/* * File: preorder_traversal_iii_template.rs * Created Time: 2023-07-15 * Author: codingonion (coderonion@gmail.com) */ include!("../include/include.rs"); use std::{cell::RefCell, rc::Rc}; use tree_node::{vec_to_tree, TreeNode}; /* 判断当前状态是否为解 */ fn is_solution(state: &mut Vec>>) -> bool { return !state.is_empty() && state.get(state.len() - 1).unwrap().borrow().val == 7; } /* 记录解 */ fn record_solution(state: &mut Vec>>, res: &mut Vec>>>) { res.push(state.clone()); } /* 判断在当前状态下,该选择是否合法 */ fn is_valid(_: &mut Vec>>, choice: Rc>) -> bool { return choice.borrow().val != 3; } /* 更新状态 */ fn make_choice(state: &mut Vec>>, choice: Rc>) { state.push(choice); } /* 恢复状态 */ fn undo_choice(state: &mut Vec>>, _: Rc>) { state.remove(state.len() - 1); } /* 回溯算法:例题三 */ fn backtrack(state: &mut Vec>>, choices: &mut Vec>>, res: &mut Vec>>>) { // 检查是否为解 if is_solution(state) { // 记录解 record_solution(state, res); } // 遍历所有选择 for choice in choices { // 剪枝:检查选择是否合法 if is_valid(state, choice.clone()) { // 尝试:做出选择,更新状态 make_choice(state, choice.clone()); // 进行下一轮选择 backtrack(state, &mut vec![choice.borrow().left.clone().unwrap(), choice.borrow().right.clone().unwrap()], res); // 回退:撤销选择,恢复到之前的状态 undo_choice(state, choice.clone()); } } } /* Driver Code */ pub fn main() { let root = vec_to_tree([1, 7, 3, 4, 5, 6, 7].map(|x| Some(x)).to_vec()); println!("初始化二叉树"); print_util::print_tree(root.as_ref().unwrap()); // 回溯算法 let mut res = Vec::new(); backtrack(&mut Vec::new(), &mut vec![root.unwrap()], &mut res); println!("\n输出所有根节点到节点 7 的路径,要求路径中不包含值为 3 的节点"); for path in res { let mut vals = Vec::new(); for node in path { vals.push(node.borrow().val) } println!("{:?}", vals); } }