deploy

chapter_appendix/terminology/index.html

@@ -3740,8 +3740,8 @@
 <tr>
 <td>层</td>
 <td>level</td>
-<td>N 皇后问题</td>
-<td>N-queens problem</td>
+<td>n 皇后问题</td>
+<td>n-queens problem</td>
 </tr>
 <tr>
 <td>度</td>

chapter_array_and_linkedlist/summary/index.html

@@ -3520,8 +3520,8 @@
 <li>数组和链表是两种基本的数据结构，分别代表数据在计算机内存中的两种存储方式：连续空间存储和分散空间存储。两者的特点呈现出互补的特性。</li>
 <li>数组支持随机访问、占用内存较少；但插入和删除元素效率低，且初始化后长度不可变。</li>
 <li>链表通过更改引用（指针）实现高效的节点插入与删除，且可以灵活调整长度；但节点访问效率低、占用内存较多。常见的链表类型包括单向链表、环形链表、双向链表。</li>
-<li>列表是一种支持增删查改的元素有序集合，通常基于动态数组实现，它保留了数组的优势，同时可以灵活调整长度。</li>
-<li>列表的出现大幅地提高了数组的实用性，但可能导致部分内存空间浪费。</li>
+<li>列表是一种支持增删查改的元素有序集合，通常基于动态数组实现。它保留了数组的优势，同时可以灵活调整长度。</li>
+<li>列表的出现大幅提高了数组的实用性，但可能导致部分内存空间浪费。</li>
 <li>程序运行时，数据主要存储在内存中。数组可提供更高的内存空间效率，而链表则在内存使用上更加灵活。</li>
 <li>缓存通过缓存行、预取机制以及空间局部性和时间局部性等数据加载机制，为 CPU 提供快速数据访问，显著提升程序的执行效率。</li>
 <li>由于数组具有更高的缓存命中率，因此它通常比链表更高效。在选择数据结构时，应根据具体需求和场景做出恰当选择。</li>
@@ -3534,10 +3534,10 @@
 <li>大小限制：栈内存相对较小，堆的大小一般受限于可用内存。因此堆更加适合存储大型数组。</li>
 <li>灵活性：栈上的数组的大小需要在编译时确定，而堆上的数组的大小可以在运行时动态确定。</li>
 </ol>
-<p><strong>Q</strong>：为什么数组要求相同类型的元素，而在链表中却没有强调同类型呢？</p>
+<p><strong>Q</strong>：为什么数组要求相同类型的元素，而在链表中却没有强调相同类型呢？</p>
 <p>链表由节点组成，节点之间通过引用（指针）连接，各个节点可以存储不同类型的数据，例如 <code>int</code>、<code>double</code>、<code>string</code>、<code>object</code> 等。</p>
 <p>相对地，数组元素则必须是相同类型的，这样才能通过计算偏移量来获取对应元素位置。例如，数组同时包含 <code>int</code> 和 <code>long</code> 两种类型，单个元素分别占用 4 字节 和 8 字节 ，此时就不能用以下公式计算偏移量了，因为数组中包含了两种“元素长度”。</p>
-<div class="highlight"><pre><span></span><code><a id="__codelineno-0-1" name="__codelineno-0-1" href="#__codelineno-0-1"></a><span class="c1"># 元素内存地址 = 数组内存地址 + 元素长度 * 元素索引</span>
+<div class="highlight"><pre><span></span><code><a id="__codelineno-0-1" name="__codelineno-0-1" href="#__codelineno-0-1"></a><span class="c1"># 元素内存地址 = 数组内存地址（首元素内存地址） + 元素长度 * 元素索引</span>
 </code></pre></div>
 <p><strong>Q</strong>：删除节点后，是否需要把 <code>P.next</code> 设为 <code>None</code> 呢？</p>
 <p>不修改 <code>P.next</code> 也可以。从该链表的角度看，从头节点遍历到尾节点已经不会遇到 <code>P</code> 了。这意味着节点 <code>P</code> 已经从链表中删除了，此时节点 <code>P</code> 指向哪里都不会对该链表产生影响。</p>

