Add Chapter greedy for JS and TS code (#718)
* Fix binary_search_tree TS code * Update binary_search_tree js code style * Add the JavaScript code for Chapter of Greedy * Add the TypeScript code for Chapter of Greedy --------- Co-authored-by: Yudong Jin <krahets@163.com>pull/719/head
parent
89a5f4d0d7
commit
f96f583771
@ -0,0 +1,48 @@
|
||||
/**
|
||||
* File: coin_change_greedy.js
|
||||
* Created Time: 2023-09-02
|
||||
* Author: Justin (xiefahit@gmail.com)
|
||||
*/
|
||||
|
||||
/* 零钱兑换:贪心 */
|
||||
function coin_change_greedy(coins, amt) {
|
||||
// 假设 coins 数组有序
|
||||
let i = coins.length - 1;
|
||||
let count = 0;
|
||||
// 循环进行贪心选择,直到无剩余金额
|
||||
while (amt > 0) {
|
||||
// 找到小于且最接近剩余金额的硬币
|
||||
while (i > 0 && coins[i] > amt) {
|
||||
i--;
|
||||
}
|
||||
// 选择 coins[i]
|
||||
amt -= coins[i];
|
||||
count++;
|
||||
}
|
||||
// 若未找到可行方案,则返回 -1
|
||||
return amt === 0 ? count : -1;
|
||||
}
|
||||
|
||||
/* Driver Code */
|
||||
// 贪心:能够保证找到全局最优解
|
||||
let coins = [1, 5, 10, 20, 50, 100];
|
||||
let amt = 186;
|
||||
let res = coin_change_greedy(coins, amt);
|
||||
console.log(`\ncoins = ${coins}, amt = ${amt}`);
|
||||
console.log(`凑到 ${amt} 所需的最少硬币数量为 ${res}`);
|
||||
|
||||
// 贪心:无法保证找到全局最优解
|
||||
coins = [1, 20, 50];
|
||||
amt = 60;
|
||||
res = coin_change_greedy(coins, amt);
|
||||
console.log(`\ncoins = ${coins}, amt = ${amt}`);
|
||||
console.log(`凑到 ${amt} 所需的最少硬币数量为 ${res}`);
|
||||
console.log("实际上需要的最少数量为 3 ,即 20 + 20 + 20");
|
||||
|
||||
// 贪心:无法保证找到全局最优解
|
||||
coins = [1, 49, 50];
|
||||
amt = 98;
|
||||
res = coin_change_greedy(coins, amt);
|
||||
console.log(`\ncoins = ${coins}, amt = ${amt}`);
|
||||
console.log(`凑到 ${amt} 所需的最少硬币数量为 ${res}`);
|
||||
console.log("实际上需要的最少数量为 2 ,即 49 + 49");
|
@ -0,0 +1,46 @@
|
||||
/**
|
||||
* File: fractional_knapsack.js
|
||||
* Created Time: 2023-09-02
|
||||
* Author: Justin (xiefahit@gmail.com)
|
||||
*/
|
||||
|
||||
/* 物品 */
|
||||
class Item {
|
||||
constructor(w, v) {
|
||||
this.w = w; // 物品重量
|
||||
this.v = v; // 物品价值
|
||||
}
|
||||
}
|
||||
|
||||
/* 分数背包:贪心 */
|
||||
function fractional_knapsack(wgt, val, cap) {
|
||||
// 创建物品列表,包含两个属性:重量、价值
|
||||
const items = wgt.map((w, i) => new Item(w, val[i]));
|
||||
// 按照单位价值 item.v / item.w 从高到低进行排序
|
||||
items.sort((a, b) => (b.v / b.w) - (a.v / a.w));
|
||||
// 循环贪心选择
|
||||
let res = 0;
|
||||
for (const item of items) {
|
||||
if (item.w <= cap) {
|
||||
// 若剩余容量充足,则将当前物品整个装进背包
|
||||
res += item.v;
|
||||
cap -= item.w;
