commit
e5563b3964
@ -1,10 +1,51 @@
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'''
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'''
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File: binary_search.py
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File: binary_search.py
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Created Time: 2022-11-25
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Created Time: 2022-11-26
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Author: Krahets (krahets@163.com)
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Author: timi (xisunyy@163.com)
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'''
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'''
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import sys, os.path as osp
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import sys, os.path as osp
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sys.path.append(osp.dirname(osp.dirname(osp.abspath(__file__))))
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sys.path.append(osp.dirname(osp.dirname(osp.abspath(__file__))))
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from include import *
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from include import *
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""" 二分查找(双闭区间) """
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def binary_search(nums, target):
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# 初始化双闭区间 [0, n-1] ,即 i, j 分别指向数组首元素、尾元素
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i, j = 0, len(nums) - 1
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while i <= j:
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m = (i + j) // 2 # 计算中点索引 m
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if nums[m] < target: # 此情况说明 target 在区间 [m+1, j] 中
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i = m + 1
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elif nums[m] > target: # 此情况说明 target 在区间 [i, m-1] 中
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j = m - 1
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else:
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return m # 找到目标元素,返回其索引
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return -1 # 未找到目标元素,返回 -1
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""" 二分查找(左闭右开) """
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def binary_search1(nums, target):
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# 初始化左闭右开 [0, n) ,即 i, j 分别指向数组首元素、尾元素+1
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i, j = 0, len(nums)
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# 循环,当搜索区间为空时跳出(当 i = j 时为空)
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while i < j:
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m = (i + j) // 2 # 计算中点索引 m
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if nums[m] < target: # 此情况说明 target 在区间 [m+1, j) 中
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i = m + 1
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elif nums[m] > target: # 此情况说明 target 在区间 [i, m) 中
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j = m
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else: # 找到目标元素,返回其索引
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return m
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return -1 # 未找到目标元素,返回 -1
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if __name__ == '__main__':
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target = 6
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nums = [1, 3, 6, 8, 12, 15, 23, 67, 70, 92]
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# 二分查找(双闭区间)
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index = binary_search(nums, target)
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print("目标元素 6 的索引 = ", index)
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# 二分查找(左闭右开)
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index = binary_search1(nums, target)
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print("目标元素 6 的索引 = ", index)
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@ -1,10 +1,38 @@
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'''
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'''
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File: linear_search.py
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File: linear_search.py
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Created Time: 2022-11-25
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Created Time: 2022-11-26
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Author: Krahets (krahets@163.com)
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Author: timi (xisunyy@163.com)
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'''
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'''
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import sys, os.path as osp
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import sys, os.path as osp
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sys.path.append(osp.dirname(osp.dirname(osp.abspath(__file__))))
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sys.path.append(osp.dirname(osp.dirname(osp.abspath(__file__))))
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from include import *
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from include import *
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""" 线性查找(数组) """
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def linear_search(nums,target):
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# 遍历数组
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for i in range(len(nums)):
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if nums[i]==target: # 找到目标元素,返回其索引
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return i
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return -1 # 未找到目标元素,返回 -1
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""" 线性查找(链表) """
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def linear_search_by_link(head,target):
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# 遍历链表
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while head:
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if head.val==target: # 找到目标结点,返回之
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return head
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head=head.next
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return None # 未找到目标结点,返回 None (Python为None)
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if __name__=='__main__':
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target=3
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# 在数组中执行线性查找
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nums=[1, 5, 3, 2, 4, 7, 5, 9, 10, 8]
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index=linear_search(nums,target)
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print("目标元素 3 的索引 = " ,index)
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# 在链表中执行线性查找
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head=list_to_linked_list(nums)
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node=linear_search_by_link(head,target)
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print("目标结点值 3 的对应结点对象为 " ,node)
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