pull/17/head
NIngCoder 2 years ago
parent 121cb10209
commit 7b8ee7fb4b

@ -1,37 +1,47 @@
'''
File: bubble_sort.py
Created Time: 2022-11-25
Author: Krahets (krahets@163.com)
Author: timi (xisunyy@163.com)
'''
import sys, os.path as osp
sys.path.append(osp.dirname(osp.dirname(osp.abspath(__file__))))
from include import *
import sys
import os.path as osp
sys.path.append(osp.dirname(osp.dirname(osp.abspath(__file__))))
"冒泡排序"
"""冒泡排序"""
def bubble_sort(nums):
n=len(nums)
n = len(nums)
# 外循环:待排序元素数量为 n-1, n-2, ..., 1
for i in range(n-1,-1,-1):
for i in range(n-1, -1, -1):
# 内循环:冒泡操作
for j in range(i):
if nums[j]>nums[j+1]:
nums[j],nums[j+1]=nums[j+1],nums[j]
"冒泡排序(标志优化)"
def bubbleSortWithFlag(nums):
n=len(nums)
# 交换 nums[j] 与 nums[j + 1]
if nums[j] > nums[j+1]:
nums[j], nums[j+1] = nums[j+1], nums[j]
"""冒泡排序(标志优化)"""
def bubble_sort_with_flag(nums):
n = len(nums)
# 外循环:待排序元素数量为 n-1, n-2, ..., 1
for i in range(n-1,-1,-1):
flag=False #初始化标志位
for i in range(n-1, -1, -1):
flag = False # 初始化标志位
# 内循环:冒泡操作
for j in range(i):
if nums[j]>nums[j+1]:
nums[j],nums[j+1]=nums[j+1],nums[j]
flag=True #记录交换元素
if not flag:break
if __name__=='__main__':
nums=[4,1,3,1,5,2]
# 交换 nums[j] 与 nums[j + 1]
if nums[j] > nums[j+1]:
nums[j], nums[j+1] = nums[j+1], nums[j]
flag = True # 记录交换元素
if not flag:
break # 此轮冒泡未交换任何元素,直接跳出
if __name__ == '__main__':
nums = [4, 1, 3, 1, 5, 2]
bubble_sort(nums)
print("冒泡排序后数组 nums = " ,nums)
bubbleSortWithFlag(nums)
print("冒泡排序后数组 nums = " ,nums)
print("排序后数组 nums = ", nums)
nums1 = [4, 1, 3, 1, 5, 2]
bubble_sort_with_flag(nums1)
print("排序后数组 nums = ", nums1)

@ -1,26 +1,28 @@
'''
File: insertion_sort.py
Created Time: 2022-11-25
Author: Krahets (krahets@163.com)
Author: timi (xisunyy@163.com)
'''
import sys, os.path as osp
sys.path.append(osp.dirname(osp.dirname(osp.abspath(__file__))))
from include import *
import sys
import os.path as osp
sys.path.append(osp.dirname(osp.dirname(osp.abspath(__file__))))
"""插入排序"""
def insertion_sort(nums):
# 外循环base = nums[1], nums[2], ..., nums[n-1]
for i in range(1, len(nums)):
base = nums[i]
j = i-1
# 内循环:将 base 插入到左边的正确位置
while j >= 0 and nums[j] > base:
nums[j+1] = nums[j] # 1. 将 nums[j] 向右移动一位
j -= 1
nums[j+1] = base # 2. 将 base 赋值到正确位置
"直接插入排序"
def insertionSort(nums):
#外循环base = nums[1], nums[2], ..., nums[n-1]
for i in range(1,len(nums)):
base=nums[i]
j=i-1
#内循环:将 base 插入到左边的正确位置
while j>=0 and nums[j]>base:
nums[j+1]=nums[j] #1. 将 nums[j] 向右移动一位
j-=1
nums[j+1]=base #2. 将 base 赋值到正确位置
if __name__=='__main__':
nums=[4,1,3,1,5,2]
insertionSort(nums)
print("排序后数组 nums = " ,nums)
if __name__ == '__main__':
nums = [4, 1, 3, 1, 5, 2]
insertion_sort(nums)
print("排序后数组 nums = ", nums)

