ Number(nums[left] < nums[right])) {
return left;
} else if (Number(nums[mid] < nums[left]) ^ Number(nums[mid] < nums[right])) {
return mid;
@ -566,7 +573,7 @@ comments: true
{
// 使用了异或操作来简化代码
// 异或规则为 0 ^ 0 = 1 ^ 1 = 0, 0 ^ 1 = 1 ^ 0 = 1
if ((nums[left] > nums[mid]) ^ (nums[left] > nums[right]))
if ((nums[left] < nums[mid]) ^ (nums[left] < nums[right]))
return left;
else if ((nums[mid] < nums[left]) ^ (nums[mid] < nums[right]))
return mid;

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