|
||||
} else {
|
||||
// 若剩余容量不足,则将当前物品的一部分装进背包
|
||||
res += (item.v / item.w) * cap;
|
||||
// 已无剩余容量,因此跳出循环
|
||||
break;
|
||||
}
|
||||
}
|
||||
return res;
|
||||
}
|
||||
|
||||
/* Driver Code */
|
||||
const wgt = [10, 20, 30, 40, 50];
|
||||
const val = [50, 120, 150, 210, 240];
|
||||
const cap = 50;
|
||||
const n = wgt.length;
|
||||
|
||||
// 贪心算法
|
||||
const res = fractional_knapsack(wgt, val, cap);
|
||||
console.log(`不超过背包容量的最大物品价值为 ${res}`);
|
@ -0,0 +1,33 @@
|
||||
/**
|
||||
* File: max_capacity.js
|
||||
* Created Time: 2023-09-02
|
||||
* Author: Justin (xiefahit@gmail.com)
|
||||
*/
|
||||
|
||||
/* 最大容量:贪心 */
|
||||
function max_capacity(ht) {
|
||||
// 初始化 i, j 分列数组两端
|
||||
let i = 0, j = ht.length - 1;
|
||||
// 初始最大容量为 0
|
||||
let res = 0;
|
||||
// 循环贪心选择,直至两板相遇
|
||||
while (i < j) {
|
||||
// 更新最大容量
|
||||
const cap = Math.min(ht[i], ht[j]) * (j - i);
|
||||
res = Math.max(res, cap);
|
||||
// 向内移动短板
|
||||
if (ht[i] < ht[j]) {
|
||||
i += 1;
|
||||
} else {
|
||||
j -= 1;
|
||||
}
|
||||
}
|
||||
return res;
|
||||
}
|
||||
|
||||
/* Driver Code */
|
||||
const ht = [3, 8, 5, 2, 7, 7, 3, 4];
|
||||
|
||||
// 贪心算法
|
||||
const res = max_capacity(ht);
|
||||
console.log(`最大容量为 ${res}`);
|
@ -0,0 +1,50 @@
|
||||
/**
|
||||
* File: coin_change_greedy.ts
|
||||
* Created Time: 2023-09-02
|
||||
* Author: Justin (xiefahit@gmail.com)
|
||||
*/
|
||||
|
||||
/* 零钱兑换:贪心 */
|
||||
function coin_change_greedy(coins: number[], amt: number): number {
|
||||
// 假设 coins 数组有序
|
||||
let i = coins.length - 1;
|
||||
let count = 0;
|
||||
// 循环进行贪心选择,直到无剩余金额
|
||||
while (amt > 0) {
|
||||
// 找到小于且最接近剩余金额的硬币
|
||||
while (i > 0 && coins[i] > amt) {
|
||||
i--;
|
||||
}
|
||||
// 选择 coins[i]
|
||||
amt -= coins[i];
|
||||
count++;
|
||||
}
|
||||
// 若未找到可行方案,则返回 -1
|
||||
return amt === 0 ? count : -1;
|
||||
}
|
||||
|
||||
/* Driver Code */
|
||||
// 贪心:能够保证找到全局最优解
|
||||
let coins: number[] = [1, 5, 10, 20, 50, 100];
|
||||
let amt: number = 186;
|
||||
let res: number = coin_change_greedy(coins, amt);
|
||||
console.log(`\ncoins = ${coins}, amt = ${amt}`);
|
||||
console.log(`凑到 ${amt} 所需的最少硬币数量为 ${res}`);
|
||||
|
||||
// 贪心:无法保证找到全局最优解
|
||||
coins = [1, 20, 50];
|
||||
amt = 60;
|
||||
res = coin_change_greedy(coins, amt);
|
||||
console.log(`\ncoins = ${coins}, amt = ${amt}`);
|
||||
console.log(`凑到 ${amt} 所需的最少硬币数量为 ${res}`);
|
||||
console.log("实际上需要的最少数量为 3 ,即 20 + 20 + 20");
|
||||
|
||||
// 贪心:无法保证找到全局最优解
|
