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hello-algo/codes/javascript/chapter_backtracking/subset_sum_ii.js

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/**
* File: subset_sum_ii.js
* Created Time: 2023-07-30
* Author: yuan0221 (yl1452491917@gmail.com)
*/
/* 回溯算法:子集和 II */
function backtrack(state, target, choices, start, res) {
// 子集和等于 target 时,记录解
if (target === 0) {
res.push([...state]);
return;
}
// 遍历所有选择
// 剪枝二:从 start 开始遍历,避免生成重复子集
// 剪枝三:从 start 开始遍历,避免重复选择同一元素
for (let i = start; i < choices.length; i++) {
// 剪枝一:若子集和超过 target ,则直接结束循环
// 这是因为数组已排序,后边元素更大,子集和一定超过 target
if (target - choices[i] < 0) {
break;
}
// 剪枝四:如果该元素与左边元素相等,说明该搜索分支重复,直接跳过
if (i > start && choices[i] === choices[i - 1]) {
continue;
}
// 尝试:做出选择,更新 target, start
state.push(choices[i]);
// 进行下一轮选择
backtrack(state, target - choices[i], choices, i + 1, res);
// 回退:撤销选择,恢复到之前的状态
state.pop();
}
}
/* 求解子集和 II */
function subsetSumII(nums, target) {
const state = []; // 状态(子集)
nums.sort((a, b) => a - b); // 对 nums 进行排序
const start = 0; // 遍历起始点
const res = []; // 结果列表(子集列表)
backtrack(state, target, nums, start, res);
return res;
}
/* Driver Code */
const nums = [4, 4, 5];
const target = 9;
const res = subsetSumII(nums, target);
console.log(`输入数组 nums = ${JSON.stringify(nums)}, target = ${target}`);
console.log(`所有和等于 ${target} 的子集 res = ${JSON.stringify(res)}`);