parent
121cb10209
commit
7b8ee7fb4b
@ -1,37 +1,47 @@
|
||||
'''
|
||||
File: bubble_sort.py
|
||||
Created Time: 2022-11-25
|
||||
Author: Krahets (krahets@163.com)
|
||||
Author: timi (xisunyy@163.com)
|
||||
'''
|
||||
|
||||
import sys, os.path as osp
|
||||
sys.path.append(osp.dirname(osp.dirname(osp.abspath(__file__))))
|
||||
from include import *
|
||||
import sys
|
||||
import os.path as osp
|
||||
sys.path.append(osp.dirname(osp.dirname(osp.abspath(__file__))))
|
||||
|
||||
"冒泡排序"
|
||||
"""冒泡排序"""
|
||||
def bubble_sort(nums):
|
||||
n=len(nums)
|
||||
n = len(nums)
|
||||
# 外循环:待排序元素数量为 n-1, n-2, ..., 1
|
||||
for i in range(n-1,-1,-1):
|
||||
for i in range(n-1, -1, -1):
|
||||
# 内循环:冒泡操作
|
||||
for j in range(i):
|
||||
if nums[j]>nums[j+1]:
|
||||
nums[j],nums[j+1]=nums[j+1],nums[j]
|
||||
"冒泡排序(标志优化)"
|
||||
def bubbleSortWithFlag(nums):
|
||||
n=len(nums)
|
||||
# 交换 nums[j] 与 nums[j + 1]
|
||||
if nums[j] > nums[j+1]:
|
||||
nums[j], nums[j+1] = nums[j+1], nums[j]
|
||||
|
||||
|
||||
"""冒泡排序(标志优化)"""
|
||||
def bubble_sort_with_flag(nums):
|
||||
n = len(nums)
|
||||
# 外循环:待排序元素数量为 n-1, n-2, ..., 1
|
||||
for i in range(n-1,-1,-1):
|
||||
flag=False #初始化标志位
|
||||
for i in range(n-1, -1, -1):
|
||||
flag = False # 初始化标志位
|
||||
# 内循环:冒泡操作
|
||||
for j in range(i):
|
||||
if nums[j]>nums[j+1]:
|
||||
nums[j],nums[j+1]=nums[j+1],nums[j]
|
||||
flag=True #记录交换元素
|
||||
if not flag:break
|
||||
if __name__=='__main__':
|
||||
nums=[4,1,3,1,5,2]
|
||||
# 交换 nums[j] 与 nums[j + 1]
|
||||
if nums[j] > nums[j+1]:
|
||||
nums[j], nums[j+1] = nums[j+1], nums[j]
|
||||
flag = True # 记录交换元素
|
||||
if not flag:
|
||||
break # 此轮冒泡未交换任何元素,直接跳出
|
||||
|
||||
|
||||
if __name__ == '__main__':
|
||||
nums = [4, 1, 3, 1, 5, 2]
|
||||
bubble_sort(nums)
|
||||
print("冒泡排序后数组 nums = " ,nums)
|
||||
bubbleSortWithFlag(nums)
|
||||
print("冒泡排序后数组 nums = " ,nums)
|
||||
print("排序后数组 nums = ", nums)
|
||||
|
||||
nums1 = [4, 1, 3, 1, 5, 2]
|
||||
bubble_sort_with_flag(nums1)
|
||||
print("排序后数组 nums = ", nums1)
|
||||
|
@ -1,48 +1,60 @@
|
||||
'''
|
||||
File: merge_sort.py
|
||||
Created Time: 2022-11-25
|
||||
Author: Krahets (krahets@163.com)
|
||||
Author: timi (xisunyy@163.com)
|
||||
'''
|
||||
|
||||
import sys, os.path as osp
|
||||
sys.path.append(osp.dirname(osp.dirname(osp.abspath(__file__))))
|
||||