chapter_backtracking/n_queens_problem/index.html

@@ -3532,7 +3532,7 @@
 
 
 <!-- Page content -->
-<h1 id="134-n">13.4 &nbsp; N 皇后问题<a class="headerlink" href="#134-n" title="Permanent link">&para;</a></h1>
+<h1 id="134-n">13.4 &nbsp; n 皇后问题<a class="headerlink" href="#134-n" title="Permanent link">&para;</a></h1>
 <div class="admonition question">
 <p class="admonition-title">Question</p>
 <p>根据国际象棋的规则，皇后可以攻击与同处一行、一列或一条斜线上的棋子。给定 <span class="arithmatex">\(n\)</span> 个皇后和一个 <span class="arithmatex">\(n \times n\)</span> 大小的棋盘，寻找使得所有皇后之间无法相互攻击的摆放方案。</p>
@@ -3575,7 +3575,7 @@
 <a id="__codelineno-0-7" name="__codelineno-0-7" href="#__codelineno-0-7"></a>    <span class="n">diags1</span><span class="p">:</span> <span class="nb">list</span><span class="p">[</span><span class="nb">bool</span><span class="p">],</span>
 <a id="__codelineno-0-8" name="__codelineno-0-8" href="#__codelineno-0-8"></a>    <span class="n">diags2</span><span class="p">:</span> <span class="nb">list</span><span class="p">[</span><span class="nb">bool</span><span class="p">],</span>
 <a id="__codelineno-0-9" name="__codelineno-0-9" href="#__codelineno-0-9"></a><span class="p">):</span>
-<a id="__codelineno-0-10" name="__codelineno-0-10" href="#__codelineno-0-10"></a><span class="w">    </span><span class="sd">&quot;&quot;&quot;回溯算法：N 皇后&quot;&quot;&quot;</span>
+<a id="__codelineno-0-10" name="__codelineno-0-10" href="#__codelineno-0-10"></a><span class="w">    </span><span class="sd">&quot;&quot;&quot;回溯算法：n 皇后&quot;&quot;&quot;</span>
 <a id="__codelineno-0-11" name="__codelineno-0-11" href="#__codelineno-0-11"></a>    <span class="c1"># 当放置完所有行时，记录解</span>
 <a id="__codelineno-0-12" name="__codelineno-0-12" href="#__codelineno-0-12"></a>    <span class="k">if</span> <span class="n">row</span> <span class="o">==</span> <span class="n">n</span><span class="p">:</span>
 <a id="__codelineno-0-13" name="__codelineno-0-13" href="#__codelineno-0-13"></a>        <span class="n">res</span><span class="o">.</span><span class="n">append</span><span class="p">([</span><span class="nb">list</span><span class="p">(</span><span class="n">row</span><span class="p">)</span> <span class="k">for</span> <span class="n">row</span> <span class="ow">in</span> <span class="n">state</span><span class="p">])</span>
@@ -3597,7 +3597,7 @@
 <a id="__codelineno-0-29" name="__codelineno-0-29" href="#__codelineno-0-29"></a>            <span class="n">cols</span><span class="p">[</span><span class="n">col</span><span class="p">]</span> <span class="o">=</span> <span class="n">diags1</span><span class="p">[</span><span class="n">diag1</span><span class="p">]</span> <span class="o">=</span> <span class="n">diags2</span><span class="p">[</span><span class="n">diag2</span><span class="p">]</span> <span class="o">=</span> <span class="kc">False</span>
 <a id="__codelineno-0-30" name="__codelineno-0-30" href="#__codelineno-0-30"></a>
 <a id="__codelineno-0-31" name="__codelineno-0-31" href="#__codelineno-0-31"></a><span class="k">def</span> <span class="nf">n_queens</span><span class="p">(</span><span class="n">n</span><span class="p">:</span> <span class="nb">int</span><span class="p">)</span> <span class="o">-&gt;</span> <span class="nb">list</span><span class="p">[</span><span class="nb">list</span><span class="p">[</span><span class="nb">list</span><span class="p">[</span><span class="nb">str</span><span class="p">]]]:</span>
-<a id="__codelineno-0-32" name="__codelineno-0-32" href="#__codelineno-0-32"></a><span class="w">    </span><span class="sd">&quot;&quot;&quot;求解 N 皇后&quot;&quot;&quot;</span>
+<a id="__codelineno-0-32" name="__codelineno-0-32" href="#__codelineno-0-32"></a><span class="w">    </span><span class="sd">&quot;&quot;&quot;求解 n 皇后&quot;&quot;&quot;</span>
 <a id="__codelineno-0-33" name="__codelineno-0-33" href="#__codelineno-0-33"></a>    <span class="c1"># 初始化 n*n 大小的棋盘，其中 &#39;Q&#39; 代表皇后，&#39;#&#39; 代表空位</span>
 <a id="__codelineno-0-34" name="__codelineno-0-34" href="#__codelineno-0-34"></a>    <span class="n">state</span> <span class="o">=</span> <span class="p">[[</span><span class="s2">&quot;#&quot;</span> <span class="k">for</span> <span class="n">_</span> <span class="ow">in</span> <span class="nb">range</span><span class="p">(</span><span class="n">n</span><span class="p">)]</span> <span class="k">for</span> <span class="n">_</span> <span class="ow">in</span> <span class="nb">range</span><span class="p">(</span><span class="n">n</span><span class="p">)]</span>
 <a id="__codelineno-0-35" name="__codelineno-0-35" href="#__codelineno-0-35"></a>    <span class="n">cols</span> <span class="o">=</span> <span class="p">[</span><span class="kc">False</span><span class="p">]</span> <span class="o">*</span> <span class="n">n</span>  <span class="c1"># 记录列是否有皇后</span>
@@ -3610,7 +3610,7 @@
 </code></pre></div>
 </div>
 <div class="tabbed-block">
-<div class="highlight"><span class="filename">n_queens.cpp</span><pre><span></span><code><a id="__codelineno-1-1" name="__codelineno-1-1" href="#__codelineno-1-1"></a><span class="cm">/* 回溯算法：N 皇后 */</span>
+<div class="highlight"><span class="filename">n_queens.cpp</span><pre><span></span><code><a id="__codelineno-1-1" name="__codelineno-1-1" href="#__codelineno-1-1"></a><span class="cm">/* 回溯算法：n 皇后 */</span>
 <a id="__codelineno-1-2" name="__codelineno-1-2" href="#__codelineno-1-2"></a><span class="kt">void</span><span class="w"> </span><span class="nf">backtrack</span><span class="p">(</span><span class="kt">int</span><span class="w"> </span><span class="n">row</span><span class="p">,</span><span class="w"> </span><span class="kt">int</span><span class="w"> </span><span class="n">n</span><span class="p">,</span><span class="w"> </span><span class="n">vector</span><span class="o">&lt;</span><span class="n">vector</span><span class="o">&lt;</span><span class="n">string</span><span class="o">&gt;&gt;</span><span class="w"> </span><span class="o">&amp;</span><span class="n">state</span><span class="p">,</span><span class="w"> </span><span class="n">vector</span><span class="o">&lt;</span><span class="n">vector</span><span class="o">&lt;</span><span class="n">vector</span><span class="o">&lt;</span><span class="n">string</span><span class="o">&gt;&gt;&gt;</span><span class="w"> </span><span class="o">&amp;</span><span class="n">res</span><span class="p">,</span><span class="w"> </span><span class="n">vector</span><span class="o">&lt;</span><span class="kt">bool</span><span class="o">&gt;</span><span class="w"> </span><span class="o">&amp;</span><span class="n">cols</span><span class="p">,</span>
 <a id="__codelineno-1-3" name="__codelineno-1-3" href="#__codelineno-1-3"></a><span class="w">               </span><span class="n">vector</span><span class="o">&lt;</span><span class="kt">bool</span><span class="o">&gt;</span><span class="w"> </span><span class="o">&amp;</span><span class="n">diags1</span><span class="p">,</span><span class="w"> </span><span class="n">vector</span><span class="o">&lt;</span><span class="kt">bool</span><span class="o">&gt;</span><span class="w"> </span><span class="o">&amp;</span><span class="n">diags2</span><span class="p">)</span><span class="w"> </span><span class="p">{</span>
 <a id="__codelineno-1-4" name="__codelineno-1-4" href="#__codelineno-1-4"></a><span class="w">    </span><span class="c1">// 当放置完所有行时，记录解</span>
@@ -3637,7 +3637,7 @@
 <a id="__codelineno-1-25" name="__codelineno-1-25" href="#__codelineno-1-25"></a><span class="w">    </span><span class="p">}</span>
 <a id="__codelineno-1-26" name="__codelineno-1-26" href="#__codelineno-1-26"></a><span class="p">}</span>
 <a id="__codelineno-1-27" name="__codelineno-1-27" href="#__codelineno-1-27"></a>
-<a id="__codelineno-1-28" name="__codelineno-1-28" href="#__codelineno-1-28"></a><span class="cm">/* 求解 N 皇后 */</span>
+<a id="__codelineno-1-28" name="__codelineno-1-28" href="#__codelineno-1-28"></a><span class="cm">/* 求解 n 皇后 */</span>
 <a id="__codelineno-1-29" name="__codelineno-1-29" href="#__codelineno-1-29"></a><span class="n">vector</span><span class="o">&lt;</span><span class="n">vector</span><span class="o">&lt;</span><span class="n">vector</span><span class="o">&lt;</span><span class="n">string</span><span class="o">&gt;&gt;&gt;</span><span class="w"> </span><span class="n">nQueens</span><span class="p">(</span><span class="kt">int</span><span class="w"> </span><span class="n">n</span><span class="p">)</span><span class="w"> </span><span class="p">{</span>
 <a id="__codelineno-1-30" name="__codelineno-1-30" href="#__codelineno-1-30"></a><span class="w">    </span><span class="c1">// 初始化 n*n 大小的棋盘，其中 &#39;Q&#39; 代表皇后，&#39;#&#39; 代表空位</span>
 <a id="__codelineno-1-31" name="__codelineno-1-31" href="#__codelineno-1-31"></a><span class="w">    </span><span class="n">vector</span><span class="o">&lt;</span><span class="n">vector</span><span class="o">&lt;</span><span class="n">string</span><span class="o">&gt;&gt;</span><span class="w"> </span><span class="n">state</span><span class="p">(</span><span class="n">n</span><span class="p">,</span><span class="w"> </span><span class="n">vector</span><span class="o">&lt;</span><span class="n">string</span><span class="o">&gt;</span><span class="p">(</span><span class="n">n</span><span class="p">,</span><span class="w"> </span><span class="s">&quot;#&quot;</span><span class="p">));</span>
@@ -3653,7 +3653,7 @@
 </code></pre></div>
 </div>
 <div class="tabbed-block">
-<div class="highlight"><span class="filename">n_queens.java</span><pre><span></span><code><a id="__codelineno-2-1" name="__codelineno-2-1" href="#__codelineno-2-1"></a><span class="cm">/* 回溯算法：N 皇后 */</span>
+<div class="highlight"><span class="filename">n_queens.java</span><pre><span></span><code><a id="__codelineno-2-1" name="__codelineno-2-1" href="#__codelineno-2-1"></a><span class="cm">/* 回溯算法：n 皇后 */</span>
 <a id="__codelineno-2-2" name="__codelineno-2-2" href="#__codelineno-2-2"></a><span class="kt">void</span><span class="w"> </span><span class="nf">backtrack</span><span class="p">(</span><span class="kt">int</span><span class="w"> </span><span class="n">row</span><span class="p">,</span><span class="w"> </span><span class="kt">int</span><span class="w"> </span><span class="n">n</span><span class="p">,</span><span class="w"> </span><span class="n">List</span><span class="o">&lt;</span><span class="n">List</span><span class="o">&lt;</span><span class="n">String</span><span class="o">&gt;&gt;</span><span class="w"> </span><span class="n">state</span><span class="p">,</span><span class="w"> </span><span class="n">List</span><span class="o">&lt;</span><span class="n">List</span><span class="o">&lt;</span><span class="n">List</span><span class="o">&lt;</span><span class="n">String</span><span class="o">&gt;&gt;&gt;</span><span class="w"> </span><span class="n">res</span><span class="p">,</span>
 <a id="__codelineno-2-3" name="__codelineno-2-3" href="#__codelineno-2-3"></a><span class="w">        </span><span class="kt">boolean</span><span class="o">[]</span><span class="w"> </span><span class="n">cols</span><span class="p">,</span><span class="w"> </span><span class="kt">boolean</span><span class="o">[]</span><span class="w"> </span><span class="n">diags1</span><span class="p">,</span><span class="w"> </span><span class="kt">boolean</span><span class="o">[]</span><span class="w"> </span><span class="n">diags2</span><span class="p">)</span><span class="w"> </span><span class="p">{</span>
 <a id="__codelineno-2-4" name="__codelineno-2-4" href="#__codelineno-2-4"></a><span class="w">    </span><span class="c1">// 当放置完所有行时，记录解</span>
@@ -3684,7 +3684,7 @@
 <a id="__codelineno-2-29" name="__codelineno-2-29" href="#__codelineno-2-29"></a><span class="w">    </span><span class="p">}</span>
 <a id="__codelineno-2-30" name="__codelineno-2-30" href="#__codelineno-2-30"></a><span class="p">}</span>
 <a id="__codelineno-2-31" name="__codelineno-2-31" href="#__codelineno-2-31"></a>
-<a id="__codelineno-2-32" name="__codelineno-2-32" href="#__codelineno-2-32"></a><span class="cm">/* 求解 N 皇后 */</span>
+<a id="__codelineno-2-32" name="__codelineno-2-32" href="#__codelineno-2-32"></a><span class="cm">/* 求解 n 皇后 */</span>
 <a id="__codelineno-2-33" name="__codelineno-2-33" href="#__codelineno-2-33"></a><span class="n">List</span><span class="o">&lt;</span><span class="n">List</span><span class="o">&lt;</span><span class="n">List</span><span class="o">&lt;</span><span class="n">String</span><span class="o">&gt;&gt;&gt;</span><span class="w"> </span><span class="nf">nQueens</span><span class="p">(</span><span class="kt">int</span><span class="w"> </span><span class="n">n</span><span class="p">)</span><span class="w"> </span><span class="p">{</span>
 <a id="__codelineno-2-34" name="__codelineno-2-34" href="#__codelineno-2-34"></a><span class="w">    </span><span class="c1">// 初始化 n*n 大小的棋盘，其中 &#39;Q&#39; 代表皇后，&#39;#&#39; 代表空位</span>
 <a id="__codelineno-2-35" name="__codelineno-2-35" href="#__codelineno-2-35"></a><span class="w">    </span><span class="n">List</span><span class="o">&lt;</span><span class="n">List</span><span class="o">&lt;</span><span class="n">String</span><span class="o">&gt;&gt;</span><span class="w"> </span><span class="n">state</span><span class="w"> </span><span class="o">=</span><span class="w"> </span><span class="k">new</span><span class="w"> </span><span class="n">ArrayList</span><span class="o">&lt;&gt;</span><span class="p">();</span>
@@ -3707,7 +3707,7 @@
 </code></pre></div>
 </div>
 <div class="tabbed-block">
-<div class="highlight"><span class="filename">n_queens.cs</span><pre><span></span><code><a id="__codelineno-3-1" name="__codelineno-3-1" href="#__codelineno-3-1"></a><span class="cm">/* 回溯算法：N 皇后 */</span>
+<div class="highlight"><span class="filename">n_queens.cs</span><pre><span></span><code><a id="__codelineno-3-1" name="__codelineno-3-1" href="#__codelineno-3-1"></a><span class="cm">/* 回溯算法：n 皇后 */</span>
 <a id="__codelineno-3-2" name="__codelineno-3-2" href="#__codelineno-3-2"></a><span class="k">void</span><span class="w"> </span><span class="nf">Backtrack</span><span class="p">(</span><span class="kt">int</span><span class="w"> </span><span class="n">row</span><span class="p">,</span><span class="w"> </span><span class="kt">int</span><span class="w"> </span><span class="n">n</span><span class="p">,</span><span class="w"> </span><span class="n">List</span><span class="o">&lt;</span><span class="n">List</span><span class="o">&lt;</span><span class="kt">string</span><span class="o">&gt;&gt;</span><span class="w"> </span><span class="n">state</span><span class="p">,</span><span class="w"> </span><span class="n">List</span><span class="o">&lt;</span><span class="n">List</span><span class="o">&lt;</span><span class="n">List</span><span class="o">&lt;</span><span class="kt">string</span><span class="o">&gt;&gt;&gt;</span><span class="w"> </span><span class="n">res</span><span class="p">,</span>
 <a id="__codelineno-3-3" name="__codelineno-3-3" href="#__codelineno-3-3"></a><span class="w">        </span><span class="kt">bool</span><span class="p">[]</span><span class="w"> </span><span class="n">cols</span><span class="p">,</span><span class="w"> </span><span class="kt">bool</span><span class="p">[]</span><span class="w"> </span><span class="n">diags1</span><span class="p">,</span><span class="w"> </span><span class="kt">bool</span><span class="p">[]</span><span class="w"> </span><span class="n">diags2</span><span class="p">)</span><span class="w"> </span><span class="p">{</span>
 <a id="__codelineno-3-4" name="__codelineno-3-4" href="#__codelineno-3-4"></a><span class="w">    </span><span class="c1">// 当放置完所有行时，记录解</span>
@@ -3738,7 +3738,7 @@
 <a id="__codelineno-3-29" name="__codelineno-3-29" href="#__codelineno-3-29"></a><span class="w">    </span><span class="p">}</span>
 <a id="__codelineno-3-30" name="__codelineno-3-30" href="#__codelineno-3-30"></a><span class="p">}</span>
 <a id="__codelineno-3-31" name="__codelineno-3-31" href="#__codelineno-3-31"></a>
-<a id="__codelineno-3-32" name="__codelineno-3-32" href="#__codelineno-3-32"></a><span class="cm">/* 求解 N 皇后 */</span>
+<a id="__codelineno-3-32" name="__codelineno-3-32" href="#__codelineno-3-32"></a><span class="cm">/* 求解 n 皇后 */</span>
 <a id="__codelineno-3-33" name="__codelineno-3-33" href="#__codelineno-3-33"></a><span class="n">List</span><span class="o">&lt;</span><span class="n">List</span><span class="o">&lt;</span><span class="n">List</span><span class="o">&lt;</span><span class="kt">string</span><span class="o">&gt;&gt;&gt;</span><span class="w"> </span><span class="n">NQueens</span><span class="p">(</span><span class="kt">int</span><span class="w"> </span><span class="n">n</span><span class="p">)</span><span class="w"> </span><span class="p">{</span>
