/** * File: coin_change_greedy.cpp * Created Time: 2023-07-20 * Author: krahets (krahets@163.com) */ #include "../utils/common.hpp" /* 零錢兌換:貪婪 */ int coinChangeGreedy(vector &coins, int amt) { // 假設 coins 串列有序 int i = coins.size() - 1; int count = 0; // 迴圈進行貪婪選擇,直到無剩餘金額 while (amt > 0) { // 找到小於且最接近剩餘金額的硬幣 while (i > 0 && coins[i] > amt) { i--; } // 選擇 coins[i] amt -= coins[i]; count++; } // 若未找到可行方案,則返回 -1 return amt == 0 ? count : -1; } /* Driver Code */ int main() { // 貪婪:能夠保證找到全域性最優解 vector coins = {1, 5, 10, 20, 50, 100}; int amt = 186; int res = coinChangeGreedy(coins, amt); cout << "\ncoins = "; printVector(coins); cout << "amt = " << amt << endl; cout << "湊到 " << amt << " 所需的最少硬幣數量為 " << res << endl; // 貪婪:無法保證找到全域性最優解 coins = {1, 20, 50}; amt = 60; res = coinChangeGreedy(coins, amt); cout << "\ncoins = "; printVector(coins); cout << "amt = " << amt << endl; cout << "湊到 " << amt << " 所需的最少硬幣數量為 " << res << endl; cout << "實際上需要的最少數量為 3 ,即 20 + 20 + 20" << endl; // 貪婪:無法保證找到全域性最優解 coins = {1, 49, 50}; amt = 98; res = coinChangeGreedy(coins, amt); cout << "\ncoins = "; printVector(coins); cout << "amt = " << amt << endl; cout << "湊到 " << amt << " 所需的最少硬幣數量為 " << res << endl; cout << "實際上需要的最少數量為 2 ,即 49 + 49" << endl; return 0; }