import copy
|
||||
from include import *
|
||||
import sys
|
||||
import os.path as osp
|
||||
sys.path.append(osp.dirname(osp.dirname(osp.abspath(__file__))))
|
||||
|
||||
|
||||
"""
|
||||
另一种 思路实现归并排序
|
||||
合并左子数组和右子数组
|
||||
左子数组区间 [left, mid]
|
||||
右子数组区间 [mid + 1, right]
|
||||
"""
|
||||
def merge_sort(nums,l,r):
|
||||
if l>=r:return
|
||||
mid=l+r>>1 #划分中点
|
||||
#进行归并
|
||||
merge_sort(nums,l,mid)
|
||||
merge_sort(nums,mid+1,r)
|
||||
|
||||
k,i,j=0,l,mid+1 #借助辅助数组 完成排序
|
||||
while i<=mid and j<=r:
|
||||
if nums[i]<=nums[j]: #这一步保证了 稳定排序
|
||||
help_ls[k]=nums[i]
|
||||
i+=1
|
||||
def merge(nums, left, mid, right):
|
||||
# 初始化辅助数组 借助 copy模块
|
||||
tmp = copy.deepcopy(nums[left:right+1])
|
||||
# 左子数组的起始索引和结束索引
|
||||
leftStart, leftEnd = left-left, mid - left
|
||||
# 右子数组的起始索引和结束索引
|
||||
rightStart, rightEnd = mid + 1 - left, right - left
|
||||
# i, j 分别指向左子数组、右子数组的首元素
|
||||
i, j = leftStart, rightStart
|
||||
# 通过覆盖原数组 nums 来合并左子数组和右子数组
|
||||
for k in range(left, right+1):
|
||||
# 若 “左子数组已全部合并完”,则选取右子数组元素,并且 j++
|
||||
if i > leftEnd:
|
||||
nums[k] = tmp[j]
|
||||
j += 1
|
||||
# 否则,若 “右子数组已全部合并完” 或 “左子数组元素 < 右子数组元素”,则选取左子数组元素,并且 i++
|
||||
elif j > rightEnd or tmp[i] <= tmp[j]:
|
||||
nums[k] = tmp[i]
|
||||
i += 1
|
||||
# 否则,若 “左子数组元素 > 右子数组元素”,则选取右子数组元素,并且 j++
|
||||
else:
|
||||
help_ls[k]=nums[j]
|
||||
j+=1
|
||||
k+=1
|
||||
nums[k] = tmp[j]
|
||||
j += 1
|
||||
|
||||
|
||||
"""归并排序"""
|
||||
def merge_sort(nums, left, right):
|
||||
# 终止条件
|
||||
if left >= right:
|
||||
return # 当子数组长度为 1 时终止递归
|
||||
# 划分阶段
|
||||
mid = left + right >> 1 # 计算中点
|
||||
merge_sort(nums, left, mid) # 递归左子数组
|
||||
merge_sort(nums, mid + 1, right) # 递归右子数组
|
||||
# 合并阶段
|
||||
merge(nums, left, mid, right)
|
||||
|
||||
while i<=mid: #对于左边区域
|
||||
help_ls[k]=nums[i]
|
||||
k,i=k+1,i+1
|
||||
while j<=r: #对于右边区域
|
||||
help_ls[k]=nums[j]
|
||||
k,j=k+1,j+1
|
||||
|
||||
i,j=l,0
|
||||
while i<=r:
|
||||
nums[i]=help_ls[j]
|
||||
i,j=i+1,j+1
|
||||
if __name__=='__main__':
|
||||
nums=[4,1,3,1,5,2]
|
||||
n=len(nums)
|
||||
help_ls=[0 for _ in range(n)]
|
||||
merge_sort(nums,0,n-1)
|
||||
print("归并排序完成后 nums = ",nums)
|
||||
if __name__ == '__main__':
|
||||
nums = [4, 1, 3, 1, 5, 2]
|
||||
merge_sort(nums, 0, len(nums)-1)
|
||||
print("归并排序完成后 nums = ", nums)
|
||||
|
@ -1,31 +1,132 @@
|
||||
'''