 <a id="__codelineno-3-34" name="__codelineno-3-34" href="#__codelineno-3-34"></a><span class="w">    </span><span class="c1">// 初始化 n*n 大小的棋盘，其中 &#39;Q&#39; 代表皇后，&#39;#&#39; 代表空位</span>
 <a id="__codelineno-3-35" name="__codelineno-3-35" href="#__codelineno-3-35"></a><span class="w">    </span><span class="n">List</span><span class="o">&lt;</span><span class="n">List</span><span class="o">&lt;</span><span class="kt">string</span><span class="o">&gt;&gt;</span><span class="w"> </span><span class="n">state</span><span class="w"> </span><span class="o">=</span><span class="w"> </span><span class="p">[];</span>
@@ -3761,7 +3761,7 @@
 </code></pre></div>
 </div>
 <div class="tabbed-block">
-<div class="highlight"><span class="filename">n_queens.go</span><pre><span></span><code><a id="__codelineno-4-1" name="__codelineno-4-1" href="#__codelineno-4-1"></a><span class="cm">/* 回溯算法：N 皇后 */</span>
+<div class="highlight"><span class="filename">n_queens.go</span><pre><span></span><code><a id="__codelineno-4-1" name="__codelineno-4-1" href="#__codelineno-4-1"></a><span class="cm">/* 回溯算法：n 皇后 */</span>
 <a id="__codelineno-4-2" name="__codelineno-4-2" href="#__codelineno-4-2"></a><span class="kd">func</span><span class="w"> </span><span class="nx">backtrack</span><span class="p">(</span><span class="nx">row</span><span class="p">,</span><span class="w"> </span><span class="nx">n</span><span class="w"> </span><span class="kt">int</span><span class="p">,</span><span class="w"> </span><span class="nx">state</span><span class="w"> </span><span class="o">*</span><span class="p">[][]</span><span class="kt">string</span><span class="p">,</span><span class="w"> </span><span class="nx">res</span><span class="w"> </span><span class="o">*</span><span class="p">[][][]</span><span class="kt">string</span><span class="p">,</span><span class="w"> </span><span class="nx">cols</span><span class="p">,</span><span class="w"> </span><span class="nx">diags1</span><span class="p">,</span><span class="w"> </span><span class="nx">diags2</span><span class="w"> </span><span class="o">*</span><span class="p">[]</span><span class="kt">bool</span><span class="p">)</span><span class="w"> </span><span class="p">{</span>
 <a id="__codelineno-4-3" name="__codelineno-4-3" href="#__codelineno-4-3"></a><span class="w">    </span><span class="c1">// 当放置完所有行时，记录解</span>
 <a id="__codelineno-4-4" name="__codelineno-4-4" href="#__codelineno-4-4"></a><span class="w">    </span><span class="k">if</span><span class="w"> </span><span class="nx">row</span><span class="w"> </span><span class="o">==</span><span class="w"> </span><span class="nx">n</span><span class="w"> </span><span class="p">{</span>
@@ -3792,59 +3792,29 @@
 <a id="__codelineno-4-29" name="__codelineno-4-29" href="#__codelineno-4-29"></a><span class="w">    </span><span class="p">}</span>
 <a id="__codelineno-4-30" name="__codelineno-4-30" href="#__codelineno-4-30"></a><span class="p">}</span>
 <a id="__codelineno-4-31" name="__codelineno-4-31" href="#__codelineno-4-31"></a>
-<a id="__codelineno-4-32" name="__codelineno-4-32" href="#__codelineno-4-32"></a><span class="cm">/* 回溯算法：N 皇后 */</span>
-<a id="__codelineno-4-33" name="__codelineno-4-33" href="#__codelineno-4-33"></a><span class="kd">func</span><span class="w"> </span><span class="nx">backtrack</span><span class="p">(</span><span class="nx">row</span><span class="p">,</span><span class="w"> </span><span class="nx">n</span><span class="w"> </span><span class="kt">int</span><span class="p">,</span><span class="w"> </span><span class="nx">state</span><span class="w"> </span><span class="o">*</span><span class="p">[][]</span><span class="kt">string</span><span class="p">,</span><span class="w"> </span><span class="nx">res</span><span class="w"> </span><span class="o">*</span><span class="p">[][][]</span><span class="kt">string</span><span class="p">,</span><span class="w"> </span><span class="nx">cols</span><span class="p">,</span><span class="w"> </span><span class="nx">diags1</span><span class="p">,</span><span class="w"> </span><span class="nx">diags2</span><span class="w"> </span><span class="o">*</span><span class="p">[]</span><span class="kt">bool</span><span class="p">)</span><span class="w"> </span><span class="p">{</span>
-<a id="__codelineno-4-34" name="__codelineno-4-34" href="#__codelineno-4-34"></a><span class="w">    </span><span class="c1">// 当放置完所有行时，记录解</span>
-<a id="__codelineno-4-35" name="__codelineno-4-35" href="#__codelineno-4-35"></a><span class="w">    </span><span class="k">if</span><span class="w"> </span><span class="nx">row</span><span class="w"> </span><span class="o">==</span><span class="w"> </span><span class="nx">n</span><span class="w"> </span><span class="p">{</span>
-<a id="__codelineno-4-36" name="__codelineno-4-36" href="#__codelineno-4-36"></a><span class="w">        </span><span class="nx">newState</span><span class="w"> </span><span class="o">:=</span><span class="w"> </span><span class="nb">make</span><span class="p">([][]</span><span class="kt">string</span><span class="p">,</span><span class="w"> </span><span class="nb">len</span><span class="p">(</span><span class="o">*</span><span class="nx">state</span><span class="p">))</span>
-<a id="__codelineno-4-37" name="__codelineno-4-37" href="#__codelineno-4-37"></a><span class="w">        </span><span class="k">for</span><span class="w"> </span><span class="nx">i</span><span class="p">,</span><span class="w"> </span><span class="nx">_</span><span class="w"> </span><span class="o">:=</span><span class="w"> </span><span class="k">range</span><span class="w"> </span><span class="nx">newState</span><span class="w"> </span><span class="p">{</span>
-<a id="__codelineno-4-38" name="__codelineno-4-38" href="#__codelineno-4-38"></a><span class="w">            </span><span class="nx">newState</span><span class="p">[</span><span class="nx">i</span><span class="p">]</span><span class="w"> </span><span class="p">=</span><span class="w"> </span><span class="nb">make</span><span class="p">([]</span><span class="kt">string</span><span class="p">,</span><span class="w"> </span><span class="nb">len</span><span class="p">((</span><span class="o">*</span><span class="nx">state</span><span class="p">)[</span><span class="mi">0</span><span class="p">]))</span>
-<a id="__codelineno-4-39" name="__codelineno-4-39" href="#__codelineno-4-39"></a><span class="w">            </span><span class="nb">copy</span><span class="p">(</span><span class="nx">newState</span><span class="p">[</span><span class="nx">i</span><span class="p">],</span><span class="w"> </span><span class="p">(</span><span class="o">*</span><span class="nx">state</span><span class="p">)[</span><span class="nx">i</span><span class="p">])</span>
-<a id="__codelineno-4-40" name="__codelineno-4-40" href="#__codelineno-4-40"></a>
-<a id="__codelineno-4-41" name="__codelineno-4-41" href="#__codelineno-4-41"></a><span class="w">        </span><span class="p">}</span>
-<a id="__codelineno-4-42" name="__codelineno-4-42" href="#__codelineno-4-42"></a><span class="w">        </span><span class="o">*</span><span class="nx">res</span><span class="w"> </span><span class="p">=</span><span class="w"> </span><span class="nb">append</span><span class="p">(</span><span class="o">*</span><span class="nx">res</span><span class="p">,</span><span class="w"> </span><span class="nx">newState</span><span class="p">)</span>
-<a id="__codelineno-4-43" name="__codelineno-4-43" href="#__codelineno-4-43"></a><span class="w">    </span><span class="p">}</span>
-<a id="__codelineno-4-44" name="__codelineno-4-44" href="#__codelineno-4-44"></a><span class="w">    </span><span class="c1">// 遍历所有列</span>
-<a id="__codelineno-4-45" name="__codelineno-4-45" href="#__codelineno-4-45"></a><span class="w">    </span><span class="k">for</span><span class="w"> </span><span class="nx">col</span><span class="w"> </span><span class="o">:=</span><span class="w"> </span><span class="mi">0</span><span class="p">;</span><span class="w"> </span><span class="nx">col</span><span class="w"> </span><span class="p">&lt;</span><span class="w"> </span><span class="nx">n</span><span class="p">;</span><span class="w"> </span><span class="nx">col</span><span class="o">++</span><span class="w"> </span><span class="p">{</span>
-<a id="__codelineno-4-46" name="__codelineno-4-46" href="#__codelineno-4-46"></a><span class="w">        </span><span class="c1">// 计算该格子对应的主对角线和次对角线</span>
-<a id="__codelineno-4-47" name="__codelineno-4-47" href="#__codelineno-4-47"></a><span class="w">        </span><span class="nx">diag1</span><span class="w"> </span><span class="o">:=</span><span class="w"> </span><span class="nx">row</span><span class="w"> </span><span class="o">-</span><span class="w"> </span><span class="nx">col</span><span class="w"> </span><span class="o">+</span><span class="w"> </span><span class="nx">n</span><span class="w"> </span><span class="o">-</span><span class="w"> </span><span class="mi">1</span>
-<a id="__codelineno-4-48" name="__codelineno-4-48" href="#__codelineno-4-48"></a><span class="w">        </span><span class="nx">diag2</span><span class="w"> </span><span class="o">:=</span><span class="w"> </span><span class="nx">row</span><span class="w"> </span><span class="o">+</span><span class="w"> </span><span class="nx">col</span>
-<a id="__codelineno-4-49" name="__codelineno-4-49" href="#__codelineno-4-49"></a><span class="w">        </span><span class="c1">// 剪枝：不允许该格子所在列、主对角线、次对角线上存在皇后</span>
-<a id="__codelineno-4-50" name="__codelineno-4-50" href="#__codelineno-4-50"></a><span class="w">        </span><span class="k">if</span><span class="w"> </span><span class="p">!(</span><span class="o">*</span><span class="nx">cols</span><span class="p">)[</span><span class="nx">col</span><span class="p">]</span><span class="w"> </span><span class="o">&amp;&amp;</span><span class="w"> </span><span class="p">!(</span><span class="o">*</span><span class="nx">diags1</span><span class="p">)[</span><span class="nx">diag1</span><span class="p">]</span><span class="w"> </span><span class="o">&amp;&amp;</span><span class="w"> </span><span class="p">!(</span><span class="o">*</span><span class="nx">diags2</span><span class="p">)[</span><span class="nx">diag2</span><span class="p">]</span><span class="w"> </span><span class="p">{</span>
-<a id="__codelineno-4-51" name="__codelineno-4-51" href="#__codelineno-4-51"></a><span class="w">            </span><span class="c1">// 尝试：将皇后放置在该格子</span>
-<a id="__codelineno-4-52" name="__codelineno-4-52" href="#__codelineno-4-52"></a><span class="w">            </span><span class="p">(</span><span class="o">*</span><span class="nx">state</span><span class="p">)[</span><span class="nx">row</span><span class="p">][</span><span class="nx">col</span><span class="p">]</span><span class="w"> </span><span class="p">=</span><span class="w"> </span><span class="s">&quot;Q&quot;</span>
-<a id="__codelineno-4-53" name="__codelineno-4-53" href="#__codelineno-4-53"></a><span class="w">            </span><span class="p">(</span><span class="o">*</span><span class="nx">cols</span><span class="p">)[</span><span class="nx">col</span><span class="p">],</span><span class="w"> </span><span class="p">(</span><span class="o">*</span><span class="nx">diags1</span><span class="p">)[</span><span class="nx">diag1</span><span class="p">],</span><span class="w"> </span><span class="p">(</span><span class="o">*</span><span class="nx">diags2</span><span class="p">)[</span><span class="nx">diag2</span><span class="p">]</span><span class="w"> </span><span class="p">=</span><span class="w"> </span><span class="kc">true</span><span class="p">,</span><span class="w"> </span><span class="kc">true</span><span class="p">,</span><span class="w"> </span><span class="kc">true</span>
-<a id="__codelineno-4-54" name="__codelineno-4-54" href="#__codelineno-4-54"></a><span class="w">            </span><span class="c1">// 放置下一行</span>
-<a id="__codelineno-4-55" name="__codelineno-4-55" href="#__codelineno-4-55"></a><span class="w">            </span><span class="nx">backtrack</span><span class="p">(</span><span class="nx">row</span><span class="o">+</span><span class="mi">1</span><span class="p">,</span><span class="w"> </span><span class="nx">n</span><span class="p">,</span><span class="w"> </span><span class="nx">state</span><span class="p">,</span><span class="w"> </span><span class="nx">res</span><span class="p">,</span><span class="w"> </span><span class="nx">cols</span><span class="p">,</span><span class="w"> </span><span class="nx">diags1</span><span class="p">,</span><span class="w"> </span><span class="nx">diags2</span><span class="p">)</span>
-<a id="__codelineno-4-56" name="__codelineno-4-56" href="#__codelineno-4-56"></a><span class="w">            </span><span class="c1">// 回退：将该格子恢复为空位</span>
-<a id="__codelineno-4-57" name="__codelineno-4-57" href="#__codelineno-4-57"></a><span class="w">            </span><span class="p">(</span><span class="o">*</span><span class="nx">state</span><span class="p">)[</span><span class="nx">row</span><span class="p">][</span><span class="nx">col</span><span class="p">]</span><span class="w"> </span><span class="p">=</span><span class="w"> </span><span class="s">&quot;#&quot;</span>
-<a id="__codelineno-4-58" name="__codelineno-4-58" href="#__codelineno-4-58"></a><span class="w">            </span><span class="p">(</span><span class="o">*</span><span class="nx">cols</span><span class="p">)[</span><span class="nx">col</span><span class="p">],</span><span class="w"> </span><span class="p">(</span><span class="o">*</span><span class="nx">diags1</span><span class="p">)[</span><span class="nx">diag1</span><span class="p">],</span><span class="w"> </span><span class="p">(</span><span class="o">*</span><span class="nx">diags2</span><span class="p">)[</span><span class="nx">diag2</span><span class="p">]</span><span class="w"> </span><span class="p">=</span><span class="w"> </span><span class="kc">false</span><span class="p">,</span><span class="w"> </span><span class="kc">false</span><span class="p">,</span><span class="w"> </span><span class="kc">false</span>
-<a id="__codelineno-4-59" name="__codelineno-4-59" href="#__codelineno-4-59"></a><span class="w">        </span><span class="p">}</span>
-<a id="__codelineno-4-60" name="__codelineno-4-60" href="#__codelineno-4-60"></a><span class="w">    </span><span class="p">}</span>
-<a id="__codelineno-4-61" name="__codelineno-4-61" href="#__codelineno-4-61"></a><span class="p">}</span>
-<a id="__codelineno-4-62" name="__codelineno-4-62" href="#__codelineno-4-62"></a>
-<a id="__codelineno-4-63" name="__codelineno-4-63" href="#__codelineno-4-63"></a><span class="kd">func</span><span class="w"> </span><span class="nx">nQueens</span><span class="p">(</span><span class="nx">n</span><span class="w"> </span><span class="kt">int</span><span class="p">)</span><span class="w"> </span><span class="p">[][][]</span><span class="kt">string</span><span class="w"> </span><span class="p">{</span>
-<a id="__codelineno-4-64" name="__codelineno-4-64" href="#__codelineno-4-64"></a><span class="w">    </span><span class="c1">// 初始化 n*n 大小的棋盘，其中 &#39;Q&#39; 代表皇后，&#39;#&#39; 代表空位</span>
-<a id="__codelineno-4-65" name="__codelineno-4-65" href="#__codelineno-4-65"></a><span class="w">    </span><span class="nx">state</span><span class="w"> </span><span class="o">:=</span><span class="w"> </span><span class="nb">make</span><span class="p">([][]</span><span class="kt">string</span><span class="p">,</span><span class="w"> </span><span class="nx">n</span><span class="p">)</span>
-<a id="__codelineno-4-66" name="__codelineno-4-66" href="#__codelineno-4-66"></a><span class="w">    </span><span class="k">for</span><span class="w"> </span><span class="nx">i</span><span class="w"> </span><span class="o">:=</span><span class="w"> </span><span class="mi">0</span><span class="p">;</span><span class="w"> </span><span class="nx">i</span><span class="w"> </span><span class="p">&lt;</span><span class="w"> </span><span class="nx">n</span><span class="p">;</span><span class="w"> </span><span class="nx">i</span><span class="o">++</span><span class="w"> </span><span class="p">{</span>
-<a id="__codelineno-4-67" name="__codelineno-4-67" href="#__codelineno-4-67"></a><span class="w">        </span><span class="nx">row</span><span class="w"> </span><span class="o">:=</span><span class="w"> </span><span class="nb">make</span><span class="p">([]</span><span class="kt">string</span><span class="p">,</span><span class="w"> </span><span class="nx">n</span><span class="p">)</span>
