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hello-algo/codes/python/chapter_searching/binary_search_insertion.py

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"""
File: binary_search_insertion.py
Created Time: 2023-08-04
Author: krahets (krahets@163.com)
"""
def binary_search_insertion_simple(nums: list[int], target: int) -> int:
"""二分查找插入点(无重复元素)"""
i, j = 0, len(nums) - 1 # 初始化双闭区间 [0, n-1]
while i <= j:
m = (i + j) // 2 # 计算中点索引 m
if nums[m] < target:
i = m + 1 # target 在区间 [m+1, j] 中
elif nums[m] > target:
j = m - 1 # target 在区间 [i, m-1] 中
else:
return m # 找到 target ,返回插入点 m
# 未找到 target ,返回插入点 i
return i
def binary_search_insertion(nums: list[int], target: int) -> int:
"""二分查找插入点(存在重复元素)"""
i, j = 0, len(nums) - 1 # 初始化双闭区间 [0, n-1]
while i <= j:
m = (i + j) // 2 # 计算中点索引 m
if nums[m] < target:
i = m + 1 # target 在区间 [m+1, j] 中
elif nums[m] > target:
j = m - 1 # target 在区间 [i, m-1] 中
else:
j = m - 1 # 首个小于 target 的元素在区间 [i, m-1] 中
# 返回插入点 i
return i
"""Driver Code"""
if __name__ == "__main__":
# 无重复元素的数组
nums = [1, 3, 6, 8, 12, 15, 23, 26, 31, 35]
print(f"\n数组 nums = {nums}")
# 二分查找插入点
for target in [6, 9]:
index = binary_search_insertion_simple(nums, target)
print(f"元素 {target} 的插入点的索引为 {index}")
# 包含重复元素的数组
nums = [1, 3, 6, 6, 6, 6, 6, 10, 12, 15]
print(f"\n数组 nums = {nums}")
# 二分查找插入点
for target in [2, 6, 20]:
index = binary_search_insertion(nums, target)
print(f"元素 {target} 的插入点的索引为 {index}")