||||
coins = [1, 49, 50];
|
||||
amt = 98;
|
||||
res = coin_change_greedy(coins, amt);
|
||||
console.log(`\ncoins = ${coins}, amt = ${amt}`);
|
||||
console.log(`凑到 ${amt} 所需的最少硬币数量为 ${res}`);
|
||||
console.log("实际上需要的最少数量为 2 ,即 49 + 49");
|
||||
|
||||
export { };
|
@ -0,0 +1,50 @@
|
||||
/**
|
||||
* File: fractional_knapsack.ts
|
||||
* Created Time: 2023-09-02
|
||||
* Author: Justin (xiefahit@gmail.com)
|
||||
*/
|
||||
|
||||
/* 物品 */
|
||||
class Item {
|
||||
w: number; // 物品重量
|
||||
v: number; // 物品价值
|
||||
|
||||
constructor(w: number, v: number) {
|
||||
this.w = w;
|
||||
this.v = v;
|
||||
}
|
||||
}
|
||||
|
||||
/* 分数背包:贪心 */
|
||||
function fractional_knapsack(wgt: number[], val: number[], cap: number): number {
|
||||
// 创建物品列表,包含两个属性:重量、价值
|
||||
const items: Item[] = wgt.map((w, i) => new Item(w, val[i]));
|
||||
// 按照单位价值 item.v / item.w 从高到低进行排序
|
||||
items.sort((a, b) => (b.v / b.w) - (a.v / a.w));
|
||||
// 循环贪心选择
|
||||
let res = 0;
|
||||
for (const item of items) {
|
||||
if (item.w <= cap) {
|
||||
// 若剩余容量充足,则将当前物品整个装进背包
|
||||
res += item.v;
|
||||
cap -= item.w;
|
||||
} else {
|
||||
// 若剩余容量不足,则将当前物品的一部分装进背包
|
||||
res += (item.v / item.w) * cap;
|
||||
// 已无剩余容量,因此跳出循环
|
||||
break;
|
||||
}
|
||||
}
|
||||
return res;
|
||||
}
|
||||
|
||||
/* Driver Code */
|
||||
const wgt: number[] = [10, 20, 30, 40, 50];
|
||||
const val: number[] = [50, 120, 150, 210, 240];
|
||||
const cap: number = 50;
|
||||
|
||||
// 贪心算法
|
||||
const res: number = fractional_knapsack(wgt, val, cap);
|
||||
console.log(`不超过背包容量的最大物品价值为 ${res}`);
|
||||
|
||||
export { };
|
@ -0,0 +1,35 @@
|
||||
/**
|
||||
* File: max_capacity.ts
|
||||
* Created Time: 2023-09-02
|
||||
* Author: Justin (xiefahit@gmail.com)
|
||||
*/
|
||||
|
||||
/* 最大容量:贪心 */
|
||||
function max_capacity(ht: number[]): number {
|
||||
// 初始化 i, j 分列数组两端
|
||||
let i = 0, j = ht.length - 1;
|
||||
// 初始最大容量为 0
|
||||
let res = 0;
|
||||
// 循环贪心选择,直至两板相遇
|
||||
while (i < j) {
|
||||
// 更新最大容量
|
||||
const cap: number = Math.min(ht[i], ht[j]) * (j - i);
|
||||
res = Math.max(res, cap);
|
||||
// 向内移动短板
|
||||
if (ht[i] < ht[j]) {
|
||||
i += 1;
|
||||
} else {
|
||||
j -= 1;
|
||||
}
|
||||
}
|
||||
return res;
|
||||
}
|
||||
|
||||
/* Driver Code */
|
||||
const ht: number[] = [3, 8, 5, 2, 7, 7, 3, 4];
|
||||
|
||||
// 贪心算法
|
||||
const res: number = max_capacity(ht);
|
||||
console.log(`最大容量为 ${res}`);
|
||||
|
||||
export { };
|
Loading…
Reference in new issue