""" File: time_complexity.py Created Time: 2022-11-25 Author: krahets (krahets@163.com) """ def constant(n: int) -> int: """Constant complexity""" count = 0 size = 100000 for _ in range(size): count += 1 return count def linear(n: int) -> int: """Linear complexity""" count = 0 for _ in range(n): count += 1 return count def array_traversal(nums: list[int]) -> int: """Linear complexity (traversing an array)""" count = 0 # Loop count is proportional to the length of the array for num in nums: count += 1 return count def quadratic(n: int) -> int: """Quadratic complexity""" count = 0 # Loop count is squared in relation to the data size n for i in range(n): for j in range(n): count += 1 return count def bubble_sort(nums: list[int]) -> int: """Quadratic complexity (bubble sort)""" count = 0 # Counter # Outer loop: unsorted range is [0, i] for i in range(len(nums) - 1, 0, -1): # Inner loop: swap the largest element in the unsorted range [0, i] to the right end of the range for j in range(i): if nums[j] > nums[j + 1]: # Swap nums[j] and nums[j + 1] tmp: int = nums[j] nums[j] = nums[j + 1] nums[j + 1] = tmp count += 3 # Element swap includes 3 individual operations return count def exponential(n: int) -> int: """Exponential complexity (loop implementation)""" count = 0 base = 1 # Cells split into two every round, forming the sequence 1, 2, 4, 8, ..., 2^(n-1) for _ in range(n): for _ in range(base): count += 1 base *= 2 # count = 1 + 2 + 4 + 8 + .. + 2^(n-1) = 2^n - 1 return count def exp_recur(n: int) -> int: """Exponential complexity (recursive implementation)""" if n == 1: return 1 return exp_recur(n - 1) + exp_recur(n - 1) + 1 def logarithmic(n: int) -> int: """Logarithmic complexity (loop implementation)""" count = 0 while n > 1: n = n / 2 count += 1 return count def log_recur(n: int) -> int: """Logarithmic complexity (recursive implementation)""" if n <= 1: return 0 return log_recur(n / 2) + 1 def linear_log_recur(n: int) -> int: """Linear logarithmic complexity""" if n <= 1: return 1 count: int = linear_log_recur(n // 2) + linear_log_recur(n // 2) for _ in range(n): count += 1 return count def factorial_recur(n: int) -> int: """Factorial complexity (recursive implementation)""" if n == 0: return 1 count = 0 # From 1 split into n for _ in range(n): count += factorial_recur(n - 1) return count """Driver Code""" if __name__ == "__main__": # Can modify n to experience the trend of operation count changes under various complexities n = 8 print("Input data size n =", n) count: int = constant(n) print("Constant complexity operation count =", count) count: int = linear(n) print("Linear complexity operation count =", count) count: int = array_traversal([0] * n) print("Linear complexity (traversing an array) operation count =", count) count: int = quadratic(n) print("Quadratic complexity operation count =", count) nums = [i for i in range(n, 0, -1)] # [n, n-1, ..., 2, 1] count: int = bubble_sort(nums) print("Quadratic complexity (bubble sort) operation count =", count) count: int = exponential(n) print("Exponential complexity (loop implementation) operation count =", count) count: int = exp_recur(n) print("Exponential complexity (recursive implementation) operation count =", count) count: int = logarithmic(n) print("Logarithmic complexity (loop implementation) operation count =", count) count: int = log_recur(n) print("Logarithmic complexity (recursive implementation) operation count =", count) count: int = linear_log_recur(n) print("Linear logarithmic complexity (recursive implementation) operation count =", count) count: int = factorial_recur(n) print("Factorial complexity (recursive implementation) operation count =", count)