-<a id="__codelineno-4-68" name="__codelineno-4-68" href="#__codelineno-4-68"></a><span class="w">        </span><span class="k">for</span><span class="w"> </span><span class="nx">i</span><span class="w"> </span><span class="o">:=</span><span class="w"> </span><span class="mi">0</span><span class="p">;</span><span class="w"> </span><span class="nx">i</span><span class="w"> </span><span class="p">&lt;</span><span class="w"> </span><span class="nx">n</span><span class="p">;</span><span class="w"> </span><span class="nx">i</span><span class="o">++</span><span class="w"> </span><span class="p">{</span>
-<a id="__codelineno-4-69" name="__codelineno-4-69" href="#__codelineno-4-69"></a><span class="w">            </span><span class="nx">row</span><span class="p">[</span><span class="nx">i</span><span class="p">]</span><span class="w"> </span><span class="p">=</span><span class="w"> </span><span class="s">&quot;#&quot;</span>
-<a id="__codelineno-4-70" name="__codelineno-4-70" href="#__codelineno-4-70"></a><span class="w">        </span><span class="p">}</span>
-<a id="__codelineno-4-71" name="__codelineno-4-71" href="#__codelineno-4-71"></a><span class="w">        </span><span class="nx">state</span><span class="p">[</span><span class="nx">i</span><span class="p">]</span><span class="w"> </span><span class="p">=</span><span class="w"> </span><span class="nx">row</span>
-<a id="__codelineno-4-72" name="__codelineno-4-72" href="#__codelineno-4-72"></a><span class="w">    </span><span class="p">}</span>
-<a id="__codelineno-4-73" name="__codelineno-4-73" href="#__codelineno-4-73"></a><span class="w">    </span><span class="c1">// 记录列是否有皇后</span>
-<a id="__codelineno-4-74" name="__codelineno-4-74" href="#__codelineno-4-74"></a><span class="w">    </span><span class="nx">cols</span><span class="w"> </span><span class="o">:=</span><span class="w"> </span><span class="nb">make</span><span class="p">([]</span><span class="kt">bool</span><span class="p">,</span><span class="w"> </span><span class="nx">n</span><span class="p">)</span>
-<a id="__codelineno-4-75" name="__codelineno-4-75" href="#__codelineno-4-75"></a><span class="w">    </span><span class="nx">diags1</span><span class="w"> </span><span class="o">:=</span><span class="w"> </span><span class="nb">make</span><span class="p">([]</span><span class="kt">bool</span><span class="p">,</span><span class="w"> </span><span class="mi">2</span><span class="o">*</span><span class="nx">n</span><span class="o">-</span><span class="mi">1</span><span class="p">)</span>
-<a id="__codelineno-4-76" name="__codelineno-4-76" href="#__codelineno-4-76"></a><span class="w">    </span><span class="nx">diags2</span><span class="w"> </span><span class="o">:=</span><span class="w"> </span><span class="nb">make</span><span class="p">([]</span><span class="kt">bool</span><span class="p">,</span><span class="w"> </span><span class="mi">2</span><span class="o">*</span><span class="nx">n</span><span class="o">-</span><span class="mi">1</span><span class="p">)</span>
-<a id="__codelineno-4-77" name="__codelineno-4-77" href="#__codelineno-4-77"></a><span class="w">    </span><span class="nx">res</span><span class="w"> </span><span class="o">:=</span><span class="w"> </span><span class="nb">make</span><span class="p">([][][]</span><span class="kt">string</span><span class="p">,</span><span class="w"> </span><span class="mi">0</span><span class="p">)</span>
-<a id="__codelineno-4-78" name="__codelineno-4-78" href="#__codelineno-4-78"></a><span class="w">    </span><span class="nx">backtrack</span><span class="p">(</span><span class="mi">0</span><span class="p">,</span><span class="w"> </span><span class="nx">n</span><span class="p">,</span><span class="w"> </span><span class="o">&amp;</span><span class="nx">state</span><span class="p">,</span><span class="w"> </span><span class="o">&amp;</span><span class="nx">res</span><span class="p">,</span><span class="w"> </span><span class="o">&amp;</span><span class="nx">cols</span><span class="p">,</span><span class="w"> </span><span class="o">&amp;</span><span class="nx">diags1</span><span class="p">,</span><span class="w"> </span><span class="o">&amp;</span><span class="nx">diags2</span><span class="p">)</span>
-<a id="__codelineno-4-79" name="__codelineno-4-79" href="#__codelineno-4-79"></a><span class="w">    </span><span class="k">return</span><span class="w"> </span><span class="nx">res</span>
-<a id="__codelineno-4-80" name="__codelineno-4-80" href="#__codelineno-4-80"></a><span class="p">}</span>
+<a id="__codelineno-4-32" name="__codelineno-4-32" href="#__codelineno-4-32"></a><span class="cm">/* 求解 n 皇后 */</span>
+<a id="__codelineno-4-33" name="__codelineno-4-33" href="#__codelineno-4-33"></a><span class="kd">func</span><span class="w"> </span><span class="nx">nQueens</span><span class="p">(</span><span class="nx">n</span><span class="w"> </span><span class="kt">int</span><span class="p">)</span><span class="w"> </span><span class="p">[][][]</span><span class="kt">string</span><span class="w"> </span><span class="p">{</span>
+<a id="__codelineno-4-34" name="__codelineno-4-34" href="#__codelineno-4-34"></a><span class="w">    </span><span class="c1">// 初始化 n*n 大小的棋盘，其中 &#39;Q&#39; 代表皇后，&#39;#&#39; 代表空位</span>
+<a id="__codelineno-4-35" name="__codelineno-4-35" href="#__codelineno-4-35"></a><span class="w">    </span><span class="nx">state</span><span class="w"> </span><span class="o">:=</span><span class="w"> </span><span class="nb">make</span><span class="p">([][]</span><span class="kt">string</span><span class="p">,</span><span class="w"> </span><span class="nx">n</span><span class="p">)</span>
+<a id="__codelineno-4-36" name="__codelineno-4-36" href="#__codelineno-4-36"></a><span class="w">    </span><span class="k">for</span><span class="w"> </span><span class="nx">i</span><span class="w"> </span><span class="o">:=</span><span class="w"> </span><span class="mi">0</span><span class="p">;</span><span class="w"> </span><span class="nx">i</span><span class="w"> </span><span class="p">&lt;</span><span class="w"> </span><span class="nx">n</span><span class="p">;</span><span class="w"> </span><span class="nx">i</span><span class="o">++</span><span class="w"> </span><span class="p">{</span>
+<a id="__codelineno-4-37" name="__codelineno-4-37" href="#__codelineno-4-37"></a><span class="w">        </span><span class="nx">row</span><span class="w"> </span><span class="o">:=</span><span class="w"> </span><span class="nb">make</span><span class="p">([]</span><span class="kt">string</span><span class="p">,</span><span class="w"> </span><span class="nx">n</span><span class="p">)</span>
+<a id="__codelineno-4-38" name="__codelineno-4-38" href="#__codelineno-4-38"></a><span class="w">        </span><span class="k">for</span><span class="w"> </span><span class="nx">i</span><span class="w"> </span><span class="o">:=</span><span class="w"> </span><span class="mi">0</span><span class="p">;</span><span class="w"> </span><span class="nx">i</span><span class="w"> </span><span class="p">&lt;</span><span class="w"> </span><span class="nx">n</span><span class="p">;</span><span class="w"> </span><span class="nx">i</span><span class="o">++</span><span class="w"> </span><span class="p">{</span>
+<a id="__codelineno-4-39" name="__codelineno-4-39" href="#__codelineno-4-39"></a><span class="w">            </span><span class="nx">row</span><span class="p">[</span><span class="nx">i</span><span class="p">]</span><span class="w"> </span><span class="p">=</span><span class="w"> </span><span class="s">&quot;#&quot;</span>
+<a id="__codelineno-4-40" name="__codelineno-4-40" href="#__codelineno-4-40"></a><span class="w">        </span><span class="p">}</span>
+<a id="__codelineno-4-41" name="__codelineno-4-41" href="#__codelineno-4-41"></a><span class="w">        </span><span class="nx">state</span><span class="p">[</span><span class="nx">i</span><span class="p">]</span><span class="w"> </span><span class="p">=</span><span class="w"> </span><span class="nx">row</span>
+<a id="__codelineno-4-42" name="__codelineno-4-42" href="#__codelineno-4-42"></a><span class="w">    </span><span class="p">}</span>
+<a id="__codelineno-4-43" name="__codelineno-4-43" href="#__codelineno-4-43"></a><span class="w">    </span><span class="c1">// 记录列是否有皇后</span>
+<a id="__codelineno-4-44" name="__codelineno-4-44" href="#__codelineno-4-44"></a><span class="w">    </span><span class="nx">cols</span><span class="w"> </span><span class="o">:=</span><span class="w"> </span><span class="nb">make</span><span class="p">([]</span><span class="kt">bool</span><span class="p">,</span><span class="w"> </span><span class="nx">n</span><span class="p">)</span>
+<a id="__codelineno-4-45" name="__codelineno-4-45" href="#__codelineno-4-45"></a><span class="w">    </span><span class="nx">diags1</span><span class="w"> </span><span class="o">:=</span><span class="w"> </span><span class="nb">make</span><span class="p">([]</span><span class="kt">bool</span><span class="p">,</span><span class="w"> </span><span class="mi">2</span><span class="o">*</span><span class="nx">n</span><span class="o">-</span><span class="mi">1</span><span class="p">)</span>
+<a id="__codelineno-4-46" name="__codelineno-4-46" href="#__codelineno-4-46"></a><span class="w">    </span><span class="nx">diags2</span><span class="w"> </span><span class="o">:=</span><span class="w"> </span><span class="nb">make</span><span class="p">([]</span><span class="kt">bool</span><span class="p">,</span><span class="w"> </span><span class="mi">2</span><span class="o">*</span><span class="nx">n</span><span class="o">-</span><span class="mi">1</span><span class="p">)</span>
+<a id="__codelineno-4-47" name="__codelineno-4-47" href="#__codelineno-4-47"></a><span class="w">    </span><span class="nx">res</span><span class="w"> </span><span class="o">:=</span><span class="w"> </span><span class="nb">make</span><span class="p">([][][]</span><span class="kt">string</span><span class="p">,</span><span class="w"> </span><span class="mi">0</span><span class="p">)</span>
+<a id="__codelineno-4-48" name="__codelineno-4-48" href="#__codelineno-4-48"></a><span class="w">    </span><span class="nx">backtrack</span><span class="p">(</span><span class="mi">0</span><span class="p">,</span><span class="w"> </span><span class="nx">n</span><span class="p">,</span><span class="w"> </span><span class="o">&amp;</span><span class="nx">state</span><span class="p">,</span><span class="w"> </span><span class="o">&amp;</span><span class="nx">res</span><span class="p">,</span><span class="w"> </span><span class="o">&amp;</span><span class="nx">cols</span><span class="p">,</span><span class="w"> </span><span class="o">&amp;</span><span class="nx">diags1</span><span class="p">,</span><span class="w"> </span><span class="o">&amp;</span><span class="nx">diags2</span><span class="p">)</span>
+<a id="__codelineno-4-49" name="__codelineno-4-49" href="#__codelineno-4-49"></a><span class="w">    </span><span class="k">return</span><span class="w"> </span><span class="nx">res</span>
+<a id="__codelineno-4-50" name="__codelineno-4-50" href="#__codelineno-4-50"></a><span class="p">}</span>
 </code></pre></div>
 </div>
 <div class="tabbed-block">
-<div class="highlight"><span class="filename">n_queens.swift</span><pre><span></span><code><a id="__codelineno-5-1" name="__codelineno-5-1" href="#__codelineno-5-1"></a><span class="cm">/* 回溯算法：N 皇后 */</span>
+<div class="highlight"><span class="filename">n_queens.swift</span><pre><span></span><code><a id="__codelineno-5-1" name="__codelineno-5-1" href="#__codelineno-5-1"></a><span class="cm">/* 回溯算法：n 皇后 */</span>
 <a id="__codelineno-5-2" name="__codelineno-5-2" href="#__codelineno-5-2"></a><span class="kd">func</span> <span class="nf">backtrack</span><span class="p">(</span><span class="n">row</span><span class="p">:</span> <span class="nb">Int</span><span class="p">,</span> <span class="n">n</span><span class="p">:</span> <span class="nb">Int</span><span class="p">,</span> <span class="n">state</span><span class="p">:</span> <span class="kr">inout</span> <span class="p">[[</span><span class="nb">String</span><span class="p">]],</span> <span class="n">res</span><span class="p">:</span> <span class="kr">inout</span> <span class="p">[[[</span><span class="nb">String</span><span class="p">]]],</span> <span class="n">cols</span><span class="p">:</span> <span class="kr">inout</span> <span class="p">[</span><span class="nb">Bool</span><span class="p">],</span> <span class="n">diags1</span><span class="p">:</span> <span class="kr">inout</span> <span class="p">[</span><span class="nb">Bool</span><span class="p">],</span> <span class="n">diags2</span><span class="p">:</span> <span class="kr">inout</span> <span class="p">[</span><span class="nb">Bool</span><span class="p">])</span> <span class="p">{</span>
 <a id="__codelineno-5-3" name="__codelineno-5-3" href="#__codelineno-5-3"></a>    <span class="c1">// 当放置完所有行时，记录解</span>
 <a id="__codelineno-5-4" name="__codelineno-5-4" href="#__codelineno-5-4"></a>    <span class="k">if</span> <span class="n">row</span> <span class="p">==</span> <span class="n">n</span> <span class="p">{</span>
@@ -3874,7 +3844,7 @@
 <a id="__codelineno-5-28" name="__codelineno-5-28" href="#__codelineno-5-28"></a>    <span class="p">}</span>
 <a id="__codelineno-5-29" name="__codelineno-5-29" href="#__codelineno-5-29"></a><span class="p">}</span>
 <a id="__codelineno-5-30" name="__codelineno-5-30" href="#__codelineno-5-30"></a>
-<a id="__codelineno-5-31" name="__codelineno-5-31" href="#__codelineno-5-31"></a><span class="cm">/* 求解 N 皇后 */</span>
+<a id="__codelineno-5-31" name="__codelineno-5-31" href="#__codelineno-5-31"></a><span class="cm">/* 求解 n 皇后 */</span>
 <a id="__codelineno-5-32" name="__codelineno-5-32" href="#__codelineno-5-32"></a><span class="kd">func</span> <span class="nf">nQueens</span><span class="p">(</span><span class="n">n</span><span class="p">:</span> <span class="nb">Int</span><span class="p">)</span> <span class="p">-&gt;</span> <span class="p">[[[</span><span class="nb">String</span><span class="p">]]]</span> <span class="p">{</span>
 <a id="__codelineno-5-33" name="__codelineno-5-33" href="#__codelineno-5-33"></a>    <span class="c1">// 初始化 n*n 大小的棋盘，其中 &#39;Q&#39; 代表皇后，&#39;#&#39; 代表空位</span>
 <a id="__codelineno-5-34" name="__codelineno-5-34" href="#__codelineno-5-34"></a>    <span class="kd">var</span> <span class="nv">state</span> <span class="p">=</span> <span class="nb">Array</span><span class="p">(</span><span class="n">repeating</span><span class="p">:</span> <span class="nb">Array</span><span class="p">(</span><span class="n">repeating</span><span class="p">:</span> <span class="s">&quot;#&quot;</span><span class="p">,</span> <span class="bp">count</span><span class="p">:</span> <span class="n">n</span><span class="p">),</span> <span class="bp">count</span><span class="p">:</span> <span class="n">n</span><span class="p">)</span>
@@ -3890,7 +3860,7 @@
 </code></pre></div>
 </div>
 <div class="tabbed-block">
-<div class="highlight"><span class="filename">n_queens.js</span><pre><span></span><code><a id="__codelineno-6-1" name="__codelineno-6-1" href="#__codelineno-6-1"></a><span class="cm">/* 回溯算法：N 皇后 */</span>
+<div class="highlight"><span class="filename">n_queens.js</span><pre><span></span><code><a id="__codelineno-6-1" name="__codelineno-6-1" href="#__codelineno-6-1"></a><span class="cm">/* 回溯算法：n 皇后 */</span>
 <a id="__codelineno-6-2" name="__codelineno-6-2" href="#__codelineno-6-2"></a><span class="kd">function</span><span class="w"> </span><span class="nx">backtrack</span><span class="p">(</span><span class="nx">row</span><span class="p">,</span><span class="w"> </span><span class="nx">n</span><span class="p">,</span><span class="w"> </span><span class="nx">state</span><span class="p">,</span><span class="w"> </span><span class="nx">res</span><span class="p">,</span><span class="w"> </span><span class="nx">cols</span><span class="p">,</span><span class="w"> </span><span class="nx">diags1</span><span class="p">,</span><span class="w"> </span><span class="nx">diags2</span><span class="p">)</span><span class="w"> </span><span class="p">{</span>
 <a id="__codelineno-6-3" name="__codelineno-6-3" href="#__codelineno-6-3"></a><span class="w">    </span><span class="c1">// 当放置完所有行时，记录解</span>
 <a id="__codelineno-6-4" name="__codelineno-6-4" href="#__codelineno-6-4"></a><span class="w">    </span><span class="k">if</span><span class="w"> </span><span class="p">(</span><span class="nx">row</span><span class="w"> </span><span class="o">===</span><span class="w"> </span><span class="nx">n</span><span class="p">)</span><span class="w"> </span><span class="p">{</span>
@@ -3916,7 +3886,7 @@
 <a id="__codelineno-6-24" name="__codelineno-6-24" href="#__codelineno-6-24"></a><span class="w">    </span><span class="p">}</span>
 <a id="__codelineno-6-25" name="__codelineno-6-25" href="#__codelineno-6-25"></a><span class="p">}</span>
 <a id="__codelineno-6-26" name="__codelineno-6-26" href="#__codelineno-6-26"></a>
