update python randomAccess

random.randomint(start, stop) 返回数字的范围是 [start, stop] 是一个闭区间，如果用len(nums) 有可能会索引超出范围
2 years ago · dab16ee53a
parent 004f570512
commit dab16ee53a
1 changed files with 1 additions and 1 deletions
--- a/docs/chapter_array_and_linkedlist/array.md
+++ b/docs/chapter_array_and_linkedlist/array.md
@ -137,7 +137,7 @@ elementAddr = firtstElementAddr + elementLength * elementIndex
    """ 随机访问元素 """
    def randomAccess(nums):
        # 在区间 [0, len(nums)) 中随机抽取一个数字
-        random_index = random.randint(0, len(nums))
+        random_index = random.randint(0, len(nums)-1)
        # 获取并返回随机元素
        random_num = nums[random_index]
        return random_num