|
||||
File: quick_sort.py
|
||||
Created Time: 2022-11-25
|
||||
Author: Krahets (krahets@163.com)
|
||||
Author: timi (xisunyy@163.com)
|
||||
'''
|
||||
|
||||
import sys, os.path as osp
|
||||
sys.path.append(osp.dirname(osp.dirname(osp.abspath(__file__))))
|
||||
from include import *
|
||||
import sys
|
||||
import os.path as osp
|
||||
sys.path.append(osp.dirname(osp.dirname(osp.abspath(__file__))))
|
||||
|
||||
|
||||
"""快速排序类"""
|
||||
class quick_sort(object):
|
||||
|
||||
"""哨兵划分"""
|
||||
def partition(self, nums, left, right):
|
||||
# 以 nums[left] 作为基准数
|
||||
i, j = left, right
|
||||
while i < j:
|
||||
while i < j and nums[j] >= nums[left]:
|
||||
j -= 1 # 从右向左找首个小于基准数的元素
|
||||
while i < j and nums[i] <= nums[left]:
|
||||
i += 1 # 从左向右找首个大于基准数的元素
|
||||
# 元素交换
|
||||
nums[i], nums[j] = nums[j], nums[i]
|
||||
# 将基准数交换至两子数组的分界线
|
||||
nums[i], nums[left] = nums[left], nums[i]
|
||||
return i # 返回基准数的索引
|
||||
|
||||
"另一种思维 实现快速排序"
|
||||
def quick_sort(nums,l,r):
|
||||
if l>=r:
|
||||
"""快速排序"""
|
||||
def quick_sort(self, nums, left, right):
|
||||
# 子数组长度为 1 时终止递归
|
||||
if left >= right:
|
||||
return
|
||||
i,j,x=l-1,r+1,nums[l+r>>1]
|
||||
while i<j:
|
||||
while True:
|
||||
i+=1
|
||||
if nums[i]>=x:break
|
||||
while True:
|
||||
j-=1
|
||||
if nums[j]<=x:break
|
||||
if i<j:nums[i],nums[j]=nums[j],nums[i]
|
||||
quick_sort(nums,l,j),quick_sort(nums,j+1,r)
|
||||
if __name__=='__main__':
|
||||
nums=[4,1,3,1,5,2]
|
||||
n=len(nums)
|
||||
help_ls=[0 for _ in range(n)]
|
||||
quick_sort(nums,0,n-1)
|
||||
print("快速排序完成后 nums = ",nums)
|
||||
# 哨兵划分
|
||||
pivot = self.partition(nums, left, right)
|
||||
# 递归左子数组、右子数组
|
||||
self.quick_sort(nums, left, pivot-1)
|
||||
self.quick_sort(nums, pivot+1, right)
|
||||
|
||||
|
||||
"""快速排序类(中位基准数优化)"""
|
||||
class quick_sort_median():
|
||||
|
||||
# 选取三个元素的中位数
|
||||
def median_three(self, nums, left, mid, right):
|
||||
# 使用了异或操作来简化代码
|
||||
# 异或规则为 0 ^ 0 = 1 ^ 1 = 0, 0 ^ 1 = 1 ^ 0 = 1
|
||||
if (nums[left] > nums[mid]) ^ (nums[left] > nums[right]):
|
||||
return left
|
||||
elif (nums[mid] < nums[left]) ^ (nums[mid] > nums[right]):
|
||||
return mid
|
||||
return right
|
||||
|
||||
"""哨兵划分(三数取中值)"""
|
||||
def partition(self, nums, left, right):
|
||||
# 以 nums[left] 作为基准数
|
||||
med = self.median_three(nums, left, (left+right)//2, right)