-<a id="__codelineno-6-27" name="__codelineno-6-27" href="#__codelineno-6-27"></a><span class="cm">/* 求解 N 皇后 */</span>
+<a id="__codelineno-6-27" name="__codelineno-6-27" href="#__codelineno-6-27"></a><span class="cm">/* 求解 n 皇后 */</span>
 <a id="__codelineno-6-28" name="__codelineno-6-28" href="#__codelineno-6-28"></a><span class="kd">function</span><span class="w"> </span><span class="nx">nQueens</span><span class="p">(</span><span class="nx">n</span><span class="p">)</span><span class="w"> </span><span class="p">{</span>
 <a id="__codelineno-6-29" name="__codelineno-6-29" href="#__codelineno-6-29"></a><span class="w">    </span><span class="c1">// 初始化 n*n 大小的棋盘，其中 &#39;Q&#39; 代表皇后，&#39;#&#39; 代表空位</span>
 <a id="__codelineno-6-30" name="__codelineno-6-30" href="#__codelineno-6-30"></a><span class="w">    </span><span class="kd">const</span><span class="w"> </span><span class="nx">state</span><span class="w"> </span><span class="o">=</span><span class="w"> </span><span class="nb">Array</span><span class="p">.</span><span class="kr">from</span><span class="p">({</span><span class="w"> </span><span class="nx">length</span><span class="o">:</span><span class="w"> </span><span class="nx">n</span><span class="w"> </span><span class="p">},</span><span class="w"> </span><span class="p">()</span><span class="w"> </span><span class="p">=&gt;</span><span class="w"> </span><span class="nb">Array</span><span class="p">(</span><span class="nx">n</span><span class="p">).</span><span class="nx">fill</span><span class="p">(</span><span class="s1">&#39;#&#39;</span><span class="p">));</span>
@@ -3931,7 +3901,7 @@
 </code></pre></div>
 </div>
 <div class="tabbed-block">
-<div class="highlight"><span class="filename">n_queens.ts</span><pre><span></span><code><a id="__codelineno-7-1" name="__codelineno-7-1" href="#__codelineno-7-1"></a><span class="cm">/* 回溯算法：N 皇后 */</span>
+<div class="highlight"><span class="filename">n_queens.ts</span><pre><span></span><code><a id="__codelineno-7-1" name="__codelineno-7-1" href="#__codelineno-7-1"></a><span class="cm">/* 回溯算法：n 皇后 */</span>
 <a id="__codelineno-7-2" name="__codelineno-7-2" href="#__codelineno-7-2"></a><span class="kd">function</span><span class="w"> </span><span class="nx">backtrack</span><span class="p">(</span>
 <a id="__codelineno-7-3" name="__codelineno-7-3" href="#__codelineno-7-3"></a><span class="w">    </span><span class="nx">row</span><span class="o">:</span><span class="w"> </span><span class="kt">number</span><span class="p">,</span>
 <a id="__codelineno-7-4" name="__codelineno-7-4" href="#__codelineno-7-4"></a><span class="w">    </span><span class="nx">n</span><span class="o">:</span><span class="w"> </span><span class="kt">number</span><span class="p">,</span>
@@ -3965,7 +3935,7 @@
 <a id="__codelineno-7-32" name="__codelineno-7-32" href="#__codelineno-7-32"></a><span class="w">    </span><span class="p">}</span>
 <a id="__codelineno-7-33" name="__codelineno-7-33" href="#__codelineno-7-33"></a><span class="p">}</span>
 <a id="__codelineno-7-34" name="__codelineno-7-34" href="#__codelineno-7-34"></a>
-<a id="__codelineno-7-35" name="__codelineno-7-35" href="#__codelineno-7-35"></a><span class="cm">/* 求解 N 皇后 */</span>
+<a id="__codelineno-7-35" name="__codelineno-7-35" href="#__codelineno-7-35"></a><span class="cm">/* 求解 n 皇后 */</span>
 <a id="__codelineno-7-36" name="__codelineno-7-36" href="#__codelineno-7-36"></a><span class="kd">function</span><span class="w"> </span><span class="nx">nQueens</span><span class="p">(</span><span class="nx">n</span><span class="o">:</span><span class="w"> </span><span class="kt">number</span><span class="p">)</span><span class="o">:</span><span class="w"> </span><span class="kt">string</span><span class="p">[][][]</span><span class="w"> </span><span class="p">{</span>
 <a id="__codelineno-7-37" name="__codelineno-7-37" href="#__codelineno-7-37"></a><span class="w">    </span><span class="c1">// 初始化 n*n 大小的棋盘，其中 &#39;Q&#39; 代表皇后，&#39;#&#39; 代表空位</span>
 <a id="__codelineno-7-38" name="__codelineno-7-38" href="#__codelineno-7-38"></a><span class="w">    </span><span class="kd">const</span><span class="w"> </span><span class="nx">state</span><span class="w"> </span><span class="o">=</span><span class="w"> </span><span class="nb">Array</span><span class="p">.</span><span class="kr">from</span><span class="p">({</span><span class="w"> </span><span class="nx">length</span><span class="o">:</span><span class="w"> </span><span class="kt">n</span><span class="w"> </span><span class="p">},</span><span class="w"> </span><span class="p">()</span><span class="w"> </span><span class="p">=&gt;</span><span class="w"> </span><span class="nb">Array</span><span class="p">(</span><span class="nx">n</span><span class="p">).</span><span class="nx">fill</span><span class="p">(</span><span class="s1">&#39;#&#39;</span><span class="p">));</span>
@@ -3980,7 +3950,7 @@
 </code></pre></div>
 </div>
 <div class="tabbed-block">
-<div class="highlight"><span class="filename">n_queens.dart</span><pre><span></span><code><a id="__codelineno-8-1" name="__codelineno-8-1" href="#__codelineno-8-1"></a><span class="cm">/* 回溯算法：N 皇后 */</span>
+<div class="highlight"><span class="filename">n_queens.dart</span><pre><span></span><code><a id="__codelineno-8-1" name="__codelineno-8-1" href="#__codelineno-8-1"></a><span class="cm">/* 回溯算法：n 皇后 */</span>
 <a id="__codelineno-8-2" name="__codelineno-8-2" href="#__codelineno-8-2"></a><span class="kt">void</span><span class="w"> </span><span class="n">backtrack</span><span class="p">(</span>
 <a id="__codelineno-8-3" name="__codelineno-8-3" href="#__codelineno-8-3"></a><span class="w">  </span><span class="kt">int</span><span class="w"> </span><span class="n">row</span><span class="p">,</span>
 <a id="__codelineno-8-4" name="__codelineno-8-4" href="#__codelineno-8-4"></a><span class="w">  </span><span class="kt">int</span><span class="w"> </span><span class="n">n</span><span class="p">,</span>
@@ -4022,7 +3992,7 @@
 <a id="__codelineno-8-40" name="__codelineno-8-40" href="#__codelineno-8-40"></a><span class="w">  </span><span class="p">}</span>
 <a id="__codelineno-8-41" name="__codelineno-8-41" href="#__codelineno-8-41"></a><span class="p">}</span>
 <a id="__codelineno-8-42" name="__codelineno-8-42" href="#__codelineno-8-42"></a>
-<a id="__codelineno-8-43" name="__codelineno-8-43" href="#__codelineno-8-43"></a><span class="cm">/* 求解 N 皇后 */</span>
+<a id="__codelineno-8-43" name="__codelineno-8-43" href="#__codelineno-8-43"></a><span class="cm">/* 求解 n 皇后 */</span>
 <a id="__codelineno-8-44" name="__codelineno-8-44" href="#__codelineno-8-44"></a><span class="n">List</span><span class="o">&lt;</span><span class="n">List</span><span class="o">&lt;</span><span class="n">List</span><span class="o">&lt;</span><span class="kt">String</span><span class="o">&gt;&gt;&gt;</span><span class="w"> </span><span class="n">nQueens</span><span class="p">(</span><span class="kt">int</span><span class="w"> </span><span class="n">n</span><span class="p">)</span><span class="w"> </span><span class="p">{</span>
 <a id="__codelineno-8-45" name="__codelineno-8-45" href="#__codelineno-8-45"></a><span class="w">  </span><span class="c1">// 初始化 n*n 大小的棋盘，其中 &#39;Q&#39; 代表皇后，&#39;#&#39; 代表空位</span>
 <a id="__codelineno-8-46" name="__codelineno-8-46" href="#__codelineno-8-46"></a><span class="w">  </span><span class="n">List</span><span class="o">&lt;</span><span class="n">List</span><span class="o">&lt;</span><span class="kt">String</span><span class="o">&gt;&gt;</span><span class="w"> </span><span class="n">state</span><span class="w"> </span><span class="o">=</span><span class="w"> </span><span class="n">List</span><span class="p">.</span><span class="n">generate</span><span class="p">(</span><span class="n">n</span><span class="p">,</span><span class="w"> </span><span class="p">(</span><span class="n">index</span><span class="p">)</span><span class="w"> </span><span class="o">=&gt;</span><span class="w"> </span><span class="n">List</span><span class="p">.</span><span class="n">filled</span><span class="p">(</span><span class="n">n</span><span class="p">,</span><span class="w"> </span><span class="s2">&quot;#&quot;</span><span class="p">));</span>
@@ -4038,7 +4008,7 @@
 </code></pre></div>
 </div>
 <div class="tabbed-block">
-<div class="highlight"><span class="filename">n_queens.rs</span><pre><span></span><code><a id="__codelineno-9-1" name="__codelineno-9-1" href="#__codelineno-9-1"></a><span class="cm">/* 回溯算法：N 皇后 */</span>
+<div class="highlight"><span class="filename">n_queens.rs</span><pre><span></span><code><a id="__codelineno-9-1" name="__codelineno-9-1" href="#__codelineno-9-1"></a><span class="cm">/* 回溯算法：n 皇后 */</span>
 <a id="__codelineno-9-2" name="__codelineno-9-2" href="#__codelineno-9-2"></a><span class="k">fn</span> <span class="nf">backtrack</span><span class="p">(</span><span class="n">row</span>: <span class="kt">usize</span><span class="p">,</span><span class="w"> </span><span class="n">n</span>: <span class="kt">usize</span><span class="p">,</span><span class="w"> </span><span class="n">state</span>: <span class="kp">&amp;</span><span class="nc">mut</span><span class="w"> </span><span class="nb">Vec</span><span class="o">&lt;</span><span class="nb">Vec</span><span class="o">&lt;</span><span class="nb">String</span><span class="o">&gt;&gt;</span><span class="p">,</span><span class="w"> </span><span class="n">res</span>: <span class="kp">&amp;</span><span class="nc">mut</span><span class="w"> </span><span class="nb">Vec</span><span class="o">&lt;</span><span class="nb">Vec</span><span class="o">&lt;</span><span class="nb">Vec</span><span class="o">&lt;</span><span class="nb">String</span><span class="o">&gt;&gt;&gt;</span><span class="p">,</span>
 <a id="__codelineno-9-3" name="__codelineno-9-3" href="#__codelineno-9-3"></a><span class="w">    </span><span class="n">cols</span>: <span class="kp">&amp;</span><span class="nc">mut</span><span class="w"> </span><span class="p">[</span><span class="kt">bool</span><span class="p">],</span><span class="w"> </span><span class="n">diags1</span>: <span class="kp">&amp;</span><span class="nc">mut</span><span class="w"> </span><span class="p">[</span><span class="kt">bool</span><span class="p">],</span><span class="w"> </span><span class="n">diags2</span>: <span class="kp">&amp;</span><span class="nc">mut</span><span class="w"> </span><span class="p">[</span><span class="kt">bool</span><span class="p">])</span><span class="w"> </span><span class="p">{</span>
 <a id="__codelineno-9-4" name="__codelineno-9-4" href="#__codelineno-9-4"></a><span class="w">    </span><span class="c1">// 当放置完所有行时，记录解</span>
@@ -4069,7 +4039,7 @@
 <a id="__codelineno-9-29" name="__codelineno-9-29" href="#__codelineno-9-29"></a><span class="w">    </span><span class="p">}</span>
 <a id="__codelineno-9-30" name="__codelineno-9-30" href="#__codelineno-9-30"></a><span class="p">}</span>
 <a id="__codelineno-9-31" name="__codelineno-9-31" href="#__codelineno-9-31"></a>
-<a id="__codelineno-9-32" name="__codelineno-9-32" href="#__codelineno-9-32"></a><span class="cm">/* 求解 N 皇后 */</span>
+<a id="__codelineno-9-32" name="__codelineno-9-32" href="#__codelineno-9-32"></a><span class="cm">/* 求解 n 皇后 */</span>
 <a id="__codelineno-9-33" name="__codelineno-9-33" href="#__codelineno-9-33"></a><span class="k">fn</span> <span class="nf">n_queens</span><span class="p">(</span><span class="n">n</span>: <span class="kt">usize</span><span class="p">)</span><span class="w"> </span>-&gt; <span class="nb">Vec</span><span class="o">&lt;</span><span class="nb">Vec</span><span class="o">&lt;</span><span class="nb">Vec</span><span class="o">&lt;</span><span class="nb">String</span><span class="o">&gt;&gt;&gt;</span><span class="w"> </span><span class="p">{</span>
 <a id="__codelineno-9-34" name="__codelineno-9-34" href="#__codelineno-9-34"></a><span class="w">    </span><span class="c1">// 初始化 n*n 大小的棋盘，其中 &#39;Q&#39; 代表皇后，&#39;#&#39; 代表空位</span>
 <a id="__codelineno-9-35" name="__codelineno-9-35" href="#__codelineno-9-35"></a><span class="w">    </span><span class="kd">let</span><span class="w"> </span><span class="k">mut</span><span class="w"> </span><span class="n">state</span>: <span class="nb">Vec</span><span class="o">&lt;</span><span class="nb">Vec</span><span class="o">&lt;</span><span class="nb">String</span><span class="o">&gt;&gt;</span><span class="w"> </span><span class="o">=</span><span class="w"> </span><span class="nb">Vec</span>::<span class="n">new</span><span class="p">();</span>
@@ -4092,7 +4062,7 @@
 </code></pre></div>
 </div>
 <div class="tabbed-block">
-<div class="highlight"><span class="filename">n_queens.c</span><pre><span></span><code><a id="__codelineno-10-1" name="__codelineno-10-1" href="#__codelineno-10-1"></a><span class="cm">/* 回溯算法：N 皇后 */</span>
+<div class="highlight"><span class="filename">n_queens.c</span><pre><span></span><code><a id="__codelineno-10-1" name="__codelineno-10-1" href="#__codelineno-10-1"></a><span class="cm">/* 回溯算法：n 皇后 */</span>
 <a id="__codelineno-10-2" name="__codelineno-10-2" href="#__codelineno-10-2"></a><span class="kt">void</span><span class="w"> </span><span class="nf">backtrack</span><span class="p">(</span><span class="kt">int</span><span class="w"> </span><span class="n">row</span><span class="p">,</span><span class="w"> </span><span class="kt">int</span><span class="w"> </span><span class="n">n</span><span class="p">,</span><span class="w"> </span><span class="kt">char</span><span class="w"> </span><span class="n">state</span><span class="p">[</span><span class="n">MAX_SIZE</span><span class="p">][</span><span class="n">MAX_SIZE</span><span class="p">],</span><span class="w"> </span><span class="kt">char</span><span class="w"> </span><span class="o">***</span><span class="n">res</span><span class="p">,</span><span class="w"> </span><span class="kt">int</span><span class="w"> </span><span class="o">*</span><span class="n">resSize</span><span class="p">,</span><span class="w"> </span><span class="kt">bool</span><span class="w"> </span><span class="n">cols</span><span class="p">[</span><span class="n">MAX_SIZE</span><span class="p">],</span>
 <a id="__codelineno-10-3" name="__codelineno-10-3" href="#__codelineno-10-3"></a><span class="w">               </span><span class="kt">bool</span><span class="w"> </span><span class="n">diags1</span><span class="p">[</span><span class="mi">2</span><span class="w"> </span><span class="o">*</span><span class="w"> </span><span class="n">MAX_SIZE</span><span class="w"> </span><span class="o">-</span><span class="w"> </span><span class="mi">1</span><span class="p">],</span><span class="w"> </span><span class="kt">bool</span><span class="w"> </span><span class="n">diags2</span><span class="p">[</span><span class="mi">2</span><span class="w"> </span><span class="o">*</span><span class="w"> </span><span class="n">MAX_SIZE</span><span class="w"> </span><span class="o">-</span><span class="w"> </span><span class="mi">1</span><span class="p">])</span><span class="w"> </span><span class="p">{</span>
 <a id="__codelineno-10-4" name="__codelineno-10-4" href="#__codelineno-10-4"></a><span class="w">    </span><span class="c1">// 当放置完所有行时，记录解</span>
@@ -4124,7 +4094,7 @@
 <a id="__codelineno-10-30" name="__codelineno-10-30" href="#__codelineno-10-30"></a><span class="w">    </span><span class="p">}</span>
 <a id="__codelineno-10-31" name="__codelineno-10-31" href="#__codelineno-10-31"></a><span class="p">}</span>
 <a id="__codelineno-10-32" name="__codelineno-10-32" href="#__codelineno-10-32"></a>
-<a id="__codelineno-10-33" name="__codelineno-10-33" href="#__codelineno-10-33"></a><span class="cm">/* 求解 N 皇后 */</span>
+<a id="__codelineno-10-33" name="__codelineno-10-33" href="#__codelineno-10-33"></a><span class="cm">/* 求解 n 皇后 */</span>
 <a id="__codelineno-10-34" name="__codelineno-10-34" href="#__codelineno-10-34"></a><span class="kt">char</span><span class="w"> </span><span class="o">***</span><span class="nf">nQueens</span><span class="p">(</span><span class="kt">int</span><span class="w"> </span><span class="n">n</span><span class="p">,</span><span class="w"> </span><span class="kt">int</span><span class="w"> </span><span class="o">*</span><span class="n">returnSize</span><span class="p">)</span><span class="w"> </span><span class="p">{</span>
 <a id="__codelineno-10-35" name="__codelineno-10-35" href="#__codelineno-10-35"></a><span class="w">    </span><span class="kt">char</span><span class="w"> </span><span class="n">state</span><span class="p">[</span><span class="n">MAX_SIZE</span><span class="p">][</span><span class="n">MAX_SIZE</span><span class="p">];</span>
 <a id="__codelineno-10-36" name="__codelineno-10-36" href="#__codelineno-10-36"></a><span class="w">    </span><span class="c1">// 初始化 n*n 大小的棋盘，其中 &#39;Q&#39; 代表皇后，&#39;#&#39; 代表空位</span>

