You can not select more than 25 topics
Topics must start with a letter or number, can include dashes ('-') and can be up to 35 characters long.
89 lines
2.6 KiB
89 lines
2.6 KiB
/*
|
|
* File: preorder_traversal_iii_template.rs
|
|
* Created Time: 2023-07-15
|
|
* Author: codingonion (coderonion@gmail.com)
|
|
*/
|
|
|
|
use hello_algo_rust::include::{print_util, vec_to_tree, TreeNode};
|
|
use std::{cell::RefCell, rc::Rc};
|
|
|
|
/* 判断当前状态是否为解 */
|
|
fn is_solution(state: &mut Vec<Rc<RefCell<TreeNode>>>) -> bool {
|
|
return !state.is_empty() && state.last().unwrap().borrow().val == 7;
|
|
}
|
|
|
|
/* 记录解 */
|
|
fn record_solution(
|
|
state: &mut Vec<Rc<RefCell<TreeNode>>>,
|
|
res: &mut Vec<Vec<Rc<RefCell<TreeNode>>>>,
|
|
) {
|
|
res.push(state.clone());
|
|
}
|
|
|
|
/* 判断在当前状态下,该选择是否合法 */
|
|
fn is_valid(_: &mut Vec<Rc<RefCell<TreeNode>>>, choice: Option<&Rc<RefCell<TreeNode>>>) -> bool {
|
|
return choice.is_some() && choice.unwrap().borrow().val != 3;
|
|
}
|
|
|
|
/* 更新状态 */
|
|
fn make_choice(state: &mut Vec<Rc<RefCell<TreeNode>>>, choice: Rc<RefCell<TreeNode>>) {
|
|
state.push(choice);
|
|
}
|
|
|
|
/* 恢复状态 */
|
|
fn undo_choice(state: &mut Vec<Rc<RefCell<TreeNode>>>, _: Rc<RefCell<TreeNode>>) {
|
|
state.pop();
|
|
}
|
|
|
|
/* 回溯算法:例题三 */
|
|
fn backtrack(
|
|
state: &mut Vec<Rc<RefCell<TreeNode>>>,
|
|
choices: &Vec<Option<&Rc<RefCell<TreeNode>>>>,
|
|
res: &mut Vec<Vec<Rc<RefCell<TreeNode>>>>,
|
|
) {
|
|
// 检查是否为解
|
|
if is_solution(state) {
|
|
// 记录解
|
|
record_solution(state, res);
|
|
}
|
|
// 遍历所有选择
|
|
for &choice in choices.iter() {
|
|
// 剪枝:检查选择是否合法
|
|
if is_valid(state, choice) {
|
|
// 尝试:做出选择,更新状态
|
|
make_choice(state, choice.unwrap().clone());
|
|
// 进行下一轮选择
|
|
backtrack(
|
|
state,
|
|
&vec![
|
|
choice.unwrap().borrow().left.as_ref(),
|
|
choice.unwrap().borrow().right.as_ref(),
|
|
],
|
|
res,
|
|
);
|
|
// 回退:撤销选择,恢复到之前的状态
|
|
undo_choice(state, choice.unwrap().clone());
|
|
}
|
|
}
|
|
}
|
|
|
|
/* Driver Code */
|
|
pub fn main() {
|
|
let root = vec_to_tree([1, 7, 3, 4, 5, 6, 7].map(|x| Some(x)).to_vec());
|
|
println!("初始化二叉树");
|
|
print_util::print_tree(root.as_ref().unwrap());
|
|
|
|
// 回溯算法
|
|
let mut res = Vec::new();
|
|
backtrack(&mut Vec::new(), &mut vec![root.as_ref()], &mut res);
|
|
|
|
println!("\n输出所有根节点到节点 7 的路径,要求路径中不包含值为 3 的节点");
|
|
for path in res {
|
|
let mut vals = Vec::new();
|
|
for node in path {
|
|
vals.push(node.borrow().val)
|
|
}
|
|
println!("{:?}", vals);
|
|
}
|
|
}
|