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/**
* File: subset_sum_i_native.kt
* Created Time: 2024-01-25
* Author: curtishd (1023632660@qq.com)
*/
package chapter_backtracking.subset_sum_i_naive
/* 回溯算法:子集和 I */
fun backtrack (
state : MutableList < Int > ,
target : Int ,
total : Int ,
choices : IntArray ,
res : MutableList < List < Int > ? >
) {
// 子集和等于 target 时,记录解
if ( total == target ) {
res . add ( ArrayList ( state ) )
return
}
// 遍历所有选择
for ( i in choices . indices ) {
// 剪枝:若子集和超过 target ,则跳过该选择
if ( total + choices [ i ] > target ) {
continue
}
// 尝试:做出选择,更新元素和 total
state . add ( choices [ i ] )
// 进行下一轮选择
backtrack ( state , target , total + choices [ i ] , choices , res )
// 回退:撤销选择,恢复到之前的状态
state . removeAt ( state . size - 1 )
}
}
/* 求解子集和 I( 包含重复子集) */
fun subsetSumINaive ( nums : IntArray , target : Int ) : List < List < Int > ? > {
val state : MutableList < Int > = ArrayList ( ) // 状态(子集)
val total = 0 // 子集和
val res : MutableList < List < Int > ? > = ArrayList ( ) // 结果列表(子集列表)
backtrack ( state , target , total , nums , res )
return res
}
/* Driver Code */
fun main ( ) {
val nums = intArrayOf ( 3 , 4 , 5 )
val target = 9
val res : List < List < Int > ? > = subsetSumINaive ( nums , target )
println ( " 输入数组 nums = ${nums.contentToString()} , target = $target " )
println ( " 所有和等于 $target 的子集 res = $res " )
println ( " 请注意,该方法输出的结果包含重复集合 " )
}