@ -1,48 +1,60 @@
'''
File: merge_sort.py
Created Time: 2022-11-25
Author: Krahets (krahets@163.com)
Author: timi (xisunyy@163.com)
'''
import sys, os.path as osp
sys.path.append(osp.dirname(osp.dirname(osp.abspath(__file__))))
import copy
from include import *
import sys
import os.path as osp
sys.path.append(osp.dirname(osp.dirname(osp.abspath(__file__))))
"""
另一种 思路实现归并排序
合并左子数组和右子数组
左子数组区间 [left, mid]
右子数组区间 [mid + 1, right]
"""
def merge_sort(nums,l,r):
if l>=r:return
mid=l+r>>1 #划分中点
#进行归并
merge_sort(nums,l,mid)
merge_sort(nums,mid+1,r)
k,i,j=0,l,mid+1 #借助辅助数组 完成排序
while i<=mid and j<=r:
if nums[i]<=nums[j]: #这一步保证了 稳定排序
help_ls[k]=nums[i]
i+=1
def merge(nums, left, mid, right):
# 初始化辅助数组 借助 copy模块
tmp = copy.deepcopy(nums[left:right+1])
# 左子数组的起始索引和结束索引
leftStart, leftEnd = left-left, mid - left
# 右子数组的起始索引和结束索引
rightStart, rightEnd = mid + 1 - left, right - left
# i, j 分别指向左子数组、右子数组的首元素
i, j = leftStart, rightStart
# 通过覆盖原数组 nums 来合并左子数组和右子数组
for k in range(left, right+1):
# 若 “左子数组已全部合并完”,则选取右子数组元素,并且 j++
if i > leftEnd:
nums[k] = tmp[j]
j += 1
# 否则,若 “右子数组已全部合并完” 或 “左子数组元素 < 右子数组元素”,则选取左子数组元素,并且 i++
elif j > rightEnd or tmp[i] <= tmp[j]:
nums[k] = tmp[i]
i += 1
# 否则,若 “左子数组元素 > 右子数组元素”,则选取右子数组元素,并且 j++
else:
help_ls[k]=nums[j]
j+=1
k+=1
while i<=mid: #对于左边区域
help_ls[k]=nums[i]
k,i=k+1,i+1
while j<=r: #对于右边区域
help_ls[k]=nums[j]
k,j=k+1,j+1
nums[k] = tmp[j]
j += 1
"""归并排序"""
def merge_sort(nums, left, right):
# 终止条件
if left >= right:
return # 当子数组长度为 1 时终止递归
# 划分阶段
mid = left + right >> 1 # 计算中点
merge_sort(nums, left, mid) # 递归左子数组
merge_sort(nums, mid + 1, right) # 递归右子数组
# 合并阶段
merge(nums, left, mid, right)
i,j=l,0
while i<=r:
nums[i]=help_ls[j]
i,j=i+1,j+1
if __name__=='__main__':
nums=[4,1,3,1,5,2]
n=len(nums)
help_ls=[0 for _ in range(n)]
merge_sort(nums,0,n-1)
print("归并排序完成后 nums = ",nums)
if __name__ == '__main__':
nums = [4, 1, 3, 1, 5, 2]
merge_sort(nums, 0, len(nums)-1)
print("归并排序完成后 nums = ", nums)