|
||||
# 将中位数交换至数组最左端
|
||||
nums[left], nums[med] = nums[med], nums[left]
|
||||
# 以 nums[left] 作为基准数
|
||||
i, j = left, right
|
||||
while i < j:
|
||||
while i < j and nums[j] >= nums[left]:
|
||||
j -= 1 # 从右向左找首个小于基准数的元素
|
||||
while i < j and nums[i] <= nums[left]:
|
||||
i += 1 # 从左向右找首个大于基准数的元素
|
||||
# 元素交换
|
||||
nums[i], nums[j] = nums[j], nums[i]
|
||||
# 将基准数交换至两子数组的分界线
|
||||
nums[i], nums[left] = nums[left], nums[i]
|
||||
return i # 返回基准数的索引
|
||||
|
||||
"""快速排序"""
|
||||
def quick_sort(self, nums, left, right):
|
||||
# 子数组长度为 1 时终止递归
|
||||
if left >= right:return
|
||||
# 哨兵划分
|
||||
pivot = self.partition(nums, left, right)
|
||||
# 递归左子数组、右子数组
|
||||
self.quick_sort(nums, left, pivot-1)
|
||||
self.quick_sort(nums, pivot+1, right)
|
||||
|
||||
|
||||
"""快速排序类(尾递归优化)"""
|
||||
class quick_sort_tail_call():
|
||||
|
||||
"""哨兵划分"""
|
||||
def partition(self, nums, left, right):
|
||||
# 以 nums[left] 作为基准数
|
||||
i, j = left, right
|
||||
while i < j:
|
||||
while i < j and nums[j] >= nums[left]:
|
||||
j -= 1 # 从右向左找首个小于基准数的元素
|
||||
while i < j and nums[i] <= nums[left]:
|
||||
i += 1 # 从左向右找首个大于基准数的元素
|
||||
# 元素交换
|
||||
nums[i], nums[j] = nums[j], nums[i]
|
||||
# 将基准数交换至两子数组的分界线
|
||||
nums[i], nums[left] = nums[left], nums[i]
|
||||
return i # 返回基准数的索引
|
||||
|
||||
"""快速排序(尾递归优化)"""
|
||||
def quick_sort(self, nums, left, right):
|
||||
# 子数组长度为 1 时终止
|
||||
while left < right:
|
||||
# 哨兵划分操作
|
||||
pivot = self.partition(nums, left, right)
|
||||
# 对两个子数组中较短的那个执行快排
|
||||
if pivot-left < right-pivot:
|
||||
self.quick_sort(nums, left, pivot-1) # 递归排序左子数组
|
||||
left = pivot+1 # 剩余待排序区间为 [pivot + 1, right]
|
||||
else:
|
||||
self.quick_sort(nums, pivot+1, right) # 递归排序右子数组
|
||||
right = pivot-1 # 剩余待排序区间为 [left, pivot - 1]
|
||||
|
||||
if __name__ == '__main__':
|
||||
# 快速排序
|
||||
nums = [4, 1, 3, 1, 5, 2]
|
||||
quick_sort().quick_sort(nums, 0, len(nums)-1)
|
||||
print("快速排序完成后 nums = ", nums)
|
||||
|
||||
# 快速排序(中位基准数优化)
|
||||
nums1 = [4, 1, 3, 1, 5, 2]
|
||||
quick_sort_median().quick_sort(nums1, 0, len(nums1)-1)
|
||||
print("快速排序(中位基准数优化)完成后 nums = ", nums)
|
||||
|
||||
# 快速排序(尾递归优化)
|
||||
nums2 = [4, 1, 3, 1, 5, 2]
|
||||
quick_sort_tail_call().quick_sort(nums, 0, len(nums2)-1)
|
||||
print("快速排序(尾递归优化)完成后 nums = ", nums)
|
||||
|
Loading…
Reference in new issue