Update Go code of subset sum.

pull/568/head
krahets 1 year ago
parent 3902ccbfc7
commit 7876e3e88c

@ -6,10 +6,8 @@ package chapter_backtracking
import "sort"
type subsetI struct{}
/* 回溯算法:子集和 I */
func (s subsetI) backtrack(start, target int, state, choices *[]int, res *[][]int) {
func backtrackSubsetSumI(start, target int, state, choices *[]int, res *[][]int) {
// 子集和等于 target 时,记录解
if target == 0 {
newState := append([]int{}, *state...)
@ -27,7 +25,7 @@ func (s subsetI) backtrack(start, target int, state, choices *[]int, res *[][]in
// 尝试:做出选择,更新 target, start
*state = append(*state, (*choices)[i])
// 进行下一轮选择
s.backtrack(i, target-(*choices)[i], state, choices, res)
backtrackSubsetSumI(i, target-(*choices)[i], state, choices, res)
// 回退:撤销选择,恢复到之前的状态
*state = (*state)[:len(*state)-1]
}
@ -35,11 +33,10 @@ func (s subsetI) backtrack(start, target int, state, choices *[]int, res *[][]in
/* 求解子集和 I */
func subsetSumI(nums []int, target int) [][]int {
s := subsetI{}
state := make([]int, 0) // 状态(子集)
sort.Ints(nums) // 对 nums 进行排序
start := 0 // 遍历起始点
res := make([][]int, 0) // 结果列表(子集列表)
s.backtrack(start, target, &state, &nums, &res)
backtrackSubsetSumI(start, target, &state, &nums, &res)
return res
}

@ -4,10 +4,8 @@
package chapter_backtracking
type subset struct{}
/* 回溯算法:子集和 I */
func (s subset) backtrack(total, target int, state, choices *[]int, res *[][]int) {
func backtrackSubsetSumINaive(total, target int, state, choices *[]int, res *[][]int) {
// 子集和等于 target 时,记录解
if target == total {
newState := append([]int{}, *state...)
@ -23,7 +21,7 @@ func (s subset) backtrack(total, target int, state, choices *[]int, res *[][]int
// 尝试:做出选择,更新元素和 total
*state = append(*state, (*choices)[i])
// 进行下一轮选择
s.backtrack(total+(*choices)[i], target, state, choices, res)
backtrackSubsetSumINaive(total+(*choices)[i], target, state, choices, res)
// 回退:撤销选择,恢复到之前的状态
*state = (*state)[:len(*state)-1]
}
@ -31,10 +29,9 @@ func (s subset) backtrack(total, target int, state, choices *[]int, res *[][]int
/* 求解子集和 I包含重复子集 */
func subsetSumINaive(nums []int, target int) [][]int {
s := subset{}
state := make([]int, 0) // 状态(子集)
total := 0 // 子集和
res := make([][]int, 0) // 结果列表(子集列表)
s.backtrack(total, target, &state, &nums, &res)
backtrackSubsetSumINaive(total, target, &state, &nums, &res)
return res
}

@ -6,10 +6,8 @@ package chapter_backtracking
import "sort"
type subsetII struct{}
/* 回溯算法:子集和 II */
func (s subsetII) backtrack(start, target int, state, choices *[]int, res *[][]int) {
func backtrackSubsetSumII(start, target int, state, choices *[]int, res *[][]int) {
// 子集和等于 target 时,记录解
if target == 0 {
newState := append([]int{}, *state...)
@ -32,7 +30,7 @@ func (s subsetII) backtrack(start, target int, state, choices *[]int, res *[][]i
// 尝试:做出选择,更新 target, start
*state = append(*state, (*choices)[i])
// 进行下一轮选择
s.backtrack(i+1, target-(*choices)[i], state, choices, res)
backtrackSubsetSumII(i+1, target-(*choices)[i], state, choices, res)
// 回退:撤销选择,恢复到之前的状态
*state = (*state)[:len(*state)-1]
}
@ -40,11 +38,10 @@ func (s subsetII) backtrack(start, target int, state, choices *[]int, res *[][]i
/* 求解子集和 II */
func subsetSumII(nums []int, target int) [][]int {
s := subsetII{}
state := make([]int, 0) // 状态(子集)
sort.Ints(nums) // 对 nums 进行排序
start := 0 // 遍历起始点
res := make([][]int, 0) // 结果列表(子集列表)
s.backtrack(start, target, &state, &nums, &res)
backtrackSubsetSumII(start, target, &state, &nums, &res)
return res
}

@ -39,7 +39,7 @@
=== "Go"
```go title="subset_sum_i_naive.go"
[class]{}-[func]{backtrackINaive}
[class]{}-[func]{backtrackSubsetSumINaive}
[class]{}-[func]{subsetSumINaive}
```
@ -152,7 +152,7 @@
=== "Go"
```go title="subset_sum_i.go"
[class]{}-[func]{backtrackI}
[class]{}-[func]{backtrackSubsetSumI}
[class]{}-[func]{subsetSumI}
```
@ -258,7 +258,7 @@
=== "Go"
```go title="subset_sum_ii.go"
[class]{}-[func]{backtrackII}
[class]{}-[func]{backtrackSubsetSumII}
[class]{}-[func]{subsetSumII}
```

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