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@ -6,10 +6,8 @@ package chapter_backtracking
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import "sort"
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type subsetII struct{}
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/* 回溯算法:子集和 II */
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func (s subsetII) backtrack(start, target int, state, choices *[]int, res *[][]int) {
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func backtrackSubsetSumII(start, target int, state, choices *[]int, res *[][]int) {
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// 子集和等于 target 时,记录解
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if target == 0 {
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newState := append([]int{}, *state...)
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@ -32,7 +30,7 @@ func (s subsetII) backtrack(start, target int, state, choices *[]int, res *[][]i
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// 尝试:做出选择,更新 target, start
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*state = append(*state, (*choices)[i])
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// 进行下一轮选择
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s.backtrack(i+1, target-(*choices)[i], state, choices, res)
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backtrackSubsetSumII(i+1, target-(*choices)[i], state, choices, res)
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// 回退:撤销选择,恢复到之前的状态
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*state = (*state)[:len(*state)-1]
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}
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@ -40,11 +38,10 @@ func (s subsetII) backtrack(start, target int, state, choices *[]int, res *[][]i
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/* 求解子集和 II */
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func subsetSumII(nums []int, target int) [][]int {
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s := subsetII{}
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state := make([]int, 0) // 状态(子集)
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sort.Ints(nums) // 对 nums 进行排序
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start := 0 // 遍历起始点
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res := make([][]int, 0) // 结果列表(子集列表)
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s.backtrack(start, target, &state, &nums, &res)
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backtrackSubsetSumII(start, target, &state, &nums, &res)
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return res
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}
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