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hello-algo/codes/cpp/chapter_computational_compl.../time_complexity.cpp

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/**
* File: time_complexity.cpp
* Created Time: 2022-11-25
* Author: Krahets (krahets@163.com)
*/
#include "../include/include.hpp"
/* 常数阶 */
int constant(int n) {
int count = 0;
int size = 100000;
for (int i = 0; i < size; i++)
count++;
return count;
}
/* 线性阶 */
int linear(int n) {
int count = 0;
for (int i = 0; i < n; i++)
count++;
return count;
}
/* 线性阶(遍历数组) */
int arrayTraversal(vector<int>& nums) {
int count = 0;
// 循环次数与数组长度成正比
for (int num : nums) {
count++;
}
return count;
}
/* 平方阶 */
int quadratic(int n) {
int count = 0;
// 循环次数与数组长度成平方关系
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
count++;
}
}
return count;
}
/* 平方阶(冒泡排序) */
int bubbleSort(vector<int>& nums) {
int count = 0; // 计数器
// 外循环:待排序元素数量为 n-1, n-2, ..., 1
for (int i = nums.size() - 1; i > 0; i--) {
// 内循环:冒泡操作
for (int j = 0; j < i; j++) {
if (nums[j] > nums[j + 1]) {
// 交换 nums[j] 与 nums[j + 1]
int tmp = nums[j];
nums[j] = nums[j + 1];
nums[j + 1] = tmp;
count += 3; // 元素交换包含 3 个单元操作
}
}
}
return count;
}
/* 指数阶(循环实现) */
int exponential(int n) {
int count = 0, base = 1;
// cell 每轮一分为二,形成数列 1, 2, 4, 8, ..., 2^(n-1)
for (int i = 0; i < n; i++) {
for (int j = 0; j < base; j++) {
count++;
}
base *= 2;
}
// count = 1 + 2 + 4 + 8 + .. + 2^(n-1) = 2^n - 1
return count;
}
/* 指数阶(递归实现) */
int expRecur(int n) {
if (n == 1) return 1;
return expRecur(n - 1) + expRecur(n - 1) + 1;
}
/* 对数阶(循环实现) */
int logarithmic(float n) {
int count = 0;
while (n > 1) {
n = n / 2;
count++;
}
return count;
}
/* 对数阶(递归实现) */
int logRecur(float n) {
if (n <= 1) return 0;
return logRecur(n / 2) + 1;
}
/* 线性对数阶 */
int linearLogRecur(float n) {
if (n <= 1) return 1;
int count = linearLogRecur(n / 2) +
linearLogRecur(n / 2);
for (int i = 0; i < n; i++) {
count++;
}
return count;
}
/* 阶乘阶(递归实现) */
int factorialRecur(int n) {
if (n == 0) return 1;
int count = 0;
// 从 1 个分裂出 n 个
for (int i = 0; i < n; i++) {
count += factorialRecur(n - 1);
}
return count;
}
/* Driver Code */
int main() {
// 可以修改 n 运行,体会一下各种复杂度的操作数量变化趋势
int n = 8;
cout << "输入数据大小 n = " << n << endl;
int count = constant(n);
cout << "常数阶的计算操作数量 = " << count << endl;
count = linear(n);
cout << "线性阶的计算操作数量 = " << count << endl;
vector<int> arr(n);
count = arrayTraversal(arr);
cout << "线性阶(遍历数组)的计算操作数量 = " << count << endl;
count = quadratic(n);
cout << "平方阶的计算操作数量 = " << count << endl;
vector<int> nums(n);
for (int i = 0; i < n; i++)
nums[i] = n - i; // [n,n-1,...,2,1]
count = bubbleSort(nums);
cout << "平方阶(冒泡排序)的计算操作数量 = " << count << endl;
count = exponential(n);
cout << "指数阶(循环实现)的计算操作数量 = " << count << endl;
count = expRecur(n);
cout << "指数阶(递归实现)的计算操作数量 = " << count << endl;
count = logarithmic((float) n);
cout << "对数阶(循环实现)的计算操作数量 = " << count << endl;
count = logRecur((float) n);
cout << "对数阶(递归实现)的计算操作数量 = " << count << endl;
count = linearLogRecur((float) n);
cout << "线性对数阶(递归实现)的计算操作数量 = " << count << endl;
count = factorialRecur(n);
cout << "阶乘阶(递归实现)的计算操作数量 = " << count << endl;
return 0;
}