chapter_computational_complexity/performance_evaluation/index.html

@@ -3525,7 +3525,7 @@
 <li><strong>时间效率</strong>：算法运行速度的快慢。</li>
 <li><strong>空间效率</strong>：算法占用内存空间的大小。</li>
 </ul>
-<p>简而言之，<strong>我们的目标是设计“既快又省”的数据结构与算法</strong>。而有效地评估算法效率至关重要，因为只有这样我们才能将各种算法进行对比，进而指导算法设计与优化过程。</p>
+<p>简而言之，<strong>我们的目标是设计“既快又省”的数据结构与算法</strong>。而有效地评估算法效率至关重要，因为只有这样，我们才能将各种算法进行对比，进而指导算法设计与优化过程。</p>
 <p>效率评估方法主要分为两种：实际测试、理论估算。</p>
 <h2 id="211">2.1.1 &nbsp; 实际测试<a class="headerlink" href="#211" title="Permanent link">&para;</a></h2>
 <p>假设我们现在有算法 <code>A</code> 和算法 <code>B</code> ，它们都能解决同一问题，现在需要对比这两个算法的效率。最直接的方法是找一台计算机，运行这两个算法，并监控记录它们的运行时间和内存占用情况。这种评估方式能够反映真实情况，但也存在较大的局限性。</p>

chapter_data_structure/number_encoding/index.html

@@ -3585,7 +3585,7 @@
 <p>补码的设计非常精妙，因篇幅关系我们就先介绍到这里，建议有兴趣的读者进一步深入了解。</p>
 <h2 id="332">3.3.2 &nbsp; 浮点数编码<a class="headerlink" href="#332" title="Permanent link">&para;</a></h2>
 <p>细心的你可能会发现：<code>int</code> 和 <code>float</code> 长度相同，都是 4 字节 ，但为什么 <code>float</code> 的取值范围远大于 <code>int</code> ？这非常反直觉，因为按理说 <code>float</code> 需要表示小数，取值范围应该变小才对。</p>
-<p>实际上，<strong>这是因为浮点数 <code>float</code> 采用了不同的表示方式</strong>。记一个 32 位长度的二进制数为：</p>
+<p>实际上，<strong>这是因为浮点数 <code>float</code> 采用了不同的表示方式</strong>。记一个 32 比特长度的二进制数为：</p>
 <div class="arithmatex">\[
 b_{31} b_{30} b_{29} \ldots b_2 b_1 b_0
 \]</div>
@@ -3618,7 +3618,7 @@ b_{31} b_{30} b_{29} \ldots b_2 b_1 b_0
 \text { val } = (-1)^0 \times 2^{124 - 127} \times (1 + 0.375) = 0.171875
 \]</div>
 <p>现在我们可以回答最初的问题：<strong><code>float</code> 的表示方式包含指数位，导致其取值范围远大于 <code>int</code></strong> 。根据以上计算，<code>float</code> 可表示的最大正数为 <span class="arithmatex">\(2^{254 - 127} \times (2 - 2^{-23}) \approx 3.4 \times 10^{38}\)</span> ，切换符号位便可得到最小负数。</p>
-<p><strong>尽管浮点数 <code>float</code> 扩展了取值范围，但其副作用是牺牲了精度</strong>。整数类型 <code>int</code> 将全部 32 位用于表示数字，数字是均匀分布的；而由于指数位的存在，浮点数 <code>float</code> 的数值越大，相邻两个数字之间的差值就会趋向越大。</p>
+<p><strong>尽管浮点数 <code>float</code> 扩展了取值范围，但其副作用是牺牲了精度</strong>。整数类型 <code>int</code> 将全部 32 比特用于表示数字，数字是均匀分布的；而由于指数位的存在，浮点数 <code>float</code> 的数值越大，相邻两个数字之间的差值就会趋向越大。</p>
 <p>如表 3-2 所示，指数位 <span class="arithmatex">\(E = 0\)</span> 和 <span class="arithmatex">\(E = 255\)</span> 具有特殊含义，<strong>用于表示零、无穷大、<span class="arithmatex">\(\mathrm{NaN}\)</span> 等</strong>。</p>
 <p align="center"> 表 3-2 &nbsp; 指数位含义 </p>
 

