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hello-algo/codes/python/chapter_greedy/coin_change_greedy.py

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"""
File: coin_change_greedy.py
Created Time: 2023-07-18
Author: Krahets (krahets@163.com)
"""
def coin_change_greedy(coins: list[int], amt: int) -> int:
"""零钱兑换:贪心"""
# 假设 coins 列表有序
i = len(coins) - 1
count = 0
# 循环进行贪心选择,直到无剩余金额
while amt > 0:
# 找到小于且最接近剩余金额的硬币
while coins[i] > amt:
i -= 1
# 选择 coins[i]
amt -= coins[i]
count += 1
# 若未找到可行方案,则返回 -1
return count if amt == 0 else -1
"""Driver Code"""
if __name__ == "__main__":
# 贪心:能够保证找到全局最优解
coins = [1, 5, 10, 20, 50, 100]
amt = 186
res = coin_change_greedy(coins, amt)
print(f"\ncoins = {coins}, amt = {amt}")
print(f"凑到 {amt} 所需的最少硬币数量为 {res}")
# 贪心:无法保证找到全局最优解
coins = [1, 20, 50]
amt = 60
res = coin_change_greedy(coins, amt)
print(f"\ncoins = {coins}, amt = {amt}")
print(f"凑到 {amt} 所需的最少硬币数量为 {res}")
print(f"实际上需要的最少数量为 3 ,即 20 + 20 + 20")
# 贪心:无法保证找到全局最优解
coins = [1, 49, 50]
amt = 98
res = coin_change_greedy(coins, amt)
print(f"\ncoins = {coins}, amt = {amt}")
print(f"凑到 {amt} 所需的最少硬币数量为 {res}")
print(f"实际上需要的最少数量为 2 ,即 49 + 49")