@ -1,31 +1,132 @@
'''
File: quick_sort.py
Created Time: 2022-11-25
Author: Krahets (krahets@163.com)
Author: timi (xisunyy@163.com)
'''
import sys, os.path as osp
sys.path.append(osp.dirname(osp.dirname(osp.abspath(__file__))))
from include import *
import sys
import os.path as osp
sys.path.append(osp.dirname(osp.dirname(osp.abspath(__file__))))
"""快速排序类"""
class quick_sort(object):
"""哨兵划分"""
def partition(self, nums, left, right):
# 以 nums[left] 作为基准数
i, j = left, right
while i < j:
while i < j and nums[j] >= nums[left]:
j -= 1 # 从右向左找首个小于基准数的元素
while i < j and nums[i] <= nums[left]:
i += 1 # 从左向右找首个大于基准数的元素
# 元素交换
nums[i], nums[j] = nums[j], nums[i]
# 将基准数交换至两子数组的分界线
nums[i], nums[left] = nums[left], nums[i]
return i # 返回基准数的索引
"""快速排序"""
def quick_sort(self, nums, left, right):
# 子数组长度为 1 时终止递归
if left >= right:
return
# 哨兵划分
pivot = self.partition(nums, left, right)
# 递归左子数组、右子数组
self.quick_sort(nums, left, pivot-1)
self.quick_sort(nums, pivot+1, right)
"""快速排序类(中位基准数优化)"""
class quick_sort_median():
# 选取三个元素的中位数
def median_three(self, nums, left, mid, right):
# 使用了异或操作来简化代码
# 异或规则为 0 ^ 0 = 1 ^ 1 = 0, 0 ^ 1 = 1 ^ 0 = 1
if (nums[left] > nums[mid]) ^ (nums[left] > nums[right]):
return left
elif (nums[mid] < nums[left]) ^ (nums[mid] > nums[right]):
return mid
return right
"""哨兵划分(三数取中值)"""
def partition(self, nums, left, right):
# 以 nums[left] 作为基准数
med = self.median_three(nums, left, (left+right)//2, right)
# 将中位数交换至数组最左端
nums[left], nums[med] = nums[med], nums[left]
# 以 nums[left] 作为基准数
i, j = left, right
while i < j:
while i < j and nums[j] >= nums[left]:
j -= 1 # 从右向左找首个小于基准数的元素
while i < j and nums[i] <= nums[left]:
i += 1 # 从左向右找首个大于基准数的元素
# 元素交换
nums[i], nums[j] = nums[j], nums[i]
# 将基准数交换至两子数组的分界线
nums[i], nums[left] = nums[left], nums[i]
return i # 返回基准数的索引
"""快速排序"""
def quick_sort(self, nums, left, right):
# 子数组长度为 1 时终止递归
if left >= right:return
# 哨兵划分
pivot = self.partition(nums, left, right)
# 递归左子数组、右子数组
self.quick_sort(nums, left, pivot-1)
self.quick_sort(nums, pivot+1, right)
"""快速排序类(尾递归优化)"""
class quick_sort_tail_call():
"""哨兵划分"""
def partition(self, nums, left, right):
# 以 nums[left] 作为基准数
i, j = left, right
while i < j:
while i < j and nums[j] >= nums[left]:
j -= 1 # 从右向左找首个小于基准数的元素
while i < j and nums[i] <= nums[left]:
i += 1 # 从左向右找首个大于基准数的元素
# 元素交换
nums[i], nums[j] = nums[j], nums[i]
# 将基准数交换至两子数组的分界线
nums[i], nums[left] = nums[left], nums[i]
return i # 返回基准数的索引
"""快速排序(尾递归优化)"""
def quick_sort(self, nums, left, right):
# 子数组长度为 1 时终止
while left < right:
# 哨兵划分操作
pivot = self.partition(nums, left, right)
# 对两个子数组中较短的那个执行快排
if pivot-left < right-pivot:
self.quick_sort(nums, left, pivot-1) # 递归排序左子数组
left = pivot+1 # 剩余待排序区间为 [pivot + 1, right]
else:
self.quick_sort(nums, pivot+1, right) # 递归排序右子数组
right = pivot-1 # 剩余待排序区间为 [left, pivot - 1]
if __name__ == '__main__':
# 快速排序
nums = [4, 1, 3, 1, 5, 2]
quick_sort().quick_sort(nums, 0, len(nums)-1)
print("快速排序完成后 nums = ", nums)
# 快速排序(中位基准数优化)
nums1 = [4, 1, 3, 1, 5, 2]
quick_sort_median().quick_sort(nums1, 0, len(nums1)-1)
print("快速排序(中位基准数优化)完成后 nums = ", nums)
"另一种思维 实现快速排序"
def quick_sort(nums,l,r):
if l>=r:
return
i,j,x=l-1,r+1,nums[l+r>>1]
while i<j:
while True:
i+=1
if nums[i]>=x:break
while True:
j-=1
if nums[j]<=x:break
if i<j:nums[i],nums[j]=nums[j],nums[i]
quick_sort(nums,l,j),quick_sort(nums,j+1,r)
if __name__=='__main__':
nums=[4,1,3,1,5,2]
n=len(nums)
help_ls=[0 for _ in range(n)]
quick_sort(nums,0,n-1)
print("快速排序完成后 nums = ",nums)
# 快速排序(尾递归优化)
nums2 = [4, 1, 3, 1, 5, 2]
quick_sort_tail_call().quick_sort(nums, 0, len(nums2)-1)
print("快速排序(尾递归优化)完成后 nums = ", nums)

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