chapter_data_structure/summary/index.html

@@ -3521,7 +3521,7 @@
 <li>常见的逻辑结构包括线性、树状和网状等。通常我们根据逻辑结构将数据结构分为线性（数组、链表、栈、队列）和非线性（树、图、堆）两种。哈希表的实现可能同时包含线性数据结构和非线性数据结构。</li>
 <li>当程序运行时，数据被存储在计算机内存中。每个内存空间都拥有对应的内存地址，程序通过这些内存地址访问数据。</li>
 <li>物理结构主要分为连续空间存储（数组）和分散空间存储（链表）。所有数据结构都是由数组、链表或两者的组合实现的。</li>
-<li>计算机中的基本数据类型包括整数 <code>byte</code>、<code>short</code>、<code>int</code>、<code>long</code> ，浮点数 <code>float</code>、<code>double</code> ，字符 <code>char</code> 和布尔 <code>boolean</code> 。它们的取值范围取决于占用空间大小和表示方式。</li>
+<li>计算机中的基本数据类型包括整数 <code>byte</code>、<code>short</code>、<code>int</code>、<code>long</code> ，浮点数 <code>float</code>、<code>double</code> ，字符 <code>char</code> 和布尔 <code>bool</code> 。它们的取值范围取决于占用空间大小和表示方式。</li>
 <li>原码、反码和补码是在计算机中编码数字的三种方法，它们之间可以相互转换。整数的原码的最高位是符号位，其余位是数字的值。</li>
 <li>整数在计算机中是以补码的形式存储的。在补码表示下，计算机可以对正数和负数的加法一视同仁，不需要为减法操作单独设计特殊的硬件电路，并且不存在正负零歧义的问题。</li>
 <li>浮点数的编码由 1 位符号位、8 位指数位和 23 位分数位构成。由于存在指数位，因此浮点数的取值范围远大于整数，代价是牺牲了精度。</li>

chapter_divide_and_conquer/build_binary_tree_problem/index.html

@@ -3553,7 +3553,7 @@
 <h1 id="123">12.3 &nbsp; 构建二叉树问题<a class="headerlink" href="#123" title="Permanent link">&para;</a></h1>
 <div class="admonition question">
 <p class="admonition-title">Question</p>
-<p>给定一棵二叉树的前序遍历 <code>preorder</code> 和中序遍历 <code>inorder</code> ，请从中构建二叉树，返回二叉树的根节点。假设二叉树中没有值重复的节点，如图 12-5 所示。</p>
+<p>给定一棵二叉树的前序遍历 <code>preorder</code> 和中序遍历 <code>inorder</code> ，请从中构建二叉树，返回二叉树的根节点。假设二叉树中没有值重复的节点（如图 12-5 所示）。</p>
 </div>
 <p><a class="glightbox" href="../build_binary_tree_problem.assets/build_tree_example.png" data-type="image" data-width="100%" data-height="auto" data-desc-position="bottom"><img alt="构建二叉树的示例数据" class="animation-figure" src="../build_binary_tree_problem.assets/build_tree_example.png" /></a></p>
 <p align="center"> 图 12-5 &nbsp; 构建二叉树的示例数据 </p>

chapter_dynamic_programming/unbounded_knapsack_problem/index.html

@@ -2990,11 +2990,11 @@
         <li class="md-nav__item">
   <a href="#1451" class="md-nav__link">
     <span class="md-ellipsis">
-      14.5.1 &nbsp; 完全背包
+      14.5.1 &nbsp; 完全背包问题
     </span>
   </a>
   
-    <nav class="md-nav" aria-label="14.5.1   完全背包">
+    <nav class="md-nav" aria-label="14.5.1   完全背包问题">
       <ul class="md-nav__list">
         
           <li class="md-nav__item">
@@ -3571,11 +3571,11 @@
         <li class="md-nav__item">
   <a href="#1451" class="md-nav__link">
     <span class="md-ellipsis">
-      14.5.1 &nbsp; 完全背包
+      14.5.1 &nbsp; 完全背包问题
     </span>
   </a>
   
-    <nav class="md-nav" aria-label="14.5.1   完全背包">
+    <nav class="md-nav" aria-label="14.5.1   完全背包问题">
       <ul class="md-nav__list">
         
           <li class="md-nav__item">
@@ -3732,7 +3732,7 @@
 <!-- Page content -->
 <h1 id="145">14.5 &nbsp; 完全背包问题<a class="headerlink" href="#145" title="Permanent link">&para;</a></h1>
 <p>在本节中，我们先求解另一个常见的背包问题：完全背包，再了解它的一种特例：零钱兑换。</p>
-<h2 id="1451">14.5.1 &nbsp; 完全背包<a class="headerlink" href="#1451" title="Permanent link">&para;</a></h2>
+<h2 id="1451">14.5.1 &nbsp; 完全背包问题<a class="headerlink" href="#1451" title="Permanent link">&para;</a></h2>
 <div class="admonition question">
 <p class="admonition-title">Question</p>
 <p>给定 <span class="arithmatex">\(n\)</span> 个物品，第 <span class="arithmatex">\(i\)</span> 个物品的重量为 <span class="arithmatex">\(wgt[i-1]\)</span>、价值为 <span class="arithmatex">\(val[i-1]\)</span> ，和一个容量为 <span class="arithmatex">\(cap\)</span> 的背包。<strong>每个物品可以重复选取</strong>，问在限定背包容量下能放入物品的最大价值。示例如图 14-22 所示。</p>

chapter_graph/graph/index.html

@@ -1877,7 +1877,7 @@
         <li class="md-nav__item">
   <a href="#911" class="md-nav__link">
     <span class="md-ellipsis">
-      9.1.1 &nbsp; 图常见类型与术语
+      9.1.1 &nbsp; 图的常见类型与术语
     </span>
   </a>
   
@@ -3496,7 +3496,7 @@
         <li class="md-nav__item">
   <a href="#911" class="md-nav__link">
     <span class="md-ellipsis">
-      9.1.1 &nbsp; 图常见类型与术语
+      9.1.1 &nbsp; 图的常见类型与术语
     </span>
   </a>
   
@@ -3593,7 +3593,7 @@ G &amp; = \{ V, E \} \newline
 <p><a class="glightbox" href="../graph.assets/linkedlist_tree_graph.png" data-type="image" data-width="100%" data-height="auto" data-desc-position="bottom"><img alt="链表、树、图之间的关系" class="animation-figure" src="../graph.assets/linkedlist_tree_graph.png" /></a></p>
 <p align="center"> 图 9-1 &nbsp; 链表、树、图之间的关系 </p>
 
-<h2 id="911">9.1.1 &nbsp; 图常见类型与术语<a class="headerlink" href="#911" title="Permanent link">&para;</a></h2>
+<h2 id="911">9.1.1 &nbsp; 图的常见类型与术语<a class="headerlink" href="#911" title="Permanent link">&para;</a></h2>
 <p>根据边是否具有方向，可分为「无向图 undirected graph」和「有向图 directed graph」，如图 9-2 所示。</p>
 <ul>
 <li>在无向图中，边表示两顶点之间的“双向”连接关系，例如微信或 QQ 中的“好友关系”。</li>

chapter_graph/graph_operations/index.html

@@ -3532,7 +3532,7 @@
 
 
 <!-- Page content -->
-<h1 id="92">9.2 &nbsp; 图基础操作<a class="headerlink" href="#92" title="Permanent link">&para;</a></h1>
+<h1 id="92">9.2 &nbsp; 图的基础操作<a class="headerlink" href="#92" title="Permanent link">&para;</a></h1>
 <p>图的基础操作可分为对“边”的操作和对“顶点”的操作。在“邻接矩阵”和“邻接表”两种表示方法下，实现方式有所不同。</p>
 <h2 id="921">9.2.1 &nbsp; 基于邻接矩阵的实现<a class="headerlink" href="#921" title="Permanent link">&para;</a></h2>
 <p>给定一个顶点数量为 <span class="arithmatex">\(n\)</span> 的无向图，则各种操作的实现方式如图 9-7 所示。</p>

chapter_preface/about_the_book/index.html

@@ -3559,12 +3559,12 @@
 
 <h2 id="013">0.1.3 &nbsp; 致谢<a class="headerlink" href="#013" title="Permanent link">&para;</a></h2>
 <p>本书在开源社区众多贡献者的共同努力下不断完善。感谢每一位投入时间与精力的撰稿人，他们是（按照 GitHub 自动生成的顺序）：krahets、codingonion、nuomi1、Gonglja、Reanon、justin-tse、danielsss、hpstory、S-N-O-R-L-A-X、night-cruise、msk397、gvenusleo、RiverTwilight、gyt95、zhuoqinyue、Zuoxun、Xia-Sang、mingXta、FangYuan33、GN-Yu、IsChristina、xBLACKICEx、guowei-gong、Cathay-Chen、mgisr、JoseHung、qualifier1024、pengchzn、Guanngxu、longsizhuo、L-Super、what-is-me、yuan0221、lhxsm、Slone123c、WSL0809、longranger2、theNefelibatas、xiongsp、JeffersonHuang、hongyun-robot、K3v123、yuelinxin、a16su、gaofer、malone6、Wonderdch、xjr7670、DullSword、Horbin-Magician、NI-SW、reeswell、XC-Zero、XiaChuerwu、yd-j、iron-irax、huawuque404、MolDuM、Nigh、KorsChen、foursevenlove、52coder、bubble9um、youshaoXG、curly210102、gltianwen、fanchenggang、Transmigration-zhou、FloranceYeh、FreddieLi、ShiMaRing、lipusheng、Javesun99、JackYang-hellobobo、shanghai-Jerry、0130w、Keynman、psychelzh、logan-qiu、ZnYang2018、MwumLi、1ch0、Phoenix0415、qingpeng9802、Richard-Zhang1019、QiLOL、Suremotoo、Turing-1024-Lee、Evilrabbit520、GaochaoZhu、ZJKung、linzeyan、hezhizhen、ZongYangL、beintentional、czruby、coderlef、dshlstarr、szu17dmy、fbigm、gledfish、hts0000、boloboloda、iStig、jiaxianhua、wenjianmin、keshida、kilikilikid、lclc6、lwbaptx、liuxjerry、lucaswangdev、lyl625760、chadyi、noobcodemaker、selear、siqyka、syd168、4yDX3906、tao363、wangwang105、weibk、yabo083、yi427、yishangzhang、zhouLion、baagod、ElaBosak233、xb534、luluxia、yanedie、thomasq0 和 YangXuanyi。</p>
-<p>本书的代码审阅工作由 codingonion, Gonglja、gvenusleo、hpstory、justin‐tse、krahets、night-cruise、nuomi1 和 Reanon 完成（按照首字母顺序排列）。感谢他们付出的时间与精力，正是他们确保了各语言代码的规范与统一。</p>
+<p>本书的代码审阅工作由 codingonion、Gonglja、gvenusleo、hpstory、justin-tse、krahets、night-cruise、nuomi1 和 Reanon 完成（按照首字母顺序排列）。感谢他们付出的时间与精力，正是他们确保了各语言代码的规范与统一。</p>
 <p>在本书的创作过程中，我得到了许多人的帮助。</p>
 <ul>
 <li>感谢我在公司的导师李汐博士，在一次畅谈中你鼓励我“快行动起来”，坚定了我写这本书的决心；</li>
 <li>感谢我的女朋友泡泡作为本书的首位读者，从算法小白的角度提出许多宝贵建议，使得本书更适合新手阅读；</li>
-<li>感谢腾宝、琦宝、飞宝为本书起了一个富有创意的名字，唤起大家写下第一行代码 "Hello World!" 的美好回忆；</li>
+<li>感谢腾宝、琦宝、飞宝为本书起了一个富有创意的名字，唤起大家写下第一行代码“Hello World!”的美好回忆；</li>
 <li>感谢校铨在知识产权方面提供的专业帮助，这对本开源书的完善起到了重要作用；</li>
 <li>感谢苏潼为本书设计了精美的封面和 logo ，并在我的强迫症的驱使下多次耐心修改；</li>
 <li>感谢 @squidfunk 提供的排版建议，以及他开发的开源文档主题 <a href="https://github.com/squidfunk/mkdocs-material/tree/master">Material-for-MkDocs</a> 。</li>

chapter_preface/suggestions/index.html

@@ -3718,7 +3718,7 @@
 </div>
 <h2 id="022">0.2.2 &nbsp; 在动画图解中高效学习<a class="headerlink" href="#022" title="Permanent link">&para;</a></h2>
 <p>相较于文字，视频和图片具有更高的信息密度和结构化程度，更易于理解。在本书中，<strong>重点和难点知识将主要通过动画以图解形式展示</strong>，而文字则作为解释与补充。</p>
-<p>如果你在阅读本书时，发现某段内容提供了如图 0-2 所示的动画或图解，<strong>请以图为主、以文字为辅</strong>，综合两者来理解内容。</p>
+<p>如果你在阅读本书时，发现某段内容提供了如图 0-2 所示的动画图解，<strong>请以图为主、以文字为辅</strong>，综合两者来理解内容。</p>
 <p><a class="glightbox" href="../../index.assets/animation.gif" data-type="image" data-width="100%" data-height="auto" data-desc-position="bottom"><img alt="动画图解示例" class="animation-figure" src="../../index.assets/animation.gif" /></a></p>
 <p align="center"> 图 0-2 &nbsp; 动画图解示例 </p>
 

