feat: add C merge sort (#434)
* feat: add C merge sort * Update merge_sort.c --------- Co-authored-by: Yudong Jin <krahets@163.com>pull/441/head
parent
0a4a846e13
commit
9b0bdd929f
@ -0,0 +1,60 @@
|
||||
/**
|
||||
* File: merge_sort.c
|
||||
* Created Time: 2022-03-21
|
||||
* Author: Guanngxu (446678850@qq.com)
|
||||
*/
|
||||
|
||||
#include "../include/include.h"
|
||||
|
||||
/* 合并左子数组和右子数组 */
|
||||
// 左子数组区间 [left, mid]
|
||||
// 右子数组区间 [mid + 1, right]
|
||||
void merge(int *nums, int left, int mid, int right) {
|
||||
int index;
|
||||
// 初始化辅助数组
|
||||
int tmp[right + 1 - left];
|
||||
for(index = left; index < right + 1; index++) {
|
||||
tmp[index - left] = nums[index];
|
||||
}
|
||||
// 左子数组的起始索引和结束索引
|
||||
int leftStart = left - left, leftEnd = mid - left;
|
||||
// 右子数组的起始索引和结束索引
|
||||
int rightStart = mid + 1 - left, rightEnd = right - left;
|
||||
// i, j 分别指向左子数组、右子数组的首元素
|
||||
int i = leftStart, j = rightStart;
|
||||
// 通过覆盖原数组 nums 来合并左子数组和右子数组
|
||||
for (int k = left; k <= right; k++) {
|
||||
// 若“左子数组已全部合并完”,则选取右子数组元素,并且 j++
|
||||
if (i > leftEnd)
|
||||
nums[k] = tmp[j++];
|
||||
// 否则,若“右子数组已全部合并完”或“左子数组元素 <= 右子数组元素”,则选取左子数组元素,并且 i++
|
||||
else if (j > rightEnd || tmp[i] <= tmp[j])
|
||||
nums[k] = tmp[i++];
|
||||
// 否则,若“左右子数组都未全部合并完”且“左子数组元素 > 右子数组元素”,则选取右子数组元素,并且 j++
|
||||
else
|
||||
nums[k] = tmp[j++];
|
||||
}
|
||||
}
|
||||
|
||||
/* 归并排序 */
|
||||
void mergeSort(int *nums, int left, int right) {
|
||||
// 终止条件
|
||||
if (left >= right) return; // 当子数组长度为 1 时终止递归
|
||||
// 划分阶段
|
||||
int mid = (left + right) / 2; // 计算中点
|
||||
mergeSort(nums, left, mid); // 递归左子数组
|
||||
mergeSort(nums, mid + 1, right); // 递归右子数组
|
||||
// 合并阶段
|
||||
merge(nums, left, mid, right);
|
||||
}
|
||||
|
||||
/* Driver Code */
|
||||
int main() {
|
||||
/* 归并排序 */
|
||||
int nums[] = { 7, 3, 2, 6, 0, 1, 5, 4 };
|
||||
int size = sizeof(nums) / sizeof(int);
|
||||
mergeSort(nums, 0, size - 1);
|
||||
printf("归并排序完成后 nums = ");
|
||||
printArray(nums, size);
|
||||
return 0;
|
||||
}
|
Loading…
Reference in new issue