/* * File: leetcode_two_sum.rs * Created Time: 2023-01-14 * Author: xBLACICEx (xBLACKICEx@outlook.com), sjinzh (sjinzh@gmail.com) */ include!("../include/include.rs"); use std::collections::HashMap; struct SolutionBruteForce; struct SolutionHashMap; /* 方法一:暴力枚举 */ impl SolutionBruteForce { pub fn two_sum(nums: &Vec, target: i32) -> Vec { let size = nums.len(); // 两层循环,时间复杂度 O(n^2) for i in 0..size - 1 { for j in i + 1..size { if nums[i] + nums[j] == target { return vec![i as i32, j as i32]; } } } vec![] } } /* 方法二:辅助哈希表 */ impl SolutionHashMap { pub fn two_sum(nums: &Vec, target: i32) -> Vec { // 辅助哈希表,空间复杂度 O(n) let mut dic = HashMap::new(); // 单层循环,时间复杂度 O(n) for (i, num) in nums.iter().enumerate() { match dic.get(&(target - num)) { Some(v) => return vec![*v as i32, i as i32], None => dic.insert(num, i as i32) }; } vec![] } } /* Driver Code */ fn main() { // ======= Test Case ======= let nums = vec![ 2, 7, 11, 15 ]; let target = 9; // 方法一 let res = SolutionBruteForce::two_sum(&nums, target); print!("方法一 res = "); print_util::print_array(&res); // 方法二 let res = SolutionHashMap::two_sum(&nums, target); print!("\n方法二 res = "); print_util::print_array(&res); }