chapter_searching/binary_search/index.html

@@ -3830,7 +3830,7 @@
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 <div style="margin-top: 5px;"><a href="https://pythontutor.com/iframe-embed.html#code=def%20binary_search%28nums%3A%20list%5Bint%5D,%20target%3A%20int%29%20-%3E%20int%3A%0A%20%20%20%20%22%22%22%E4%BA%8C%E5%88%86%E6%9F%A5%E6%89%BE%EF%BC%88%E5%8F%8C%E9%97%AD%E5%8C%BA%E9%97%B4%EF%BC%89%22%22%22%0A%20%20%20%20%23%20%E5%88%9D%E5%A7%8B%E5%8C%96%E5%8F%8C%E9%97%AD%E5%8C%BA%E9%97%B4%20%5B0,%20n-1%5D%20%EF%BC%8C%E5%8D%B3%20i,%20j%20%E5%88%86%E5%88%AB%E6%8C%87%E5%90%91%E6%95%B0%E7%BB%84%E9%A6%96%E5%85%83%E7%B4%A0%E3%80%81%E5%B0%BE%E5%85%83%E7%B4%A0%0A%20%20%20%20i,%20j%20%3D%200,%20len%28nums%29%20-%201%0A%20%20%20%20%23%20%E5%BE%AA%E7%8E%AF%EF%BC%8C%E5%BD%93%E6%90%9C%E7%B4%A2%E5%8C%BA%E9%97%B4%E4%B8%BA%E7%A9%BA%E6%97%B6%E8%B7%B3%E5%87%BA%EF%BC%88%E5%BD%93%20i%20%3E%20j%20%E6%97%B6%E4%B8%BA%E7%A9%BA%EF%BC%89%0A%20%20%20%20while%20i%20%3C%3D%20j%3A%0A%20%20%20%20%20%20%20%20%23%20%E7%90%86%E8%AE%BA%E4%B8%8A%20Python%20%E7%9A%84%E6%95%B0%E5%AD%97%E5%8F%AF%E4%BB%A5%E6%97%A0%E9%99%90%E5%A4%A7%EF%BC%88%E5%8F%96%E5%86%B3%E4%BA%8E%E5%86%85%E5%AD%98%E5%A4%A7%E5%B0%8F%EF%BC%89%EF%BC%8C%E6%97%A0%E9%A1%BB%E8%80%83%E8%99%91%E5%A4%A7%E6%95%B0%E8%B6%8A%E7%95%8C%E9%97%AE%E9%A2%98%0A%20%20%20%20%20%20%20%20m%20%3D%20%28i%20%2B%20j%29%20//%202%20%20%23%20%E8%AE%A1%E7%AE%97%E4%B8%AD%E7%82%B9%E7%B4%A2%E5%BC%95%20m%0A%20%20%20%20%20%20%20%20if%20nums%5Bm%5D%20%3C%20target%3A%0A%20%20%20%20%20%20%20%20%20%20%20%20i%20%3D%20m%20%2B%201%20%20%23%20%E6%AD%A4%E6%83%85%E5%86%B5%E8%AF%B4%E6%98%8E%20target%20%E5%9C%A8%E5%8C%BA%E9%97%B4%20%5Bm%2B1,%20j%5D%20%E4%B8%AD%0A%20%20%20%20%20%20%20%20elif%20nums%5Bm%5D%20%3E%20target%3A%0A%20%20%20%20%20%20%20%20%20%20%20%20j%20%3D%20m%20-%201%20%20%23%20%E6%AD%A4%E6%83%85%E5%86%B5%E8%AF%B4%E6%98%8E%20target%20%E5%9C%A8%E5%8C%BA%E9%97%B4%20%5Bi,%20m-1%5D%20%E4%B8%AD%0A%20%20%20%20%20%20%20%20else%3A%0A%20%20%20%20%20%20%20%20%20%20%20%20return%20m%20%20%23%20%E6%89%BE%E5%88%B0%E7%9B%AE%E6%A0%87%E5%85%83%E7%B4%A0%EF%BC%8C%E8%BF%94%E5%9B%9E%E5%85%B6%E7%B4%A2%E5%BC%95%0A%20%20%20%20return%20-1%20%20%23%20%E6%9C%AA%E6%89%BE%E5%88%B0%E7%9B%AE%E6%A0%87%E5%85%83%E7%B4%A0%EF%BC%8C%E8%BF%94%E5%9B%9E%20-1%0A%0A%0A%22%22%22Driver%20Code%22%22%22%0Aif%20__name__%20%3D%3D%20%22__main__%22%3A%0A%20%20%20%20target%20%3D%206%0A%20%20%20%20nums%20%3D%20%5B1,%203,%206,%208,%2012,%2015,%2023,%2026,%2031,%2035%5D%0A%0A%20%20%20%20%23%20%E4%BA%8C%E5%88%86%E6%9F%A5%E6%89%BE%EF%BC%88%E5%8F%8C%E9%97%AD%E5%8C%BA%E9%97%B4%EF%BC%89%0A%20%20%20%20index%20%3D%20binary_search%28nums,%20target%29%0A%20%20%20%20print%28%22%E7%9B%AE%E6%A0%87%E5%85%83%E7%B4%A0%206%20%E7%9A%84%E7%B4%A2%E5%BC%95%20%3D%20%22,%20index%29&codeDivHeight=800&codeDivWidth=600&cumulative=false&curInstr=5&heapPrimitives=nevernest&origin=opt-frontend.js&py=311&rawInputLstJSON=%5B%5D&textReferences=false" target="_blank" rel="noopener noreferrer">全屏观看 &gt;</a></div></p>
 </details>
-<p><strong>时间复杂度为 <span class="arithmatex">\(O(\log n)\)</span></strong> ：在二分循环中，区间每轮缩小一半，循环次数为 <span class="arithmatex">\(\log_2 n\)</span> 。</p>
+<p><strong>时间复杂度为 <span class="arithmatex">\(O(\log n)\)</span></strong> ：在二分循环中，区间每轮缩小一半，因此循环次数为 <span class="arithmatex">\(\log_2 n\)</span> 。</p>
 <p><strong>空间复杂度为 <span class="arithmatex">\(O(1)\)</span></strong> ：指针 <span class="arithmatex">\(i\)</span> 和 <span class="arithmatex">\(j\)</span> 使用常数大小空间。</p>
 <h2 id="1011">10.1.1 &nbsp; 区间表示方法<a class="headerlink" href="#1011" title="Permanent link">&para;</a></h2>
 <p>除了上述双闭区间外，常见的区间表示还有“左闭右开”区间，定义为 <span class="arithmatex">\([0, n)\)</span> ，即左边界包含自身，右边界不包含自身。在该表示下，区间 <span class="arithmatex">\([i, j)\)</span> 在 <span class="arithmatex">\(i = j\)</span> 时为空。</p>

chapter_sorting/heap_sort/index.html

@@ -3530,7 +3530,7 @@
 <ol>
 <li>输入数组并建立大顶堆。完成后，最大元素位于堆顶。</li>
 <li>将堆顶元素（第一个元素）与堆底元素（最后一个元素）交换。完成交换后，堆的长度减 <span class="arithmatex">\(1\)</span> ，已排序元素数量加 <span class="arithmatex">\(1\)</span> 。</li>
-<li>从堆顶元素开始，从顶到底执行堆化操作（Sift Down）。完成堆化后，堆的性质得到修复。</li>
+<li>从堆顶元素开始，从顶到底执行堆化操作（sift down）。完成堆化后，堆的性质得到修复。</li>
 <li>循环执行第 <code>2.</code> 步和第 <code>3.</code> 步。循环 <span class="arithmatex">\(n - 1\)</span> 轮后，即可完成数组排序。</li>
 </ol>
 <div class="admonition tip">

chapter_stack_and_queue/stack/index.html

@@ -1266,7 +1266,7 @@
         <li class="md-nav__item">
   <a href="#514" class="md-nav__link">
     <span class="md-ellipsis">
-      5.1.4 &nbsp; 栈典型应用
+      5.1.4 &nbsp; 栈的典型应用
     </span>
   </a>
   
@@ -3556,7 +3556,7 @@
         <li class="md-nav__item">
   <a href="#514" class="md-nav__link">
     <span class="md-ellipsis">
-      5.1.4 &nbsp; 栈典型应用
+      5.1.4 &nbsp; 栈的典型应用
     </span>
   </a>
   
@@ -5259,7 +5259,7 @@
 <p>在初始化列表时，系统会为列表分配“初始容量”，该容量可能超出实际需求；并且，扩容机制通常是按照特定倍率（例如 2 倍）进行扩容的，扩容后的容量也可能超出实际需求。因此，<strong>基于数组实现的栈可能造成一定的空间浪费</strong>。</p>
 <p>然而，由于链表节点需要额外存储指针，<strong>因此链表节点占用的空间相对较大</strong>。</p>
 <p>综上，我们不能简单地确定哪种实现更加节省内存，需要针对具体情况进行分析。</p>
-<h2 id="514">5.1.4 &nbsp; 栈典型应用<a class="headerlink" href="#514" title="Permanent link">&para;</a></h2>
+<h2 id="514">5.1.4 &nbsp; 栈的典型应用<a class="headerlink" href="#514" title="Permanent link">&para;</a></h2>
 <ul>
 <li><strong>浏览器中的后退与前进、软件中的撤销与反撤销</strong>。每当我们打开新的网页，浏览器就会对上一个网页执行入栈，这样我们就可以通过后退操作回到上一个网页。后退操作实际上是在执行出栈。如果要同时支持后退和前进，那么需要两个栈来配合实现。</li>
 <li><strong>程序内存管理</strong>。每次调用函数时，系统都会在栈顶添加一个栈帧，用于记录函数的上下文信息。在递归函数中，向下递推阶段会不断执行入栈操作，而向上回溯阶段则会不断执行出栈操作。</li>

chapter_stack_and_queue/summary/index.html

@@ -3529,7 +3529,7 @@
 <p><strong>Q</strong>：在出栈后，是否需要释放出栈节点的内存？</p>
 <p>如果后续仍需要使用弹出节点，则不需要释放内存。若之后不需要用到，<code>Java</code> 和 <code>Python</code> 等语言拥有自动垃圾回收机制，因此不需要手动释放内存；在 <code>C</code> 和 <code>C++</code> 中需要手动释放内存。</p>
 <p><strong>Q</strong>：双向队列像是两个栈拼接在了一起，它的用途是什么？</p>
-<p>双向队列就像是栈和队列的组合，或两个栈拼在了一起。它表现的是栈 + 队列的逻辑，因此可以实现栈与队列的所有应用，并且更加灵活。</p>
+<p>双向队列就像是栈和队列的组合或两个栈拼在了一起。它表现的是栈 + 队列的逻辑，因此可以实现栈与队列的所有应用，并且更加灵活。</p>
 <p><strong>Q</strong>：撤销（undo）和反撤销（redo）具体是如何实现的？</p>
 <p>使用两个栈，栈 <code>A</code> 用于撤销，栈 <code>B</code> 用于反撤销。</p>
 <ol>

chapter_tree/avl_tree/index.html

@@ -3778,7 +3778,7 @@
 
 <p>1962 年 G. M. Adelson-Velsky 和 E. M. Landis 在论文“An algorithm for the organization of information”中提出了「AVL 树」。论文中详细描述了一系列操作，确保在持续添加和删除节点后，AVL 树不会退化，从而使得各种操作的时间复杂度保持在 <span class="arithmatex">\(O(\log n)\)</span> 级别。换句话说，在需要频繁进行增删查改操作的场景中，AVL 树能始终保持高效的数据操作性能，具有很好的应用价值。</p>
 <h2 id="751-avl">7.5.1 &nbsp; AVL 树常见术语<a class="headerlink" href="#751-avl" title="Permanent link">&para;</a></h2>
-<p>AVL 树既是二叉搜索树也是平衡二叉树，同时满足这两类二叉树的所有性质，因此也被称为「平衡二叉搜索树 balanced binary search tree」。</p>
+<p>AVL 树既是二叉搜索树，也是平衡二叉树，同时满足这两类二叉树的所有性质，因此也被称为「平衡二叉搜索树 balanced binary search tree」。</p>
 <h3 id="1">1. &nbsp; 节点高度<a class="headerlink" href="#1" title="Permanent link">&para;</a></h3>
 <p>由于 AVL 树的相关操作需要获取节点高度，因此我们需要为节点类添加 <code>height</code> 变量：</p>
 <div class="tabbed-set tabbed-alternate" data-tabs="1:12"><input checked="checked" id="__tabbed_1_1" name="__tabbed_1" type="radio" /><input id="__tabbed_1_2" name="__tabbed_1" type="radio" /><input id="__tabbed_1_3" name="__tabbed_1" type="radio" /><input id="__tabbed_1_4" name="__tabbed_1" type="radio" /><input id="__tabbed_1_5" name="__tabbed_1" type="radio" /><input id="__tabbed_1_6" name="__tabbed_1" type="radio" /><input id="__tabbed_1_7" name="__tabbed_1" type="radio" /><input id="__tabbed_1_8" name="__tabbed_1" type="radio" /><input id="__tabbed_1_9" name="__tabbed_1" type="radio" /><input id="__tabbed_1_10" name="__tabbed_1" type="radio" /><input id="__tabbed_1_11" name="__tabbed_1" type="radio" /><input id="__tabbed_1_12" name="__tabbed_1" type="radio" /><div class="tabbed-labels"><label for="__tabbed_1_1">Python</label><label for="__tabbed_1_2">C++</label><label for="__tabbed_1_3">Java</label><label for="__tabbed_1_4">C#</label><label for="__tabbed_1_5">Go</label><label for="__tabbed_1_6">Swift</label><label for="__tabbed_1_7">JS</label><label for="__tabbed_1_8">TS</label><label for="__tabbed_1_9">Dart</label><label for="__tabbed_1_10">Rust</label><label for="__tabbed_1_11">C</label><label for="__tabbed_1_12">Zig</label></div>

index.html

@@ -3540,7 +3540,7 @@
     </a>
 </p>
 
-<p>本书的代码审阅工作由 codingonion、Gonglja、gvenusleo、hpstory、justin‐tse、krahets、night-cruise、nuomi1 和 Reanon 完成（按照首字母顺序排列）。感谢他们付出的时间与精力，正是他们确保了各语言代码的规范与统一。</p>
+<p>本书的代码审阅工作由 codingonion、Gonglja、gvenusleo、hpstory、justin-tse、krahets、night-cruise、nuomi1 和 Reanon 完成（按照首字母顺序排列）。感谢他们付出的时间与精力，正是他们确保了各语言代码的规范与统一。</p>
 <div class="center-table">
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         <tbody>